108 first-year and senior students were asked if they had used cannibis in the past six months. The sampl. is summarized in the table. Is using cannabis independent of being a first-year? Used Cannabis (C) Did Not Use Cannabis (C) Total 21 36 15 First-Year Students (FY) 30 72 42 Senior Students (S) 51 108 57 Total O Yes: Since P(FY) + P(FY | C). O No: Since P(FY) + P(FY | C). O No: Since P(FY) = P(FY | C). O No: Since P(FY) = P(C | FY). %3D
108 first-year and senior students were asked if they had used cannibis in the past six months. The sampl. is summarized in the table. Is using cannabis independent of being a first-year? Used Cannabis (C) Did Not Use Cannabis (C) Total 21 36 15 First-Year Students (FY) 30 72 42 Senior Students (S) 51 108 57 Total O Yes: Since P(FY) + P(FY | C). O No: Since P(FY) + P(FY | C). O No: Since P(FY) = P(FY | C). O No: Since P(FY) = P(C | FY). %3D
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section: Chapter Questions
Problem 8CR
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Concept explainers
Contingency Table
A contingency table can be defined as the visual representation of the relationship between two or more categorical variables that can be evaluated and registered. It is a categorical version of the scatterplot, which is used to investigate the linear relationship between two variables. A contingency table is indeed a type of frequency distribution table that displays two variables at the same time.
Binomial Distribution
Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.
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Transcribed Image Text:108 first-year and senior students were asked if they had used cannibis in the past six months. The sampl
is summarized in the table. Is using cannabis independent of being a first-year?
Used Cannabis (C) Did Not Use Cannabis (C Total
15
21
36
First-Year Students (FY)
42
30
72
Senior Students (S)
57
51
108
Total
O Yes: Since P(FY) + P(FY | C).
O No: Since P(FY) + P(FY | C).
O No: Since P(FY) = P(FY | C).
O Ne: Since P(FY) = P(C | FY).
ONone of the above.
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