1) #include #include int power(int, int); int main(void) { int x, n; printf("Enter a number and powerto raise it to: "); scanf_s("%d %d", &x, &n); printf("Result: %d\n", power(n, x)); return 0; } int power(int x, int n) { int m; if (n == 0) return 1; if (n % 2 == 0) { m = power(x, n / 2); return m * m; } else return x * power(x, n - 1); } 2) #include int hcf(int n1, int n2); int main() { int n1, n2; printf("Enter any two positive integers: "); scanf("%d %d", &n1, &n2); printf("Greatest Common Divisor of %d and %d is %d.", n1, n2, hcf(n1,n2)); return 0; } int hcf(int n1, int n2) { if (n2 != 0) return hcf(n2, n1%n2); else return n1; } 3) #include int main() { int array[], minimum, size, c, location = 1; printf("Enter the number of elements in array\n"); scanf("%d",&size); printf("Enter %d integers\n", size); for ( c = 0 ; c < size ; c++ ) scanf("%d", &array[c]); minimum = array[0]; for ( c = 1 ; c < size ; c++ ) { if ( array[c] < minimum ) { minimum = array[c]; location = c+1; } } printf("Minimum element is %d", minimum); return 0; } Write the int main(void) function as a driver program and call the above three functions result with sample Input/Output.
1) #include #include int power(int, int); int main(void) { int x, n; printf("Enter a number and powerto raise it to: "); scanf_s("%d %d", &x, &n); printf("Result: %d\n", power(n, x)); return 0; } int power(int x, int n) { int m; if (n == 0) return 1; if (n % 2 == 0) { m = power(x, n / 2); return m * m; } else return x * power(x, n - 1); } 2) #include int hcf(int n1, int n2); int main() { int n1, n2; printf("Enter any two positive integers: "); scanf("%d %d", &n1, &n2); printf("Greatest Common Divisor of %d and %d is %d.", n1, n2, hcf(n1,n2)); return 0; } int hcf(int n1, int n2) { if (n2 != 0) return hcf(n2, n1%n2); else return n1; } 3) #include int main() { int array[], minimum, size, c, location = 1; printf("Enter the number of elements in array\n"); scanf("%d",&size); printf("Enter %d integers\n", size); for ( c = 0 ; c < size ; c++ ) scanf("%d", &array[c]); minimum = array[0]; for ( c = 1 ; c < size ; c++ ) { if ( array[c] < minimum ) { minimum = array[c]; location = c+1; } } printf("Minimum element is %d", minimum); return 0; } Write the int main(void) function as a driver program and call the above three functions result with sample Input/Output.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
100%
1)
#include
#include
int power(int, int);
int main(void)
{
int x, n;
printf("Enter a number and powerto raise it to: ");
scanf_s("%d %d", &x, &n);
printf("Result: %d\n", power(n, x));
return 0;
}
int power(int x, int n)
{
int m;
if (n == 0) return 1;
if (n % 2 == 0) {
m = power(x, n / 2);
return m * m;
}
else return x * power(x, n - 1);
}
2)
#include
int hcf(int n1, int n2);
int main()
{
int n1, n2;
printf("Enter any two positive integers: ");
scanf("%d %d", &n1, &n2);
printf("Greatest Common Divisor of %d and %d is %d.", n1, n2, hcf(n1,n2));
return 0;
}
int hcf(int n1, int n2)
{
if (n2 != 0)
return hcf(n2, n1%n2);
else
return n1;
}
3)
#include
int main()
{
int array[], minimum, size, c, location = 1;
printf("Enter the number of elements in array\n");
scanf("%d",&size);
printf("Enter %d integers\n", size);
for ( c = 0 ; c < size ; c++ )
scanf("%d", &array[c]);
minimum = array[0];
for ( c = 1 ; c < size ; c++ )
{
if ( array[c] < minimum )
{
minimum = array[c];
location = c+1;
}
}
printf("Minimum element is %d", minimum);
return 0;
}
Write the
int main(void)
function as a driver program and call the above
three
functions result with
sample Input/Output.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 4 steps