15х2 — х3— 43х - 19 The integral | can be rewritten as (x + 1)²(x² – 6x + 13) Ах + B C D lax² + bx + c (mx + n)t' rx + s] C What is the value of ? (тx + п)*

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter8: Polynomials
Section8.5: Using The Distributive Property
Problem 57PFA
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15х2 — х3 —43х - 19
...
The integral
can be rewritten as
(x + 1)2(x2 – 6x + 13)
Ах + В
C
D
ax² + bx + c
+
(тх + п)*
rx + s.
C
What is the value of
(тx + п)*
3
A
x + 1
1
B
x + 1
2
x + 1
-2 In ( x+1) 2
Transcribed Image Text:15х2 — х3 —43х - 19 ... The integral can be rewritten as (x + 1)2(x2 – 6x + 13) Ах + В C D ax² + bx + c + (тх + п)* rx + s. C What is the value of (тx + п)* 3 A x + 1 1 B x + 1 2 x + 1 -2 In ( x+1) 2
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