(1 point) Approximate both In(0.98) and In(1.02) using First note that In(0.98) and In(1.02) both In(1). Let f(x) = ln(x). Then, f'(x) = 1/x Let xp = 1. Then f'(1) = | L(x), the line tangent to In(x) at xo = 1 is: L(x)= Note that the tangent line is a good approximation to t values below: In(0.98) In(1.02) ≈ Hint: If you put the exact values into your calculator yo
(1 point) Approximate both In(0.98) and In(1.02) using First note that In(0.98) and In(1.02) both In(1). Let f(x) = ln(x). Then, f'(x) = 1/x Let xp = 1. Then f'(1) = | L(x), the line tangent to In(x) at xo = 1 is: L(x)= Note that the tangent line is a good approximation to t values below: In(0.98) In(1.02) ≈ Hint: If you put the exact values into your calculator yo
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter6: Applications Of The Derivative
Section6.CR: Chapter 6 Review
Problem 20CR
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