16.792 g of Ba(OH)2 (171.342 g.mol') is weighed out and carefully dissolved to make a 500.00cm³ solution. A 25.00 cm³ of this solution is pipette then transfer into a 100.00 mL volumetric flask, filling up to the mark with water. A 40.00 mL sample of this diluted solution is then reacted with a 0.753 M solution of HNO3. Ba(OH)2(aq) + 2HNO3(aq) → Ba(NO3)2(aq) + 2H20(1) The moles of Ba(OH)2 transferred to the beaker is: 1.96 x 10-3 mol 5.21 x 10-3 mol 4.90 x 102 mol 1.96 x 10-1 mol O 3.92 x 10-3 mol O None of the above

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter4: Reactions In Aqueous Solution
Section: Chapter Questions
Problem 77QAP: A 300.0-g sample of a solid is made up of a uniform mixture of NaNO3, MgCl2, and BaCl2. A 100.0-g...
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16.792 g of Ba(OH)2 (171.342 g.mol') is weighed out and carefully dissolved to make a 500.00cm³ solution. A 25.00 cm³ of this solution is
pipette then transfer into a 100.00 mL volumetric flask, filling up to the mark with water. A 40.00 mL sample of this diluted solution is then reacted
with a 0.753 M solution of HN3.
Ba(OH)2(aq) + 2HNO3(aq)
Ba(NO3)2(aq)
+2H2O(1)
The moles of Ba(OH)2 transferred to the beaker is:
1.96 x 10-3 mol
5.21 x 10-3 mol
4.90 x 10-2 mol
1.96 x 10-1 mol
O 3.92 x 103 mol
None of the above
Transcribed Image Text:16.792 g of Ba(OH)2 (171.342 g.mol') is weighed out and carefully dissolved to make a 500.00cm³ solution. A 25.00 cm³ of this solution is pipette then transfer into a 100.00 mL volumetric flask, filling up to the mark with water. A 40.00 mL sample of this diluted solution is then reacted with a 0.753 M solution of HN3. Ba(OH)2(aq) + 2HNO3(aq) Ba(NO3)2(aq) +2H2O(1) The moles of Ba(OH)2 transferred to the beaker is: 1.96 x 10-3 mol 5.21 x 10-3 mol 4.90 x 10-2 mol 1.96 x 10-1 mol O 3.92 x 103 mol None of the above
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