n = mg = 35 kg x 9.8 m/s²= 343 NHs n = 0.50 x 343 Nfs == 171.5 NFp = fs = 171.5 N2. A boy exerts 50.0 N to push an object across a horizontal surface at constantvelocity. If the object has a mass of 10.0 kg, what is the coefficient of kinetic frictionbetween the object and the surface?3. How much force is needed in Problem 2 if the boy exerts the force at an angle of30.0° above the horizontal.The coefficient of sliding friction between a 50.0 kg ice and the pavement is0.06. What force is needed to move the ice at constant speed across the pavement?4. ACTIVITY 2: SOLVE THESE PROBLEMS FOR MEDirection: Answer the following problems. Write the given, what is required, sketch of thegiven, free-body diagram and the solution.1. Art pushes a 35 kg box across a wooden surface whose coefficient of static frictionforce is 0.50. How much force is needed to start the motion?Given:Required:m = 35 kg.FPv = 0.00 m/s Hs= 0.50shutterstock.c om 3 98746132FP = fs.FW = n

Answered: Image /qna-images/answer/4dcbf2df-5cca-4389-ad35-3904fcecb979.jpg

2. A boy exerts 50.0 N to push an object across a horizontal surface at constant velocity. If the object has a mass of 10.0 kg, what is the coefficient of kinetic friction between the object and the surface?

2. A boy exerts 50.0 N to push an object across a horizontal surface at constant velocity. If the object has a mass of 10.0 kg, what is the coefficient of kinetic friction between the object and the surface?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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ACTIVITY 2: SOLVE THESE PROBLEMS FOR ME Direction: Answer the following problems. Write the given, what is required, sketch of the given, free-body diagram and the solution. 1. Art pushes a 35 kg box across a wooden surface whose coefficient of static friction force is 0.50. How much force is needed to start the motion? Given: Required: m = 35 kg. v = 0.00 m/s µs FP = 0.50 shutterstock.com- 398746132 FP = fs. FW = n n = mg = 35 kg x 9.8 m/s? %3D = 343 N f; = Hsn = 0.50 x 343 N = 171.5 N Fp = f; = 171.5 N
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Hi the last part is telling me it is wrong for the frictional force? im trying to solve but not sure the correct way ff=u*FN?
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Name ver ve Problem 2 Section A 50.0-kg block is being pushed down a 16.0° slope by a force Ê of magnitude 250 ove directed at an angle of 25.0° from the horizontal as shown on the figure. The block moves down the incline plane. The coefficient of kinetic friction between the block and the Blope to 0.200. a) brock. babel each force clearly. Also show your x- and y-axes clearly. | Draw the free body diagram of the block showing all the forces acting on the |25.00 ) 16.0° b) [6 mri Calculate the magnitude of the normal force. hand the the top of Calculate the magnitude of the acceleration of the block. 20.0 peed B0 flling with pointa]