Pt1420 Unit 6 Research Paper

25 Amount owed. If line 23d is smaller than the total of lines 22c and 24, enter amount owed

So our first problem will look like this; a (1) = 395 (1) + 5419 = 5814. The second year, a (2) = 395 (2) + 5419 = 6209. The third year; a (3) = 395 (3) + 5419 = 6604. The fourth year, a (4) = 395 (4) + 5419 = 6999. So now we have the sums of all four years. Which are: 5814, 6209, 6604, and 6999. To solve for Part B we will be using the formula given Sn = (n/2) (a1 + an). So, a1 = the first year sum, n= the fourth year and fourth year sum. This is how the problem looks written out with the correct numbers plugged in S4 = 4/2 (5814 + 6999). So to get this answer you will simply divide 2 into 4 and you get 2 or 4/2 = 2. Then you add the sums in the parenthesis or (5814 + 6999) = 12813. Finally you will multiply 2(12813) and get

Find the optimal solution using the graphical method (use graph paper). Identify the feasible region and the optimal solution on the graph. How much is the maximum profit? Consider the following linear programming problem: Minimize Z = 3 x + 5 y (cost, $) subject to 10 x + 2 y ≥ 20 6 x + 6 y ≥ 36 y ≥ 2 x, y ≥ 0 Find the optimal solution using the graphical method (use graph paper). Identify the feasible region and the optimal solution on the graph. How much is the minimum cost? 2. The Turner-Laberge Brokerage firm has just been instructed by one of its clients

This two-variable inequality problem uses the following basic information. Ozark Furniture Company uses 15 board feet of maple to make a classic maple rocker and 12 board feet of maple to make a modern maple rocker. Using y for classic rockers and x for modern rockers, the following inequality expresses the number of rockers of each type that could be made with 3,000 feet of maple or less: y -4/5x +200.

1) 6X + 15Y = 90 Multiply this equation by 2 to eliminate the X variable

11. Alan participated in a car race in which he had to cover a distance of at least 50 kilometers. He had fuel in his car for a maximum distance of 53 kilometers. If the distance is given by , where t is the time in hours, find the minimum and maximum number of hours for which Alan can drive his car.

a + b > 1, then k (b − a) (a + b− 1) > 0; c1 < c2, so c1- c2> 0. Therefore, p1 – p2 > 0 must be true, that is, equilibrium price of Dotcoms retailers is higher than that of MCRs retailers.

count++; sum += num; squareSum += num*num; if (num > max) max = num; if (num < min) min = num; } public int getCount() { // Return number of items that have been entered. return count; } public double getSum() { // Return the sum of all the items that have been entered. return sum; } public double getMean() { //

⎟ ⎜ D + E × rE ⎟ = ⎜ 40 + 300 × 0.05 ⎟ + ⎜ 40 + 300 × 0.10 ⎟

Country A; Cost ratio = 40:20 = 2:1, therefore, to determine the resource for X and Y this ration may be used

c. If the price of good X increases to $20, then the equation will change to 600=20X+40Y. So the new budget line is shown below:

mathematical problems using quadratic equations or by its forms, this led him to a great loss

It is clear that demand is higher than supply. Since demand is greater than supply, the demand constraints will be less than or equal to in the equation. Using solver in Excel, we can complete the spreadsheet. We find that the optimal solution is:

8. Eduardo spends his entire income on 12 sacks of acorns and 2 crates of butternuts. The price of acorns is 2 dollars per sack and his income is 34 dollars. He can just afford a commodity bundle with A sacks of acorns and B crates of butternuts which satisffies the budget equation: (b) 4A+ 10B = 68.

budget constraint that restricts the money to spend on the items. (24) { (26) give the limits