0.86 0.85 0.84 0.78 0.75 0.76 0.82 0.88 0.94 0.74 0.71 0.84 0.99 0.99 0.72 0.87 The following data represent the weights (in grams) of a random sample of 50 candies. 0.82 0.72 0.94 0.87 0.95 0.82 0.77 0.77 0.82 0.84 0.81 0.92 0.78 0.81 0.93 0.86 0.85 0.82 0.96 0.81 0.84 0.76 0.85 0.84 0.88 0.72 0.91 0.72 0.84 0.82 0.87 0.92 0.91 0.84 a) Determine the sample standard deviation weight. =- gram Round to two decimal places as needed.)
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- The cash register receipts each day last week at a coffee shop were $1,845. $1,520. $1,438, $1,682, $1,850, $2,721, $2,539. Find the (a) mean, (b) median, and (c) mode.The accompanying data represent the weights (in grams) of a random sample of 48 M&M plain candies. Complete parts (a) through (f). Click the icon to view the weights of the M&M plain candies. M&M Candy Weights 0.87 0.88 0.88 0.86 0.87 0.90 0.81 0.84 0.91 0.94 0.92 0.89 0.93 0.86 0.84 0.83 0.83 0.91 0.82 0.84 0.89 0.93 0.84 0.90 0.91 0.95 0.86 0.85 0.79 0.91 0.88 0.86 0.88 0.91 0.86 0.90 0.93 0.87 0.88 0.84 0.88 0.88 0.87 0.86 0.84 0.82 0.85 0.87Weights of 10 red and 36 brown randomly chosen M&M plain candies are listed below. Red: 0.9130. 8820. 8740. 9120. 8910. 8970. 9520. 8770. 9130. 9240 Brown: 0.860 .8570 .9040 .9140 .8970 .9150 .8711 .0010 .8890 .9180 .9850 .9880 .8670 .9090 .930 .8610 .8750 .866 0.9280 .9550 .9050 .9660 .920 .9090 .9360 .9310 .90 .8770 .8580 .9120 .920 .9020 .9210 .9230 .9860 .898 4. A 95% confidence interval for the mean weight of brown M{\&}M plain candies isblank<μ< blank
- Weights of 10 red and 36 brown randomly chosen M&M plain candies are listed below. Red: 0.9130. 8820. 8740. 9120. 8910. 8970. 9520. 8770. 9130. 9240 Brown: 0.860 .8570 .9040 .9140 .8970 .9150 .8711 .0010 .8890 .9180 .9850 .9880 .8670 .9090 .930 .8610 .8750 .866 0.9280 .9550 .9050 .9660 .920 .9090 .9360 .9310 .90 .8770 .8580 .9120 .920 .9020 .9210 .9230 .9860 .898 1. To construct a 95% confidence interval for the mean weight of red M{\&}M plain candies, you have to useA. The t distribution with 10 degrees of freedomB. The t distribution with 9 degrees of freedomC. The normal distributionD. The t distribution with 11 degrees of freedomE. None of the above2. A 95% confidence interval for the mean weight of red M&M plain candies is blank<μ<blank3. To construct a 95% confidence interval for the mean weight of brown M{\&}M plain candies, you have to useA. The t distribution with 35 degrees of freedomB. The normal distributionC. The t distribution with 37…sed on data from WHO, a representative sample of 11-year-old males could consist of the following 15 values. 15.7, 16.0, 13.9, 15.3, 18.6, 14.8, 17.7, 16.6, 18.1, 19.2, 16.3, 17.3, 16.9, 25.6, 20.4 using the data calculate the 85th perThe following data shows the amount of soft drinks of 50 bottles. 2.109 2.086 2.066 2.075 2.065 2.057 2.052 2.044 2.036 2.038 2.031 2.029 2.025 2.029 2.023 2.020 2.015 2.014 2.013 2.014 2.012 2.012 2.012 2.01 2.005 2.003 1.999 1.996 1.997 1.992 1.994 1.986 1.984 1.981 1.973 1.975 1.971 1.969 1.966 1.967 1.963 1.957 1.951 1.951 1.947 1.941 1.941 1.938 1.908 1.894 a. Construct a distribution frequency table and an ogive. Does the amount of soft drink filled in the bottles concentrate around the specific values?
- Use the data in the table to the right to answer the following questions. Weights (g) of a Sample Bag of Candy Red Blue Brown Green Yellow 0.964 0.793 0.784 0.814 0.966 0.708 0.991 0.845 0.771 0.733 Find the sample proportion of candy that are red. 0.747 0.886 0.782 0.793 0.882 0.766 0.766 0.919 0.923 0.975 0.849 The proportion of red candy = 0.958 0.762 0.712 0.938 0.752 0.915 (Type an integer or decimal rounded to three decimal places as needed.) 0.822 0.844 0.733 0.781 0.976 0.955 0.827 0.939 0.818 0.805 0.812 0.725 0.966 0.815 0.854 0.915Use the data in the table to the right to answer the following questions. Weights (g) of a Sample Bag of Candy Red Blue Brown Green Yellow 0.708 0.771 0.991 0.966 0.845 0.964 0.784 0.793 0.814 0.733 Find the sample proportion of candy that are red. 0.747 0.923 0.919 0.975 0.782 0.793 0.882 0.886 0.766 0.849 The proportion of red candy = 233 0.958 0.766 0.915 0.938 0.752 0.712 (Type an integer or decimal rounded to three decimal places as needed.) 0.733 0.822 0.955 0.762 0.844 0.781 0.827 0.939 Use that result to construct a 95% confidence interval estimate of the population percentage of candy that are red. 0.818 0.976 0.805 0.812 0.725 0.966 0.815 0.854 0.915 %Use the data in the table to the right to answer the following questions. Weights (g) of a Sample Bag of Candy Red Blue Brown Green Yellow 0.982 0.747 0.871 0.729 0.809 0.972 0.994 0.749 0.764 0.806 Find the sample proportion of candy that are red. 0.833 0.834 0.835 0.969 0.815 0.874 0.816 0.835 0.798 0.849 0.721 0.822 The proportion of red candy = 25 (Type an integer or decimal rounded to three decimal places as needed.) 0.751 0.713 0.918 0.994 0.778 0.831 0.778 0.751 0.804 0.829 0.883 0.813 Use that result to construct a 95% confidence interval estimate of the population 0.996 0.728 0.938 percentage of candy that are red. 0.735 0.926 0.799 %As of July 8, 2020, the national average price for a gallon of regular unleaded gasoline was $2.18. The prices for a sample of n = 10 gas stations in the state of Illinois are provided. $2.365 $2.417 $2.437 $2.421 $2.396 $2.444 $2.422 $2.374 $2.422 $2.447 It is of interest to use this sample to compare the average gas price in Illinois to the national average. Use the provided randomization distribution (based on 1,000 samples) to estimate the p-value for this sample. 1.98 2.04 2.10 2.16 2.22 2.28 2.34 2.40 null = 2.18 Each symbol represents up to 2 observations. iThe list below shows the ages (in years) of 8 people riding in a van to a math competition. Calculate the mean age of the people in the van. Round your answer to the nearest tenth of a year. ages 13 10 9. 14 12 15 15 44 Mean years (Please round your answer to the %3D nearest tenth.) Median years (Please enter an exact answer.) %3DThe data to the right represent the weights (in grams) of a random sample of 50 candies. 0.87 0.85 0.86 0.82 0.84 0.86 0.95 0.83 0.92 0.82 0.82 0.88 0.79 0.89 0.85 0.81 0.72 0.83 0.74 0.82 0.95 0.78 0.78 0.92 0.85 0.93 0.85 0 85 0.82 0.75 0.97 0.84 0.79 0.75 0.84 0.78 0.82 0.86 0.89 0.76 Complete parts (a) through (f). 0.73 0.95 0.72 0.72 0.81 0.82 0.89 0.93 0.91 0.83 (a) Determine the sample standard deviation weight. gram(s) (Do not round until the final answer. Then round to three decimal places as needed.) (b) On the basis of the histogram to the right, comment on the appropriateness of using the Empirical Rule to make any general statements about the weights of the candies. 20- O A. The histogram is approximately bell-shaped so the Empirical Rule can be used. O B. The histogram is approximately bell-shaped so the Empirical Rule cannot be used. O C. The histogram is not approximately bell-shaped so the Empirical Rule can be used. 0.7 Weights (g) O D. The histogram is not…SEE MORE QUESTIONSRecommended textbooks for youGlencoe Algebra 1, Student Edition, 9780079039897…AlgebraISBN:9780079039897Author:CarterPublisher:McGraw HillGlencoe Algebra 1, Student Edition, 9780079039897…AlgebraISBN:9780079039897Author:CarterPublisher:McGraw Hill