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Isopropyl Acetate Lab Report

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3 mL of a 1:1 isopropyl acetate and toluene mixture along with a spin vane was added to a 5 mL conical vial using a calibrated Pasteur pipette. A Hickman still and heating block was assembled. The connector and lower portion of the Hickman still was wrapped with aluminum foil and the top of the still was loosely covered with foil. The thermometer was placed into the heating block and was moved into the Hickman still once the temperature of the heating block was near the listed temperature from the lab manual. The solution was stirred slowly while the hot plate was turned on. The temperature of the heating block was slowly (5°C/min) raised to 80-90°C. The connector between the flask and Hickman still was periodically tightened. Using a bent …show more content…

Fractional distillation was accomplished by using the knowledge of the boiling points of both isopropyl acetate and toluene and controlling the temperature of the apparatus so that one substance would boil but not the other. By doing this, isopropyl acetate was able to evaporate first because it has a lower boiling point than toluene. This is why Fraction 1 contained much more isopropyl acetate than it did toluene. By slowly raising the temperature of the apparatus to that of the boiling point of toluene, the distillate collected for Fraction 2 contained more toluene due to the majority of the isopropyl acetate having already evaporated. By using gas chromatography, the exact percentage of each substance in Fractions 1 and 2 were found. Fractional distillation was required to separate the liquids because isopropyl acetate and toluene have similar boiling points. It allows the liquid with the lower boiling point to evaporate and be collected and separated first. The liquid with the higher boiling point can then evaporate and be collected. The purpose of re-distillation is to removed most of the liquid with the lower boiling point and leaving a purer toluene in the vial. The working principle of gas chromatography is that once the solution is

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