2. In a survey of 1024 US adults, 287 said that their favorite sport to watch is football. a. Find a point estimate for the population proportion of US adults who say favorite sport to watch is football. their b. Then construct a 95% confidence interval for the proportion of US adults who say their favorite sport to watch is football.

Q: How many of the 3005 subjects used at least one prescription medication? Construct a 90% confidence…

A: p=0.817 = probability of subject use at least one prescription  n = 3005 = number of adults involved…

Q: Suppose we want to estimate the proportion of teenagers (aged 13-18) who are lactose intolerant. If…

A: Given information Error = 4% = 0.04 Confidence level = 0.95

Q: a. How many of the 3039 subjects used at least one prescription medication? (Round to the nearest…

A: Given : Total sample size of the survey  = 3039 Out of the sample, proportion of people who have…

Q: A university dean is interested in determining the proportion of students who receive some sort of…

A: Confidence Interval: The form of the confidence interval is, CI = Point estimate ± Margin of error…

Q: What is the number of data values? O 50 O 78 O 120 49 O 76 How many degrees of freedom are used for…

A: data value 76

Q: Suppose we want to estimate the proportion of teenagers (aged 13-18) who are lactose intolerant. If…

A: Given information Error = 2% = 0.02 Confidence level = 0.95

Q: Calculate 95 percent confidence intervals for the means of the following set of numb 15,9, 18, 10,…

A: Given data, 15,9,18,10,14,23,14,11,15,11,18,14,18,15,13   From the given data. n=15 The sample mean…

Q: Suppose we want to estimate the proportion of teenagers (aged 13-18) who are lactose intolerant. If…

A:

Q: In a survey conducted by the Gallup organization September 6-9, 2012, 1,017 adults were asked, "In…

A: Given that  Total= 1017 Find Frequency table

Q: If n=160 and ˆp (p-hat) =0.48, find the margin of error at a 99% confidence level

A: Given Data: p^=0.48n=160   We know that, p^-pp^(1-p^)n~ Normal(0,1)

Q: A Florida newspaper reported on the topics that teenagers most want to discuss with their parents.…

A: Given that there are 533 teenagers and the percentage of more family discussions about school is 37%…

Q: If α = 0.05, then what is the confidence level?

A: Given: α = 0.05   we know that, Confidence level+ α = 1

Q: 11. A television station surveys 200 customers and finds that 23% of customers watch the evening…

A: Margin of error = z*√(pq/n) Where z= z value            n=no of customer            q=1-p…

Q: Suppose we want to estimate the proportion of teenagers (aged 13-18) who are lactose intolerant. If…

A: According to the provided information, The z score at 95% confidence interval from the standard…

Q: packer produces 1,200 packages of ham per shift, how many packages should the Quality Control area…

A: To find the confidence level of 95%.

Q: How large is the sample if the confidence level is 97%, Ɛ = 2.5%  and ρ = .35?

A:

Q: If n=320 and ˆpp^ (p-hat) =0.26, find the margin of error at a 95% confidence level

A:

Q: Do People Think the Sun Goes around the Earth? In the 2018 General Social Survey, people were asked…

A: According to our policy we can answer only first three part for remaining please repost the…

Q: 2. A researcher wants to estimate the daily expenses of college students. He wants a 95% confidence…

A: We have given that,  Population standard deviation (σ) = 99.50, margin of error (E) = 45 and…

Q: A random sample of 600 voters in Centreville indicated that 90 of them believed their congressional…

A: Formula for confidence interval for population proportion : CI =p^ ± E  Where ,  p^ is sample…

Q: The figure to the right shows the results of a survey in which 1016 adults from Country A, 1014…

A: Proportion is almost similar to the concept of probability. Proportion is a fraction of population…

Q: If n = 41, ã=30, and s = 6, construct a confidence interval at a 80% confidence level.

A: It is given that Sample size n = 41 Sample mean = 30 Sample SD s = 6 The critical value of t at df =…

Q: Suppose we want to estimate the proportion of teenagers (aged 13-18) who are lactose intolerant. If…

A: Given information Error = 3% = 0.03 Confidence level = 0.95

Q: Ten students on a low-fat diet designed to lower their cholesterol and recorded their before and…

A: Let X represents the cholesterol level before diet and Y represents the cholesterol level after…

Q: Elly and Drew work together to collect data to estimate the percentage of their classmates who own a…

A: Given that Elly and Drew work together to collect the data to estimate the percentage of their…

Q: are the 95 percent confidence limits on the difference between the population means, where…

A: The data for listed from a before-and-after experimental design After Before 54 35 79 49…

Q: If n=150 and ˆpp^ (p-hat) =0.25, find the margin of error at a 90% confidence level

A: n = 150p^ = 0.2590% confidence level

Q: 4. To estimate the mean retail price of designer jeans, a buyer sampled 19 retailers in New York…

A:

Q: In June 2020, a Gallup Poll asked U.S. adults whether immigration was a good thing or a bad thing…

A: Given X=600 n=1000

Q: a. Given that Emily used a coin toss to select either her right hand or her left​ hand, what…

A: a. Given that Emily used a coin toss to select either her right hand or her left​ hand, what…

Q: The following small data set represents a simple random sample from a normally distributed…

A: a. The point estimate of is, Thus, the point estimate of is 50.25.

Q: In a statistics activity, students are asked to determine if there is a difference in the proportion…

A: Given : Claim : there is a difference in the proportion of times that a spinning penny will land…

Q: What Z score would be used to construct a 90% confidence level? Is it ... a. 1.65 b. 2.33 c.…

A: Confidence Level = 90 Significance Level = α = (100-90)% = 0.1 Critical value = z* = 1.65   […

Q: If about 75% of the students of a certain university are expected to use a laptop for online…

A: Given,sample proportion (p^)=0.75margin of error(E)=0.05α=1-0.99=0.01α2=0.005Z0.005=2.5758…

Q: The figure to the right shows the results of a survey in which 996 adults from Country A, 1006…

A:

Q: 3. Aresearcher wants to estimate the daily expenses of college students. He wants a 99% confidence…

A:

Q: The figure to the right shows the results of a survey in which 999 adults from Country A, 1002…

A:

Q: If n = 520 and p^ = 0.85, construct a 99% confidence interval

A: Here, n = 520 and p hat = 0.85.

Q: If a confidence interval for the mean is (38≤μ≤89)(38≤μ≤89), a) What is the point estimate?    b)…

A: Given,   Lower bound = 38​ Upper bound = 89

Q: The table shows the results of a survey in which separate samples of 400 adults each from the East,…

A: Given : n = 400 p̂= 0.26

Q: Consider the data set 34 45 27 33 38 41 45 29 30 39 34 40 28 33 36 (a) What is the sample median?…

A: (a) First arrange the data in ascending order. The order is,  27, 28, 29, 30, 33, 33, 34, 34, 36,…

Q: If a confidence interval for the mean is (43≤μ≤82)(43≤μ≤82), a) What is the point estimate?    b)…

A: Given the confidence interval for the population mean in tri-linear inequality form: Hence,

Q: A school administrator wants to know what proportion of the approximately 80,000 teachers in their…

A: Given: x=55n=100

Q: b. Construct a 90% confidence interval for the percentage of all judges who are in favor of the…

A: a. A random sample of 15 judges and asked them whether or not they favor the death penalty in which…

Q: 12. In a sample of 500 Canadians, 275 say they would rather retire in the US than in Canada.…

A: From the given information, Consider, X be the random variable that denotes the number of people who…

Q: The manager of a car company will select a random sample of its customers to create a 90 percent…

A: From the provided information, Confidence level = 90% Margin of error = 0.06

Q: (d) Use the combined data of 80 students, construct a 95% confidence interval estimate of the…

A: Given that  Total students=n=40+40=80 Number of pass students=X=28+32=60

Q: 26.4, 226.9, 227.1, and 228.6.  Student B:  229.5, 226.1, 230.7, 223.8, and 227.5

A: For student A: Sample size, n=5 228.3, 226.4, 226.9, 227.1, 228.6…

Q: If n=420 and ˆpp^ (p-hat) =0.19, find the margin of error at a 95% confidence level

A:

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.