1/0 Program Input: One integer value for transitor type, and four flaoting-point values for the threshold voltge Vth, Vg which is voltage of terminal g, Vd which is voltage of terminal d, and Vs voltage of terminal s. Program Output: One line that shows the mode of operation of the transistor as OFF or Linear or Saturation if the input values are valid. Else it will show Invalid. Note that the output is case-sensitive.
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- Course: Digital Logic Design You have to solve the question step by step and clearly Please. You have to solve in a 1 hour. Question is well explained you have to read first carefully then answers properly in a single solution: Question 5: Colors of different nature can be produced by mixing three fundamental colors that are red, green and blue. Consider you are assigned a task to design a digital system that is equipped with three different LEDs and four different color sensors. One LED is red (symbolized with R), one is green (symbolized with G) and one is blue (symbolized with L) while one sensor detects white color (symbolized with W), one detects black color (symbolized with B), one detects cyan color (symbolized with C) and one sensor detects magenta color (symbolized with M). It is known that each color sensor produces logic 1 output if and only if when an object of its corresponding color passes in front of it, otherwise logic 0. Each LED turns on when logic 0 is provided to…Task: DL34. In digital electronics, a NAND gate (NOT-AND) is a logic gate which produces an output which is false only if all its inputs are true; thus, its output is complement to that of an AND gate. A LOW (0) output results only if all the inputs to the gate are HIGH (1); if any input is LOw (0), a HIGH (1) output results. A NAND gate is made using transistors and junction diodes. Minimum number of NAND gates required to implement the following binary equation (A'+B') (C+D)?The slide 16 in lecture L2 shows the CMOS circuit for a NAND functionality and which transistors are ON or OFF depending on what the input is from the truth table. Draw a similar set of circuits showing which transistors are ON and OFF for a NOR functionality by first drawing the NOR circuit, similar to that in the slide.
- Design a CMOS transistor circuit that has 2 inputs, A and B, and produces a high output if and only if the two inputs differ from each other (this is an XOR gate). In order to accomplish this, you can assume that you also have access to the inverses of A and B and that you can use those as inputs to your circuit. Please remember that to get full points your circuit must be a proper CMOS circuit, label the pull down and pull up networks and make sure that these two circuits are complementary to each other.An asynchronous state machine has two inputs (X1 and X2) and one output (Z). The output is the same of the previous value if (X2=D0) and (Z) equals to the value of (X1) if (X2=1). The circuit combines .. AND- ..... * .gate(s) 3 1In digital electronics and modern computer hardware, a flip-flop is sequential digital circuit used as a basic memory element. It has two stable states and can be used to store state information. One of its states represents ‘1’ while the other represents ‘0’. The most common types of flip-flops are SR-flip-flop, JK-flip-flop, and D flip-flop. When used in a finite-state machine, the output and next state depend not only on its current input, but also on its current state (and hence, previous inputs).
- In digital electronics and modern computer hardware, a flip-flop is sequential digital circuit used as a basic memory element. It has two stable states and can be used to store state information. One of its states represents ‘1’ while the other represents ‘0’. The most common types of flip-flops are SR-flip-flop, JK-flip-flop, and D flip-flop. When used in a finite-state machine, the output and next state depend not only on its current input, but also on its current state (and hence, previous inputs). Figure 1 D-Flip-flop with clock pulse (CP) Figure 1 shows a D flip-flop with clock pulse (CP). D is directly passed from stage1 to stage 2 through NAND gate and passed as inverted through gate 5 and gate 4. The input D is always sampled when the system CP is 1. Considering the memory element in Figure 1, perform the following tasks: Design FSM for the Figure 1 Simulate the Figure 1 using C. Write 400 words report on shift and…Design a 2x1 Multiplexer circuit shown in Figure 1.9. Follow the design steps of the combinational circuit and apply the following: i Build the truth table diagram ii- Show the K-map steps, and the equation of the circuit. iii- Implement your design on the Circuit Maker. iv- Build the circuit practically and compare your experimental results with previous step (Circuit Maker Results).Designing Combinational Logic Circuits Exercise Example: Design a 4-input (A,B,C,D) digital circuit that will give at its output (X) a logic 1 only if there more ones than zeros in the binary number formed at the input. Inputs Output X = АвсD 0 0 0 0 1 0 0 0 0 0 1 0 0 1 0 1 0 0 0 1 0 1 1 CD 2 АВ 00 01 11 10 3 1 4 00 01 1 1 11 0 1 0 0 0 1 0 0 1 10 1 0 1 11 1 7 1 1 8 1 10 9 0 1 1 0 0 1 12 1 13 1 10 1 14 | 1 15 1 X = 1 1 1 1 1 А в С D X X
- Bipolar junction transistors (BJTs) are considered “normally-off” devices, because their natural state with no signal applied to the base is no ........... between emitter and collector, like an open switch. * Your answerAhmed designed a Digital Circuit Board that occupies a huge amount of electronic gates which is given in the following figure. A B G Pease help him to Write the Boolean Expression for the above digital circuit. ii. Simplify the circuit by using K-Maps. Redesign the circuit with less components. i. iii.06 A convolutional circuit has three internal registers (S0, S1, and s2), and two outputs (CO and c1), calculated as follows: c0=i+s0; c1=i+50+s1. We are currently in state 110 and receive input 1. What is the output and next state? O c0=0; c1=1; next=111 c0=0; c1=0; next=111 c0=1; c1=0; next=111 c0=1; c1=1; next=111 QUESTION 8 35 A convolutional circuit has three internal registers (S0, S1, and s2), and two outputs (co and c1), calculated as follows: c0=i+s2; c1=i+50+s1. We are currently in state 110 and receive input 0. What is the output and next state? c0=0; c1=0; next=011 c0=1; c1=0; next=011 c0=1; c1=1; next=011 c0=0; c1=1; next=011