Answered: 10 kN 60 kN-m B -2 m -2 m 1 m--1 m→

Engineering

Mechanical Engineering

10 kN 60 kN-m B -2 m -2 m 1 m--1 m→

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter11: Columns

Section: Chapter Questions

Problem 11.2.4P: Repeat Problem 11.2-3 assuming that R= 10 kN · m/rad and L = 2 m.

See similar textbooks

Similar questions

ZAIN IQ 15 ull 36 zain 1Q Q1: MO =s 400 Ib F1= 400 F2 = -600 k F3 = 500 sin 45 i-500 cos 45 k Y600 lb M- rxF,, M, r2x F, M,- r3xF, M-M, + M, + M, 500 lb :س 2 15m P-08 kN T-12 AN 3m Determine the x-, y, and z- components of T. Determine the angles which the line of action of T forms with the positive x, y, and z-axes. Calculate the projection of P onto a line between d and F and determine the angle between P and AF. - Determine the vector expression for the moment of P about point E اضف ملف يقدم .لا ترسل كلمات السر عبر نماذج جوجل
A turbine rotor is mounted on a stepped shaft that is fixed at both ends as shown in The torsional stiffnesses of the two segments of the shaft are given by k = 3,000 N-m/rad and k2 = 4,000 N-m/rad. The turbine generates a harmonic torque given by M(1) = Mo cos wt about the shaft axis with M, = 200 N-m and w = 500 rad/s. The mass moment of inertia of the rotor about the shaft axis is J, = 0.05 kg-m?. Assuming the equivalent torsional damping constant of the system as e, = 2.5 N-m-s/rad, determine the steady-state response of the rotor, 0(1). O(1) M(1) = Mg cos etr %3! Turbine rotor, Jo
@ ll 65% 1:20 PM Edit 18 TREBLA Questian B2 The hydraulic cylinder shown in figure B2a exerts a force of 3 kN drected to the right on point Band to the left on point E. If the drum is required to rotate dockwise at a constant speed a. Copy and complete the free body diagram (figure B2b) by supplying the missing forces, moments, labels and dimensions. b. Detemine the magnitude of the couple M required to rotate the drum dockwise at a constant speed [5 marks] [10 marks) H,=0.40 H-0.30 D. 150'mm 150 mm E 300 mm 300 mm 150 mm 150 mm 250 mm Figure B2a 150 mm 300 mm 150 mm Figure B2b DO פם B8 W Tools Mobile View Share PDF to DOC 3
Q1 Two spur gears in a simple train shown in Figure Q1 are having the same module, m = 2 and their respective number of teeth is NTm = 30 for the driver gear, and NTG = 45 for the driven gear. The inertia of the gear attached to the motor is Im = 0.1 kgm? and the inertia of the second gear is IG = 0.1 kgm?. The second gear is connected to a pulley with the radius of 30 mm. The pulley is hoisting up the 2kg load with acceleration of a = 2 ms?. Given the gear transmission efficiency is 90%. a) Based on the module and number of teeth given, examine the pitch diameter of eachgear. b) Considering acceleration of load at 2 ms-?, evaluate the torque of the motor toovercome gears inertia.
6.21-6.38 For the beam shown, derive the expressions for V and M, and draw the shear force and bending moment diagrams. Neglect the weight of the beam.
(Seperate question) Also for 7-31 write one single V(x) and M(x) expression that covers the full length of the beam x=0 to x=12 do not write it by parts.
A turbine rotor is mounted on a stepped shaft that is fixed at both ends as shown in The torsional stiffnesses of the two segments of the shaft are given by ka = 3,000 N-m/rad and k2 = 4,000 N-m/rad. The turbine generates a harmonic torque given by M(t) = Mo cos wt about the shaft axis with M, = 200 N-m and w = 500 rads. The mass moment of inertia of the rotor about the shaft axis is Jo = 0.05 kg-m. Assuming the equivalent torsional damping constant of the system as c, = 2.5 N-m-s/rad, determine the steady-state response of the rotor, 6(1). O(1) ke M(1) = M, cos ot Turbine rotor, Jo
Q2/ Hydraulic cylinder is used to lift cars weighing 75 kN for 550 mm in 6 sec. The ratio of cross-section is 3:1 and the maximum pressure that provided by pump is 250 bar as in figure. Calculate a- The diameter of cylinder and rod W=75 kN 다 Dcy = 100 mm, Dr = 56 mm MIS 550 mm
Q1/ An open belt drive connected two pulleys 120 cm and 50 cm diameter on parallel shafts 4 m apart. The belt weights 0.9 kg/m length and maximum tension in it is not to exceed 2000 N. 0.3. The 120 cm pulley, which is the driver, runs at 200 rpm. Due to belt slip on one of the pulleys, the velocity of the driven shaft is only 450 rpm. Calculate the torque on each of the two shafts and power transmitted.
Find the axial force on the back of the impeller, whose outer diameter is D₂ = 300mm, the shaft diameter is D. = 50mm, the outlet pressure is 2.3bar and the revolution number is 1470rpm. The average angular velocity of the fluid is 85% of that of the impeller. (Solution: F = 9.36kN)
In a gearbox, a spur gear is mounted on a shaft at equal distances from twosupporting bearings. The shaft and mounted gear turn together at a speed of3600RPM. The gearbox is designed to transmit a maximum power of 3kW. Thegear contact angle is φ = 20°. The pitch diameter of the gear is dp = 30 in. a) Findthe radial force on each of the two bearings supporting the shaft.The ratio of the two bearings’ length and diameter is L/D = 0.5. The bearings aremade of acetal resin material with the following limits:Surface velocity limit, V, is 5m/s.Average surface-pressure limit, P, is 7 MPa.PV limit is 3000 psi-ft/min.b) Find the diameter of the shaft in order not to exceed the stated limits.
Q2 / A shaft transmitting 15kW at 200r.p.m. are supported by two bearings placed 1 m apart. A 600 mm diameter pulley is mounted at a distance of 300 mm to the right of left hand bearing and this drives a pulley directly below it with the help of belt having maximum tension of 2.25kN. Another pulley 400 mm diameter is placed 200 mm to the left of right hand bearing and is driven with the help of electric motor and belt having maximum tension of 3.376kN, which is placed horizontally to the right. The angle of contact for both the pulleys is180° and =0.24. Determine the suitable diameter for a solid shaft if the bending moment acting on the shaft is reversed, allowing working stress of 42MPA in shear for the material of shaft and have yield stress of 400MPA and ultimate stress of 500MP.. And design the keys which support each pulley if the material of the keys is the same for the material of shaft.