2. A hollow cylinder 2 m long has an outside diameter of 50mm and inside diameter of 30mm. If the cylinder is carrying a load of 25 KN. FInd the stress in cylinder , also find deformation of the cylinder E=100 Gpa.
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![2. A hollow cylinder 2 m long has an
outside diameter of 50mm and inside
diameter of 30mm. If the cylinder is
carrying a load of 25 KN. FInd the stress in
cylinder , also find deformation of the
cylinder E=100 Gpa.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcf36f9e7-8ed0-4e90-a906-f20ac776e068%2F5e04cf8e-b8f4-4902-b060-64a09b5f58ae%2F1s2wse8_processed.jpeg&w=3840&q=75)
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- 2. A hollow cylinder 2 m long has an outside diameter of 50mm and inside diameter of 30mm. If the cylinder is carrying a load of 25 KN. FInd the stress in cylinder , also find deformation of the cylinder E=100 Gpa.A mild steel rod of 25 mm diameter and 400 m long is encased centrally inside a hollow coppertube of external diameter 35 mm and inside diameter 30 mm. The ends of the rod and tube arerigidly attached, and the composite bar is subjected to an axial pull of 40 kN. If E for steel andcooper is 200 GN/m2 and 100 GN/m2 respectively, find the stress developed in the rod and thetube. Find also the extension of the rod.Clear my choice Let's consider a rod having a solid circular cross-section with diameter of 4 mm and it is made of a material having a Young's modulus E= 200 Gpa and a Poisson's ratio of 0.3. If a tensile force Fis subjected to that rod cross-section, the diameter becomes 3.995 mm. determine the applied force F. Select one: O F= 5236 N OF=15708N O F= 13090 N OF=10472 N OF=4189 N O F=6283 N Clear my choice Finish attempt NEXT ACTIVITY MENG360 Test -Spring 2020-2021 Jup to
- Z. a 300 mm 300 mm a F Find the maximum F that can be applied to the lever, if the material has a yield stress 60 MPa and if the diameter @ a-a crossection is 55 mmSolve for the indentation diameter if the BHN of the material is 70 and a 500 kg of load is applied? Use indenter diameter 10mm.An iron column of annular cross-section has an outer diameter of 200 mm and is subjected to a force of 75 kN. Find the thickness of the wall if the allowable compressive stress is 10 Mpa.
- Let's consider a rod having a solid circular cross-section with diameter of 4 mm and it is made of a material having a Young's modulus E = 120 Gpa and a Poisson's ratio of 0.33. If a tensile force F is subjected to that rod cross-section, the diameter becomes 3.995 mm. determine the applied force F. Select one: O F= 2856 N OF = 2285 N OF = 7140N OF = 5712 N OF = 3427 N O F = 8568 NB4 The short concrete cylinder having a diameter of 50 mm is subjected to a torque of 500 Nm and an axial tensile force of 2 kN. Find: 500 Nm 500 Nm A 2kN 2kN (a) the tensile stress in the concrete;A bronze bar is fastened between a steel bar and an aluminum bar as shown in Fig. Axail loads are applied at the positions indicated. Find the largest value of P that not exceed an overall deformation of 0.1 mm, or the following stresses: 140 MPa in the steel, 120 MPa in the bronze, and 80 MPa in the aluminum. Assume that the assembley is suitablly barced to prevent buckling. Use E = 200 GPa for steel, E=83 GPa for bronze, and E= 70 GPa for aluminum. Steel A= 480 mm² Bronze A = 650 mm² Aluminum A = 320 mm² 3P 4P 2P 1.0 m 1.5 m P = 12.8 KNO P = 6.8 KN P = 1.4 KN P = 0.4 KN 2.0 m
- Find stress of a aluminum cylinder of diameter 12.8mm and gauge length 50.8mm. The force applied is 47,500N.A 12 mm thick steel tire has a width of 110 mm has an internal diameter of 800 mm. Tire is heated and shrunk to a steel wheel 800.5 mm in diameter. E=200 MPa. Find the tensile stress in the tire. Look for the compressive pressure between the tire and wheel.Clear my choice Let's consider a rod having a solid circular cross-section with diameter of 6 mm and it is made of a material having a Young's modulus E = 120 Gpa and a Poisson's ratio of 0.33. If a tensile force F is subjected to that rod cross-section, the diameter becomes 5.998 mm. determine the applied force F. Select one: O F= 5712 N O F= 2285 N O F= 8568 N O F= 2856 N O F= 3427 N O F=7140 N Finish attempt..
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