"OF2. Forces P and F acting along the bar shown in the figure, to maintain equilibrium of pin A. Determinethe value of P and F.DOA¹08 800 000 = AR BMX 6.5 = A0=33'00 m2 00 00k = g20088.840 = R9mG6mPC008 12m400#582000E = 0180 N300 N 0-0

2. Forces P and F acting along the bar shown in the figure, to maintain equilibrium of pin A. Determine the value of P and F. DOA 108 800 006 = AR B MX 6.88 = A 0=√73 '00 m2 00 00k = gl 2008 = 8.840 = R 9m 6m P C 008-12m 200 0E = 0 180 N 1400-58 300 N 0-0

2. Forces P and F acting along the bar shown in the figure, to maintain equilibrium of pin A. Determine the value of P and F. DOA 108 800 006 = AR B MX 6.88 = A 0=√73 '00 m2 00 00k = gl 2008 = 8.840 = R 9m 6m P C 008-12m 200 0E = 0 180 N 1400-58 300 N 0-0

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

System of Forces

A force is an external influence or agent that changes the state of a system. According to Newton's second law, the force applied to a body is proportional to the change in momentum of a body. Hence, whenever a force is applied to a body, its momentum changes. If the body is at rest, under the action of force, its state of rest changes to motion. In other words, the magnitude of the momentum of the body changes from zero to a measurable value. Similarly, if the body possesses some initial velocity, it has some associated momentum, the effect of force can cause the body to halt or come to rest, that is, the momentum reduces to zero.

Question

"OF
2. Forces P and F acting along the bar shown in the figure, to maintain equilibrium of pin A. Determine
the value of P and F.
DOA
¹08 800 000 = AR B
MX 6.5 = A
0=33
'00 m2 00 00k = g
2008
8.840 = R
9m
G
6m
P
C
008 12m
400#58
200
0E = 0
180 N
300 N 0-0

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