1. Consider the temperature-composition diagram shown below for benzene (bp = 80°C) and toluene (bp =110°C). For a 80/20 mixture of toluene to benzene answer the following:Temperature (°C)110895903801T110.20.40.6Mole Fraction of Toluenea) At what temperature will the mixture begin to boil (use just approximate values)?b) When the mixture begins to boil, what is the mol % benzene in the vapor?c) What is the boiling point of the liquid formed by condensation of the vapor?10.811010095908580

We are given the temperature-composition diagram for the composition of a mixture of benzene and…

1. Consider the temperature-composition 110°C). For a 80/20 mixture of toluene to benzene answer the following: Temperature (°C) 110 100 95 90 85 80 0.2 diagram shown below for benzene (bp = 80°C) and toluene (bp = 0.4 0.6 Mole Fraction of Toluene 0.8 1 a) At what temperature will the mixture begin to boil (use just approximate values)? b) When the mixture begins to boil, what is the mol % benzene in the vapor? c) What is the boiling point of the liquid formed by condensation of the vapor? 110 100 95 90 85 80

1. Consider the temperature-composition 110°C). For a 80/20 mixture of toluene to benzene answer the following: Temperature (°C) 110 100 95 90 85 80 0.2 diagram shown below for benzene (bp = 80°C) and toluene (bp = 0.4 0.6 Mole Fraction of Toluene 0.8 1 a) At what temperature will the mixture begin to boil (use just approximate values)? b) When the mixture begins to boil, what is the mol % benzene in the vapor? c) What is the boiling point of the liquid formed by condensation of the vapor? 110 100 95 90 85 80

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter12: Solutions

Section: Chapter Questions

Problem 12.98QE

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