2. (This is a problem from Physics 211 (Mechanics). Of course it has an electrical analog in the hydrogen atom, due to the analogy between gravity and electricity.) You are to make use of Kepler's laws of planetary motion to solve this problem. The orbit of Mercury around the sun is actually an ellipse with a very small eccentricity. For elliptical motion the location of the distance of closest approach of a planet to the sun is called the perihelion, and the location of the furthest distance of planet from the sun is called the aphelion. You are given the following data: mass of the sun: 1.98 × 10³0 kg; distance of Mercury from the sun at the perihelion: 24 X 100 km; speed of Mercury at the perihelion: 50 km/sec; speed of Mercury at the aphelion: 34 km/ sec; G = 6.67 X 10-¹1 m³/(kg sec²). Determine: 1) the distance of Mercury from the sun when it is located at the aphelion; 2) the length of a Mercurian year in seconds.

University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter13: Gravitation
Section: Chapter Questions
Problem 37P: Two planets in circular orbits around a star have speed of v and 2v . (a) What is the ratio of the...
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Chapter 21 and 22, Problem 2

2. (This is a problem from Physics 211 (Mechanics). Of course it has an electrical analog in the
hydrogen atom, due to the analogy between gravity and electricity.) You are to make use of Kepler's laws
of planetary motion to solve this problem. The orbit of Mercury around the sun is actually an ellipse with
a very small eccentricity. For elliptical motion the location of the distance of closest approach of a planet
to the sun is called the perihelion, and the location of the furthest distance of planet from the sun is called
the aphelion. You are given the following data: mass of the sun: 1.98 × 1030 kg; distance of Mercury
from the sun at the perihelion: 24 X 100 km; speed of Mercury at the perihelion: 50 km/sec; speed of
Mercury at the aphelion: 34 km/ sec; G = 6.67 x 10-¹1 m³/(kg sec2). Determine: 1) the distance of
Mercury from the sun when it is located at the aphelion; 2) the length of a Mercurian year in seconds.
6
Transcribed Image Text:2. (This is a problem from Physics 211 (Mechanics). Of course it has an electrical analog in the hydrogen atom, due to the analogy between gravity and electricity.) You are to make use of Kepler's laws of planetary motion to solve this problem. The orbit of Mercury around the sun is actually an ellipse with a very small eccentricity. For elliptical motion the location of the distance of closest approach of a planet to the sun is called the perihelion, and the location of the furthest distance of planet from the sun is called the aphelion. You are given the following data: mass of the sun: 1.98 × 1030 kg; distance of Mercury from the sun at the perihelion: 24 X 100 km; speed of Mercury at the perihelion: 50 km/sec; speed of Mercury at the aphelion: 34 km/ sec; G = 6.67 x 10-¹1 m³/(kg sec2). Determine: 1) the distance of Mercury from the sun when it is located at the aphelion; 2) the length of a Mercurian year in seconds. 6
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