2. Solve the initial value problem and the boundary value problem 2 – 164 + 50y = –14e-t + 10t°et [2 – 16 + 50y = –14et + 10t°e=t lv(0) – 0, y' (0) = 1, dt2 dt2 y(0) = 0, y(1) = 1. %3D (2) (a) Find the general solution of corresponding homogeneous equation.

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