.A single crystal of aluminum is oriented for a tensile test such that its slip plan normal akes and angle of 28.1° with the tensile axis. There are three possible slip directions, hich make angles of i) 62.4°, ii)72.0°, and iii)81.1° with the tensile axis Vhich of these three slip direction is most favored? f plastic deformation begins at an applied tensile stress of 1.95MPA, determine the ritical resolved shear stress of aluminum.

.A single crystal of aluminum is oriented for a tensile test such that its slip plan normal akes and angle of 28.1° with the tensile axis. There are three possible slip directions, hich make angles of i) 62.4°, ii)72.0°, and iii)81.1° with the tensile axis Vhich of these three slip direction is most favored? f plastic deformation begins at an applied tensile stress of 1.95MPA, determine the ritical resolved shear stress of aluminum.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

1.) Consider a metal single crystal oriented such that the normal to the slip plane and the slip direction are at angles of 35.5° and 25.4°, respectively, with the tensile axis. If the critical resolved shear stress is 25 MPa, will an applied stress of 30 MPa cause the single crystal to yield? If not, what stress will be necessary? a) Yes it is enough to yield b) No it is not enough to yield, 31 Mpa will be enough c) No it is not enough to yield, 32 Mpa will be enough d) No it is not enough to yield, 33 Mpa will be enough e) No it is too much to yield, 24 Mpa or smaller should it be
Define the given terms related to mechanical properties of materials. 1. elastic material 2. Apparent Viscosity 3. Bend test 4. Bingham Plastic 5. Dilatant
A copper specimen of Young's Modulus 122 GPa is subjected to a tensile test in a laboratory and the following data are obtained. a) Initial length of the Specimen = 363 mm; b) Initial diameter of Specimen = 10 mm; c) Yield Stress = 128 N/mm2; d) Ultimate Stress = 212 N/mm2; e) Fracture Stress = 180 N/mm2; %3D g) % of Elongation = 44 %; h) % of Reduction in area = 38 %.
1) Draw (using a normal graph paper) a conventional stress-strain diagram for ANY metallic material (e.g. steel, aluminium, copper, brass, iron, tungsten). The diagram should be as accurate as possible using a suitable scale (e.g. 1cm: 10 N). 2) Calculate the Modulus of Elasticity, Modulus of Toughness and Modulus of Resilience for the material from the stress-strain diagram. Show your calculations in detail on a separate A4 piece of paper.
8) An FCC crystal is subjected to a tensile stress. This stress is applied in a direction that forms an angle of 28.1° with the slip plane of the crystal, and an angle of 62.4° with the slip direction respectively within the crystal, If a tensile stress of 0.80MPA is applied: a) Calculate the Resolved Shear Stress for the Crystal b) If the material's Critical Resolved Shear Stress is 0.73MP and a Safety Factor of 2 is applied to that stress, is your Resolved Shear Stress from "Part a" considered "safe" with respect to your Working Stress? (HINT: Safety Factors can be applied to Shear Stresses the same way they are applied to Normal Stresses)
A copper specimen of Young's Modulus 120 GPa is subjected to a tensile test in a laboratory and the following data are obtained. a) Initial length of the Specimen = 395 mm; b) Initial diameter of Specimen = 10 mm; c) Yield Stress = 133 N/mm2; d) Ultimate Stress = 228 N/mm2; e) Fracture Stress = 178 N/mm2; g) % of Elongation = 59 %; h) % of Reduction in area = 41 %. Determine the following i) The elongation of the specimen at load 101 kN (in mm) ii) Maximum load (in N) iii) Fracture load (in N) iv) Final Length (in mm) v) Final Diameter
Correctly complete the following phrase below: "When a structure is subjected to general loading in two dimensions, Tresca and the Von-Mises criteria are used to... determine the maximum shear stress." Don't Know calculate the principle planes." calculate the deformation in a structure." determine failure of materials that behave plastically."
In the First project: you have been asked to perform tensile testing for four different materialsand analyse the results and work on some NDT process selection:a. For the results shown in Table 1 of the tensile testing that you have performed, find thefollowing, if you know that the original length of specimen is 20.8 mm and the original diameteris 6.4 mm. Fill the calculated results in the summary table below (Table 1):1. Plot the engineering stress versus engineering strain for each material and L-D Diagram.2. Compute the modulus of elasticity, E in GPa.3. Determine the yield strength at a strain offset of 0.002.4. Determine the tensile strength in MPa.5. What is the approximate %El ductility, measured by percent elongation?6. Compute the modulus of resilience.7. Determine the fracture stress in MPa.8. Compute the final area (Af) in mm2.
1. What are the elastic modulus (E) and the Poisson's ratio () used to indicate? 2. Illustrate the differences between actual stress and engineered stress with strain, and also describe their underlying physical concepts. 3. If the engineering strain is 2% for a specific state of uniaxial stress, what is the real strain? Please solve for all in full detail and step by step
draft is 10.nm Q2: The following stress and strain values were measured in the plastic region during a tensile test carried out on a new experimental metal: (1) true stress = 43.608 lb/in2 and true strain = 0.27. (2) true stress = 52.048 lb/in2 and true strain = 0.85. Based on these data points, determine the (strength coefficient and strain- hardening exponent. Find the engineering stress and strain at the second noint
7) Stress-strain plot for a metal is given below. Determine the following: a) Modulus of elasticity. b) Yield strength by 0.2% off-set method. c) Tensile and fracture strengths. d) Maximum load that can be sustained by a cylindrical specimen having an original diameter of 15.3 mm. e) If a specimen having an original length of 320 mm and elongation is measured as 2.56 mm, determine the applied stress. 450 400 350 300 250 200 150 100 50 0.002 0.004 0.006 0.008 0.01 0.012 0.014 0.016 Strain Stress (MPa)
The following data are obtained from a tensile test of an aluminium specimen. - The load at the yield point is 147 kN - Length of the specimen is 29 mm. - The yield strength is 79 kN/mm2. - The percentage of elongation is 49 %. Determine the following (i) Diameter of the specimen, ii) Final length of the specimen, iii) Stress under an elastic load of 15 kN, iv) Young's Modulus if the elongation is 2.8 mm at 15 kN (1.5 Marks) and (v) Final diameter if the percentage of reduction in area is 20 %. (1.5 Initial Cross-sectional Area (in mm2) The Diameter of the Specimen (in mm) Final Length of the Specimen (in mm) Stress at the elastic load (in N/mm2) Young's Modulus of the Specimen (in N/mm2) Final Area of the Specimen at Fracture (in mm) Final Diameter of the Specimen after Fracture (in mm)