-2 Molarity of Standard Ag(NO), 5.2167/10 M Trial I Trial II Trial III Mass of Unknown 0.237 o. 232 g Initial Burette Reading 0.00 ml 7.90 mL ml Final Burette Reading 31.00 mL 42.00 mL mL Vol. Ag(NO,) Added mL mL mL Moles Ag(NO,) Moles CI Mass Cr % Ct in Unknown Average % Cr in unknown
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- La) Provide the balance cauation for this veaction Consider th hydrasne Na He NHs Caq)NA ockag)+ H2 OpN2H rcacko to produce 4- st Na Cl(an) b)if, 136.0.me of 0.375 M amming solution reacts With188L Na OCL at STP Which the immiting reagent and Which is the excess regont. is c)if 250ML hudrazine gas is collected at STP, wheet is eaction. the percend yield of theUEid- base tit ration the Consentrat ion of ammonia Solution excess HCL was titrated ith o.07om Na, cO3 Solutian. The volume of Na, Coz Solution reguired was 15.50 ml using the following eguations: 2HCLem> + Na, COgcaps CO2 Cays + HzO1) t NaCL Calculate the concentration (molarity and ppm) of ammonia in the Original Solution.(MM of NHzis 17.031.9/4) 10.0 was by of o.10OMI HCE to ThenH1 gramof Sampleof an impure mixture af NARCOZ and Natteo, containing impurties is dissalved and tityated with SN Hel wit p colourless after addition5mD otacid-Methyt ge is then added and 22ontof, acid reguired orange tochange the of Naz coz benotphthalein as indicator, the sotudion Curns this indicator what is the percoulye and Na Heoz in the sample ?
- An aqueous of 2.0dm3 contains 53.0g Na2CO3 Calculate in a) gdm-3 b) moldm-3A silver nitrate soluti on contains 14.77 g of primary standard AGNO3 , in 1.00 L what volume of this solution is needed toreact completely with 50.00 ml. of 0.01808 M Na2S. 1. O10.40 ml. 2. O 20.79 ml. 6.10 ml. 4. O12.31 ml. 5. O18.21 ml. 3.A 3.00 mL aliquot of 0.001 M NaSCN is diluted to 25.0 mL with 0.1 M HNO3. How many moles of SCN- are present?
- I1.6. A lo0mL solntion g 0.050MM tuffered to pHq.00 was titrates rith n+ 0. OSD OMEDTA. ca) Hhat is the egniralene volume, Ve in milliliters? (b) Caleulate Hhe concenpration f m" at ntA 350.00 mL solution of 0.00265 M A3B4 is added to a 280.00 mL solution of 0.00205 M C3D2. What is pQsp for A3D4?Q1) A sada- Lime Sample is 90% NaoH and 10% CaO• If 3gm is dissolved in 250 ml, what is the tutal normadity of the Selution as abase ? How many milliliters of O.57N H2 S@4 would be requiredd to titrate i00 me of the Solution ? Ans.s ( 0.309 N, 60.59 ml) Q12) How much water that required add to 200 ml HNO, ( densly = 1.285 gm/ml) Contains 46 wt% acid to Convert lo wt% acid solution? Ars. : 919.6 ml
- ng resourc.. (27) Could've Been - [References] Calculate the pH at the halfway point and at the equivalence point for each of the following titrations. a. 100.0 mL of 0.30 M HC7H502 (Ka = 6.4 x 10-5) titrated by 0.10 M NaOH pH at the halfway point = pH at the equivalence point = b. 100.0 mL of 0.40 M C2H;NH2 (K½ = 5.6 × 10¬4) titrated by 0.10 M HNO3 pH at the halfway point = pH at the equivalence point = c. 100.0 mL of 0.70 M HC1 titrated by 0.15 M NaOH pH at the halfway point = pH at the equivalence point =101 Chem101 b My Questions | bartleby А аpp.101edu.co E Apps e Resource Library -. Dashboard 101 Chem101 E Reading list Word wco Writing Centers at. 11-0218 NCI Theor.. Question 5 of 11 Submit A solution of tartaric acid (H:C&H.Os) with a known concentration of 0.155 M H2C«H«Os is titrated with a 0.425 M NaOH solution. How many mL of NaOH are required to reach the second equivalence point with a starting volume of 70.0 mL H.C«H«Os , according to the following balanced chemical equation: H:CH.Os + 2 NAOH - Na:CaH.Os + 2 H:O STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) 1000 0.425 0.001 0.0217 12.8 25.5 0.155 1 0.0511 51.1 5.11 x 104 70.0 g NaOH L H2CsH.Os mol H:CAH.O6 M H2CH«Os mol NaOH mL NaOH M NaOH mL H2CaH«Os L NAOH g H2C4H.O6 1:35 PM P Type here to search 46°F 2/27/2022A Sample Containfng mmol of KNOS is "parsed 6.00 x10-2² mmol of vesay ad z.00x102 mmol af ves@y ad 2.00x1o2 though a cation -excharye Column. the Colculate. volume o.02.00 M NaH of needed to titrete the elwate,