1. A second fault exists 100 meters elevation below the one depicted below. Draw its map expression ( the equivalent of the red line)2. Draw in the map expression of the horizontal bed as it is cut by these two faults. Relationships between structure contours for a planar surface, a topographic surface and the mapexpression on the map of the planar surface.You saw in the above exercise how one can map the line created by the intersection of two surfaces.You basically connect the points created by the intersection of the contours of equal elevation of thetwo respective surfaces to create what the map pattern should be. You of course can do the opposite,connect the points where the line representing the map expression crosses the same contour toestimate the structure contour line at the elevation of the contour.Exercise 2: Use the map diagram below to complete the following. The thicker dotted line representstopographic contour lines, the thinner continuous line represent contours on a fault surface, and the red(grey in b&w) represents the surface/map expression of the fault surface.a) A second fault surface exists exactly 100 meters elevation below the one depicted below. Draw itsmap expression (the equivalent of the red line for the second fault).b) A horizontal bed is cut by these faults. In the footwall of the lowest fault it is at an elevation of 350 m.In the footwall of the higher fault it is at an elevation of 290 m, and in the hanging wall of the higherfault it is at 210 m elevation. Draw in the map expression of the horizontal bed as it is cut by these twofaults. You will need to interpolate between the given contour lines. Remember that the footwall is theblock beneath a dipping fault, and the hanging wall is that above.100 m500 m400 m -400 m300 m200 m400 m100 m,500 m500 m300 m*300 m200 m200 m10b m100 mgeologic contactnd contouring point x,y,z data.e computer programs conduct this type of analysis readily, it is useful to hand contour data alscases it can be argued that an experienced geologist might produce a better contour map of

Answered: 1. A second fault exists 100 meters…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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1. A second fault exists 100 meters elevation below the one depicted below. Draw its map expression ( the equivalent of the red line) 2. Draw in the map expression of the horizontal bed as it is cut by these two faults.

Relationships between structure contours for a planar surface, a topographic surface and the map
expression on the map of the planar surface.
You saw in the above exercise how one can map the line created by the intersection of two surfaces.
You basically connect the points created by the intersection of the contours of equal elevation of the
two respective surfaces to create what the map pattern should be. You of course can do the opposite,
connect the points where the line representing the map expression crosses the same contour to
estimate the structure contour line at the elevation of the contour.
Exercise 2: Use the map diagram below to complete the following. The thicker dotted line represents
topographic contour lines, the thinner continuous line represent contours on a fault surface, and the red
(grey in b&w) represents the surface/map expression of the fault surface.
a) A second fault surface exists exactly 100 meters elevation below the one depicted below. Draw its
map expression (the equivalent of the red line for the second fault).
b) A horizontal bed is cut by these faults. In the footwall of the lowest fault it is at an elevation of 350 m.
In the footwall of the higher fault it is at an elevation of 290 m, and in the hanging wall of the higher
fault it is at 210 m elevation. Draw in the map expression of the horizontal bed as it is cut by these two
faults. You will need to interpolate between the given contour lines. Remember that the footwall is the
block beneath a dipping fault, and the hanging wall is that above.
100 m
500 m
400 m -
400 m
300 m
200 m
400 m
100 m,
500 m
500 m
300 m*
300 m
200 m
200 m
10b m
100 m
geologic contact
nd contouring point x,y,z data.
e computer programs conduct this type of analysis readily, it is useful to hand contour data als
cases it can be argued that an experienced geologist might produce a better contour map of

Expert Solution

Step 1

The horizontal bed has been disrupted by the fault. Its trace has been found in 350 m at the footwall for higher fault and for the lower fault at an elevation of 290 m. we can find the trace of the bed at the hanging wall for the higher fault at 210 m. so, the net slip due to the upper fault is 140 m.

As the fault are parallel, we can say that the displacement is 140 m due to the lower fault.

As per the V rule of topography, a horizontal bed will follow the topographic contour line. Using the V rule, it is clear that the fault is dipping towards the South-west. so, the southern block is a hanging wall block and the northern block is a foot wall. The beds at the foot wall will be at the higher elevation whereas they will be at 140 m below in the foot wall block. The map has been completed sing this notations and all the color coded index has been provided with map also.

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