18 kN 3 B 25 kN 8m DE 6m D 10 kN Figure 1

Q: 4 kN RA = 64 kN 30 kN/m 2.0 m 2.5 m MA = 70 kN.m %3D

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Q: 2m A * 4m 4m E 4M 4200 kN

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Q: (M=450 lb-ft (M)s = 300 lb-ft 3.5 ft 1.5 ft 2 ft 2 ft (Mh = 250 lb-ft

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Q: 20 KN/m 10 KN/m 學 2.00 1.70 1.30

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Q: 25 lb 40 lb 24 in. 0.5 in. 4 in. a B Section a – a

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Q: 1 kN 2 kN 2 kN 2 kN 1 kN H 0.46 m F D 2.62 B I A C| E G| 2.4 m 2.4 m 2.4 m 2.4 m Figure 2

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Q: Find the force of the rods AB, AC, BC, CD and AD. 20 N I. 40 N B C 10 cm A D 10 cm

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Q: 10 kN 5 kN 3 kN/m F C D E 3 m 1 m 4 m 3 m 1 m

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Q: 60 Ib 90 lb 30 45 150 lb

A: GIVEN DATA- A 150lb BOX GIVEN ACTED BY TWO FORCES WE HAVE TO FIND ACCELERATION OF IT

Q: 40 kN E 2 m B F 3 m 50

A: to find reaction component at B and C

Q: free-body diagrams. 6 ft 3 kip/ft B. 2 kip/ft -3 ft C

A: As per bartleby guidelines we are allowed to solve only 1st question if multiple questions are…

Q: 500N 900N 60 B 4m A 5m

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Q: R=50 Lbs Length FE75 inch Length FR 12 Inches Calculate E (Lbs) Calculate MA

A: Draw the free body diagram.

Q: FIGURE 1 60 kN B 0.75 E F :1.00 1.00. 1.00 25 kN

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Q: F 1000 lb y 500 lb 45° 30°

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Q: 50KN 20 kN 1OKN/M 3m 1m 2 m Figure 1

A: Given

Q: Neglecting the mass of the beam, compute the reactions at A and B.

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Q: W=4 kN/m 5 kN A 2.5 m + 1.5 m

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Q: W= 75 Ib W= 150 lb W= 75 Ib R.

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Q: 60° looks 50 g C 80° 6 G 30 VO 38 66 f 7 ft 78 ) ។ Yo >15 3ft 4ft 2ft Find force for all member? E

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Q: 20 kN 12 kN A В M = 10 kN-m %3D 4m 4m 4m Figure Q1 (b)

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Q: 3 kN/m В 8 m 4 m D 10 m 5 kN H. = 5 kN A A M, = 66 kNm a Va= 24 kN

A:

Q: 12KN 4 kN /m 12m 24 KN 12m 36m 一- 10

A: Dear student, we are suppose to solve only one question. Please post other question as a separate…

Q: Set P = 45 kN, P 25 kN. (Figure 1) %3! Figure 1of

A: To find force in member AB,BC,AG

Q: 100 lb 30° 200 lb 2 ft 300 ft-lb 2 ft 2 ft 2 ft-

A: First we resolved 100 lb force, and calculated horizontal force, vertical force and moment due to…

Q: 1.5 m 4 kN A B 2 m 8 kN C D 2 m F E

A: Let  RFx and RFy are the horizontal and vertical reaction at F RE is vertical reaction at E By using…

Q: 4 m A) 12 kN.m B) 16 kN m C) 20 kN m D) 22 kN.m 4 KN co 2 m 10 kN 2 m 2 m 2 kN/m E

A:

Q: In the Figure 6, the absolute force value in the bar AC is (in kN): Figure 6: 5 m/ 5 m 5 m A 20 KN B

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Q: < 1 of 1 Figure E 6 m D 4 m 4 m 4 m Pi P2

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Q: - 2- 45 100lbs/ft 300lb 30 200lbs

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Q: 5 panels at 3 m E 3 m G 1.8 kN 15 1.8 kN 3 m 15° 3 m 5 m

A: given data: we consider only calculating side figure: TAB=force in member ABTAE=force in member…

Q: B A 10m 6m C 8m 6m

A: Given:

Q: F 105° 60° 45° 300 lb 60° 400 lb 200 lb

A:

Q: 100 kN/m 150 KN E (m) 5 7 10

A: "Since you have posted a question with multiple sub-parts, we will solve the first three sub-parts…

Q: 12 KN 2.5 KN/M 介介企 A 12 m B 4m

A: A beam is defined as a structural member subjected to transverse shear load during its…

Q: figure. 400 lb 30 Note: 1" x 1" 228 lb

A: To find resultant

Q: 100 kN Half circle 6.0 m Pinned Pinned 4.0 m 40m

A: Let RA and RB are the reactions at pin support  By law of equilibrium of forces in vertical…

Q: In the Figure 6, the absolute force value in the bar AB is (in kN): Figure 6: 5 m 5 m A 20 KN 5 m B

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Q: 12 kN/m 40 kN C A B 2 m 1m-

A: Let us draw the reaction force at A and C

Q: |20 kN 15 kN/m A 2 m 4 m B.

A: The reactions on the supports of beam can be drawn as follows,

Q: 20 kN D 20 kN 20 kN 3 m 10 kN 3 m 3 m A 4 m 4 m E 4 m 4 m B,

A:

Q: 10 KN/m 1a KN (m Ra 1.5 m 4m 3 m 1.5m

A: For solution refer below images.

Q: A 0.8 ft 4.8 ft 60 lb 3.5 ft E 48 lb 1.8 ft B |C D 3.6 ft

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Q: 2 kN/m 10 kN t. 5 m 3 m 2 m Figure 2

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Q: A 12' 1500 lb D 2000 lb E/ 10' 48' Figure 1-63 150 lb/ft G F 2000 lb B

A: Let us consider the given figure 1-63.tan θ=1024      θ=22.6°CA=12cos 22.6=13.6°FB=AD=ACcosθ…

Q: 1500 lb 300 lb/ft 300 lb/ft A B 3 ft- 3 ft- HINGE ROLLER (2)

A:

Q: 100 kN I 120 kN/m 60 kN/m Ic D 315 kN-m 3 m 3 m 3 m 3 m

A: Draw the free-body diagram of the beam.

Q: 3.kN 30 kN/m B.

A: given; upper left beam; ⇒lets take reaction force at A=RA⇒lets take reaction force at B=RB⇒load…