1. If f(x) = x² – 2, compute the following: a) f(1) = b) f(1+h) = c) f(1+ h) – f(1) h Bring your answer to the simplest possible form.

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter3: The Derivative
Section3.1: Limits
Problem 77E
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Question 1c
1. If f(r) = x² – 2, compute the following:
a)
f(1) =
b)
f(1+h) =
c)
f(1+h) – f(1)
h
Bring your answer to the simplest possible form.
2. a) Now, for the same function as above f(z) = x² – 2, compute the limit
f(1+h) – f(1)
lim
h
Note: From our class discussions, recall that this limit represents in fact the value of
the derivative of the given function at 1, i.e.
f(1+h) -- f(1}
f'(1) = lim
h-0
h
b) In general, what is the derivative
-(x² – 2) =
dz
Check your answer from a) by means of classic rules of differentiation, in other words
compute the derivative 4 (22 – 2) at z = 1.
2
c) Finally, draw a large and clear sketch of the graph of f(x) = x² – 2 and illustrate
the tangent line at P(1, –1). Give the slope of the tangent line at P and compute
the equation of this tangent line.
Note: You may want to recall that, in general, the slope of the tangent line at x = a is
in fact given by the derivative of f at x = a or the instantaneous rate of change of f at
x = a. As discussed in class, the instantaneous rate of change is viewed as the limit as
I + a of rates of change Le-1@ Put differently, given the curve y = f(x), the slope
of the tangent line at P(a, f(a) can be interpreted as a limit of slopes of secant lines
PQ as Q comes closer and closer to P along the curve, i.e.
f(x) – f(a)
lim
I- a
This limit can also be written as the limit of a difference quotient as
f(a+h) – f(a).
lim
h
As such, in our case, since a=1, we deduce that f'(1), which comes from
f'(1) = lim
f(x) – f(1)
= lim
f(1+h) – f(1)
I - 1
h
gives us nothing but the slope of the tangent line at P(1, –1). You may want to note that
we have already computed these things in part a), and that you may just use the answer of
f'(1) to give the slope of the tangent line at P(1, –1).
Transcribed Image Text:1. If f(r) = x² – 2, compute the following: a) f(1) = b) f(1+h) = c) f(1+h) – f(1) h Bring your answer to the simplest possible form. 2. a) Now, for the same function as above f(z) = x² – 2, compute the limit f(1+h) – f(1) lim h Note: From our class discussions, recall that this limit represents in fact the value of the derivative of the given function at 1, i.e. f(1+h) -- f(1} f'(1) = lim h-0 h b) In general, what is the derivative -(x² – 2) = dz Check your answer from a) by means of classic rules of differentiation, in other words compute the derivative 4 (22 – 2) at z = 1. 2 c) Finally, draw a large and clear sketch of the graph of f(x) = x² – 2 and illustrate the tangent line at P(1, –1). Give the slope of the tangent line at P and compute the equation of this tangent line. Note: You may want to recall that, in general, the slope of the tangent line at x = a is in fact given by the derivative of f at x = a or the instantaneous rate of change of f at x = a. As discussed in class, the instantaneous rate of change is viewed as the limit as I + a of rates of change Le-1@ Put differently, given the curve y = f(x), the slope of the tangent line at P(a, f(a) can be interpreted as a limit of slopes of secant lines PQ as Q comes closer and closer to P along the curve, i.e. f(x) – f(a) lim I- a This limit can also be written as the limit of a difference quotient as f(a+h) – f(a). lim h As such, in our case, since a=1, we deduce that f'(1), which comes from f'(1) = lim f(x) – f(1) = lim f(1+h) – f(1) I - 1 h gives us nothing but the slope of the tangent line at P(1, –1). You may want to note that we have already computed these things in part a), and that you may just use the answer of f'(1) to give the slope of the tangent line at P(1, –1).
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