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- I'm asked to "assume that ozempic is in a solution at pH = 7. Draw the functional groups at their correct protonation form". For this, would I make all of the carboxyl groupsgo from COOH to COO-? and then the amide groups go from CONH to CONH3 + ? What about ether groups (COC) ?Addition of phenolphthalein to an unknown colorlesssolution does not cause a color change. The addition ofbromthymol blue to the same solution leads to a yellowcolor. (a) Is the solution acidic, neutral, or basic? (b) Whichof the following can you establish about the solution: (i) Aminimum pH, (ii) A maximum pH, or (iii) A specific rangeof pH values? (c) What other indicator or indicators wouldyou want to use to determine the pH of the solution moreprecisely?Benzoic acid (C6H5COOH) and aniline (C6H5NH2) areboth derivatives of benzene. Benzoic acid is an acid withKa = 6.3 x10-5 and aniline is a base with Ka = 4.3 x10-10. (a) What are the conjugate base of benzoic acid andthe conjugate acid of aniline? (b) Anilinium chloride(C6H5NH3Cl) is a strong electrolyte that dissociates intoanilinium ions (C6H5NH3+) and chloride ions. Which willbe more acidic, a 0.10 M solution of benzoic acid or a 0.10M solution of anilinium chloride? (c) What is the value ofthe equilibrium constant for the following equilibrium?C6H5COOH(aq) + C6H5NH2(aq) ⇌ C6H5COO-(aq) + C6H5NH3+(aq)
- 1) Complete the following reactions and identify the acid, base, conjugate acid and conjugate base. CH;CH,NH2 (aq) + H2O (1) a) CH;COOH (aq) + H,O (I) b) c) Identify the conjugate base and conjugate acid of each of the following. Conjugate Base Molecule Conjugate Acid HCO3 H20 HSO4- H2PO4C6H5NH2 + H2O <-> C6H5NH3+ + OH-. Aniline, a weak base, reacts with water according to the reaction. (a) a sample of aniline is dissolved in water to produce 25.0 mL of 0.10 m solution. The pH of the solution 8.82. Calculate the equilibrium constant, Kb, for this reaction (b) What is the percent disassociation for the solution in part (a) (c) 25.0 mL of 0.10 HCI was then added in a titration experiment. What is the pH at the equivalence point?Using the table of the weak base below, you have chosen Pyridine as your weak base in the buffer solution. You have already added enough of the conjugate acid salt to make the buffer solution concentration at 0.62 M in this salt. The desired pH of the buffer should be equal to 4.5. Values of K, for Some Common Weak Bases Conjugate Acid Name Formula Ammonia Methylamine Ethylamine Aniline NH3 CH;NH2 CH;NH2 CH;NH, C;H;N NH,+ CH;NH;* CH$NH;* CH;NH;* C;H;NH* 1.8 × 10-5 4.38 x 10-4 5.6 x 10-4 3.8 x 10-10 1.7 x 10-9 Pyridine 3. Compute the concentration of the weak base in Molarity. (Write your answer in 3 decimal places without the unit).
- (a) Given that Ka for acetic acid is 1.8 x 10-5 and that forhypochlorous acid is 3.0 x 10-8, which is the stronger acid?(b) Which is the stronger base, the acetate ion or the hypochloriteion? (c) Calculate Kb values for CH3COO- and ClO-.4. A student has prepared 0.05 M solution of CH3-C=CH and has added to it 0.05 M solution of potassium tert-butoxide (K" O-C(CH3)3). (i) Write the equation for the acid-base reaction that might occur. (ii) With curved arrows track the movements of electron pairs. (iii) Assign Base, Acid, Conjugate acid for the base, Conjugate base for the acid. (iv) Calculate the percentage of deprotonated methyl acetylene taking into account that pKa of the conjugate acid of potassium tert-butoxide equals 18 and pKa of methyl acetylene equals 24.2) Calculate the pH of a sólution prepared by dissolving 0.150 mol of acetic acid and 0.300 mol of sodium acetate in water sufficient to yield 1.00 L of solution. The Ka of acetic acid is 1.76E-5.
- NaHCO3 can deprotonate benzoic acid but cannot deprotonate phenol. On the other hand, NaOH can deprotonate both benzoic acid and phenol. Given this information, rank the molecules numbered I to V in order of decreasing acidity. COH cOH он H,0 H,CO, IV CH3 II I II (A) V > II >I > III > IV (В) II > 1 > V > III IV (C) II > V >I > IV > IIPhenylamine is an aromatic amine that is used in the manufacture of dyes. When absorbed through the skin itcauses the Fe+2 in hemoglobin to become oxidized into Fe+3, resulting in the formation of methemoglobin whichcannot bind to or transport oxygen. Phenylamine is soluble in water and acts as a weak base.C6H5NH2 (aq) + H2O (ℓ) ⇋ C6H5NH3+ (aq) + OH- (aq)a. When you measure the concentrations of the ionized substances you find them to be:[C6H5NH2] = 0.234 mol/L [C6H5NH3+] = 2.8 x 10-5 mol/L [OH-]= 2.8 x 10-5 mol/LIf the Kb is 4.27 x 10-10, is the reaction at equilibrium? If not, which direction does it need to move (rightor left) to reach equilibrium? Explain. b. At equilibrium the concentrations of the ionized substances are:[C6H5NH2] = 0.0537 mol/L [C6H5NH3+] = 4.79 x 10-6 mol/L [OH-]= 4.79 x 10-6 mol/LIf this reaction is taking place in a 2.0L container, and 1.5 moles of phenylamine were added to thereaction, what will the new concentrations of the three ionic species be when…(a) Tsomane and Nyiko were given a task of synthesising methylenecyclohexane 2. After a brief discussion with each other, Tsomane proposed Method A to synthesise 2 from cyclohexanone 1 while Nyiko proposed Method B that started from hydroxymethylcyclohexane 3. Each student believed that their proposed method is better than the other. (Scheme below) (ii) Ph Ph Ph 640 THF A 1 B H₂SO4 100 °C 3 OH In analysing both these methods, are there other possible alkene products other than methylenecyclohexane 2?