1. It is estimated that the BOD of raw sewage received at a treatment plant serving a population of 20,000 will be 300 mg/L. It is es1mated that the per capita BOD loading is 0.17 lbm/day. 30% of influent BOD is removed by settling. One single-stage high-rate trickling filter is to be used to reduce the plant effluent to 50 mg/L. Recirculation is from the filter effluent to the primary settling influent. Ten States' Standards is in effect, which specifies 100 gpcd in the absence of other information. (1) What is the design flow rate? In MGD (2) Assuming a design flow rate of 1.35 MGD, what is the total organic load on the filter? In lbm/day (3) Assuming an incoming volume of 1.35 MGD and an organic loading of 60 lbm/1000^3.d, what flow should be recirculated? In MGD (4) What is the overall plant efficiency? In precent%

1. It is estimated that the BOD of raw sewage received at a treatment plant serving a population of 20,000 will be 300 mg/L. It is es1mated that the per capita BOD loading is 0.17 lbm/day. 30% of influent BOD is removed by settling. One single-stage high-rate trickling filter is to be used to reduce the plant effluent to 50 mg/L. Recirculation is from the filter effluent to the primary settling influent. Ten States' Standards is in effect, which specifies 100 gpcd in the absence of other information. (1) What is the design flow rate? In MGD (2) Assuming a design flow rate of 1.35 MGD, what is the total organic load on the filter? In lbm/day (3) Assuming an incoming volume of 1.35 MGD and an organic loading of 60 lbm/1000^3.d, what flow should be recirculated? In MGD (4) What is the overall plant efficiency? In precent%

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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1. It is estimated that the BOD of raw sewage received at a treatment plant serving a population of 20,000 will be 300 mg/L. It is es1mated that the per capita BOD loading is 0.17 lbm/day. 30% of influent BOD is removed by settling. One single-stage high-rate trickling filter is to be used to reduce the plant effluent to 50 mg/L. Recirculation is from the filter effluent to the primary settling influent. Ten States' Standards is in effect, which specifies 100 gpcd in the absence of other information. (1) What is the design flow rate? In MGD (2) Assuming a design flow rate of 1.35 MGD, what is the total organic load on the filter? In Ibm/day (3) Assuming an incoming volume of 1.35 MGD and an organic loading of 60 lbm/1000^3 d, what flow should be recirculated? In MGD (4) What is the overall plant efficiency? In precent %
1. It is estimated that the BOD of raw sewage received at a treatment plant serving a population of 20,000 will be 300 mg/L. It is es1mated that the per capita BOD loading is 0.17 lbm/day. 30% of influent BOD is removed by settling. One single-stage high-rate trickling filter is to be used to reduce the plant effluent to 50 mg/L. Recirculation is from the filter effluent to the primary settling influent. Ten States' Standards is in effect, which specifies 100 gpcd in the absence of other information. Styles (1) What is the design flow rate? In MGD (A) 0.9 MGD (B) 1.1 MGD (C) 1.4 MGD (D) 2.0 MGD (2) Assuming a design flow rate of 1.35 MGD, what is the total organic load on the filter? In Ibm/day (A) 1700 lbm/day (B) 2100 lbm/day (C) 2400 lbm/day (D) 3400 lbm/day (3) Assuming an incoming volume of 1.35 MGD and an organic loading of 60 lbm/1000^3.d, what flow should be recirculated? In MGD (A) 0.6 MGD (B) 1.1 MGD (C) 1.2 MGD (D) 2.2 MGD (4) What is the overall plant efficiency? In…
The BOD3 of a wastewater is determined to be 270 mg/L at 20 o The rate constant (k) value is known to be 0.34 per day as first order. (C: 12 g/mol, H: 1 g/mol, O: 16 g/mol) Note: Reaction should be stoichiometricly balanced CH2O + O2 ------> CO2 + H2O (a) What would be BOD5 value if tests were run at 20 oC? (b) What is the concentration of formaldehyde (CH2O) in wastewater?
A completely mixed activated sludge plant treats wastewater at a rate of 2,565 m³/d. The influent BOD is 280 mg/L, and the MLVSS in the aeration tank is 2,500 mg/L. The F/M ratio for the aeration tank is 0.35 kg BOD/kg MLVSS.d. Assuming 30% of BOD is removed in the primary tank, determine the organic loading rate in kg BOD/m³.d and the volume of the aeration tank in m³.
The PEF, Inc. firm desires to utilize a complete-mix activated-sludge system with recycle to treat their municipal wastewater after primary sedimentation. The design parameters are: Flow rate=0.92m³/s Influent Soluble BOD5 = 292mg/L MLVSS=2,500mg/L Mean cell residence time = 7.24 d For any missing parameters, use typical values of growth constants for domestic wastewater (provided in your text, page 494). Assume that the solids lost in the secondary clarifier effluent are minor and can be neglected. Assuming a BODs (S) concentration of 24 mg/L, the detention time (residence time or theta) in the activated sludge system is most nearly: O 28 hours O 6.5 hours O 168 hours O 53 hours
A complete mix activated sludge process is to be used for biological treatment. This plant receives 10,000 m³ of wastewater per day with BOD loading of 250 mg/L. The primary treatment efficiency is 25%. Assume the followings: ● ● -4- Plant effluent BOD5 = 12 mg/L Biomass yield = 0.54 kg biomass / kg BOD Endogenous decay rate=0.05 day-¹ Solids Retention Time = 8 days MLVSS concentration in the aeration tank = 2,700 mg/L Waste and recycle solids concentration = 12,000 mg/L Determine the followings: (i). The hydraulic detention time in hours. (ii). The aeration tank volume in cubic meters. ...4/- SULIT EAP582
The shrimp processing plant generates 0.012 m3/s of wastewater each day. The wastewater is treated in an activated sludge plant. The average BOD5 of the raw wastewater before primary settling is 1400 mg/L. The aeration tank has effective liquid dimensions of 8.0 m wide by 8.0 m long by 5.0 m deep. The plant operating parameters are as follows: Soluble BOD5 after primary settling = 966 mg/L MLVSS = 2000 mg/L MLSS = 1.25 (MLVS) Settled sludge volume after 30 min = 225 mL/L Aeration tank liquid temperature = 15°C Determine the following: Return Activated Sludge (RAS) flow rate and Wasting Activated Sludge (WAS) flow rate.
A 14 mgd wastewater treatment plant has a primary clarifier that treats an influent with 800 mg/L of solids and a removal efficiency of 55%. Sludge at the bottom of the tank is pumped at a rate of 0.1 mgd. 1. What is the effluent solids concentration from the clarifier (in mg/L)? What is the solids concentration in the sludge at the bottom of the tank (in mg/L and %)? The primary sludge is further processed in a digester following treatment. What weight of solids (in lbs) need to be handled each week? а. b. с.
A wastewater with a BOD of 25mg/L is discharged through an outfall to a freshwater stream of mean velocity 0.1m/s. The DO downstream of the outfall is 8.5mg/L. Assume the deoxygenation rate is 0.25/d, the reaeration rate is 0.4 /d and the temperature of 20 degree C (DOs = 9.09mg/L). Compute for the ff: a) Critical distance b) minimum DO c) Oxygen deficit d) Critical time
The 550-bed Atlanta Hospital has a small, activated sludge plant to treat wastewater from the hospital. The average daily hospital discharge is 1.50 m3 per day per bed, and the average soluble BOD5 after primary settling is 450 mg/L. The aeration tank effective liguid dimensions of 10 m x 10 m x 5 m. The plant operating parameters are as follows: MLVSS - 2,600 mg/L; MLSS - 1.20 (MLVSS); Settling sludge volume after 30 min. = 200 mL/L. The aeration time is nearly?
After primary treatment, a municipal wastewater contains 150 mg/L BOD5. The wastewater flow of 0.44 m³/s (10 MGD) is then treated in an activated sludge system with an SRT of 12 d and an HRT of 6 h. Given the biokinetic parameters tabulated below, determine the effluent BOD5 (mg/L). Parameter Himax Ks ka Y Value 3 d ¹ 60 mg/L BOD, 0.10 d ¹ 0.6 mg VSS/mg BOD, K
A secondary treatment using a mixed water activated sludge system, have the flow rate of 10000m^3/day of municipal wastewater. BOD after primary clarification is 150mg/L.It is desired to not reach 5mg/L of soluble BOD in effluent. The kinetic values of the system having X=0.5kg/kg and Kd=0.05d^-1.MLVSS concentration in the secondary treatment is 3000 mg/L, the concentration in return sludge is 10000mg/L. Calculate the mass of solid that must be wasted each day for each of the selected sludge.