10 Mg(s) + Cd(aq) -> Mg (aq) + Cd(s) E = +1.98 V The magnesium electrode was dipped into a 1.00 M salution of M9SO4 and the cadmium elestrede was dipped into a solution of unknown Cd* concentration. The pctential of the cell was measured to be +1.54 V. What was the unknown Cd? concentration? (Answer: 1.4 x 1015 M)
10 Mg(s) + Cd(aq) -> Mg (aq) + Cd(s) E = +1.98 V The magnesium electrode was dipped into a 1.00 M salution of M9SO4 and the cadmium elestrede was dipped into a solution of unknown Cd* concentration. The pctential of the cell was measured to be +1.54 V. What was the unknown Cd? concentration? (Answer: 1.4 x 1015 M)
Principles of Instrumental Analysis
7th Edition
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Chapter24: Coulometry
Section: Chapter Questions
Problem 24.5QAP: What cathode potential (versus SCE) would be required to lower the total Hg(II) concentration of the...
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