10)26 foot lodder leons againsta building so that its foot movesaway from the building at the noteof 3 feet per second. When the foot ofthe ladder is 10 feet from the building,the top is moving down, at what note.c.c.- What is dyafA) 46511) y = x². Tanx ; dy = ?dxB) 2A) 5x tanxD) 5x tanxA) = 7(3x+)²212) y = 2-X ;3x+1D)B) X5 sec X; dy = ?B) 6X-5(3XH)²c) 5x sec²³xE) SX"tanx + X-sec²x13) y = [X²+2X-1; dy = ?A) X+LX+B) 4y (x+1)(XH)(x²+2x-1) 3/2D) {(3x+1)2E) //c) 1D)2\x²+2x-13+2X

Since you have asked multiple questions, we will solve the first question for you. If you want any…

10) a 26 foot lodder bons against a building so that its foot moves away from the building at the note of 3 feet per second. When the foot of the ladder is 10 feet from the building.. the top is moving down, at what c.c.- What is dy df B) 3 D) { E) // A) 46 45

10) a 26 foot lodder bons against a building so that its foot moves away from the building at the note of 3 feet per second. When the foot of the ladder is 10 feet from the building.. the top is moving down, at what c.c.- What is dy df B) 3 D) { E) // A) 46 45

Elementary Geometry for College Students

6th Edition

ISBN:9781285195698

Author:Daniel C. Alexander, Geralyn M. Koeberlein

Publisher:Daniel C. Alexander, Geralyn M. Koeberlein

Chapter6: Circles

Section6.CT: Test

Problem 12CT

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Question

10)
26 foot lodder leons against
a building so that its foot moves
away from the building at the note
of 3 feet per second. When the foot of
the ladder is 10 feet from the building,
the top is moving down, at what note.
c.c.- What is dy
af
A) 46
5
11) y = x². Tanx ; dy = ?
dx
B) 2
A) 5x tanx
D) 5x tanx
A) = 7
(3x+)²
2
12) y = 2-X ;
3x+1
D)
B) X5 sec X
; dy = ?
B) 6X-5
(3XH)²
c) 5x sec²³x
E) SX"tanx + X-sec²x
13) y = [X²+2X-1; dy = ?
A) X+L
X+
B) 4y (x+1)
(XH)
(x²+2x-1) 3/2
D) {
(3x+1)2
E) //
c) 1
D)
2\x²+2x-1
3+2X

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