2.004, p. 3.746 + log q. 4.876 + log (,0E) = 4.632 X = '1.005 '2.005

Introductory Chemistry: An Active Learning Approach
6th Edition
ISBN:9781305079250
Author:Mark S. Cracolice, Ed Peters
Publisher:Mark S. Cracolice, Ed Peters
Chapter3: Measurement And Chemical Calculations
Section: Chapter Questions
Problem 5E
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Please answer p and q

Solve the following. Be sure to report to the correct number of significant figures.
105
a.
103
8x102
b.
2x 10-6
c. (10)? =
d. 42 =
e. log (4x 2) =.
f. (2.0 x 1012) + (1.5 x 1014) =.
g. V8x 10° =
h. (5.0 x 107)(2.0 x 104)
%3D
i. log ) = 64
j. In )= 12
X =
0.082 2(0.20)*
I.
0.021
X =
=
2(0.10)*
m. 12.4 = 0.10 e.314(293)
X =
-4834
n. x= 4.62 e8.314(298) x=
o. 4x = 1.1 x 10s x=
2.004
p. 3.746 + log
'1.005
q. 4.876 + log (,mE) = 4.632
X =
'2.005
4.
Transcribed Image Text:Solve the following. Be sure to report to the correct number of significant figures. 105 a. 103 8x102 b. 2x 10-6 c. (10)? = d. 42 = e. log (4x 2) =. f. (2.0 x 1012) + (1.5 x 1014) =. g. V8x 10° = h. (5.0 x 107)(2.0 x 104) %3D i. log ) = 64 j. In )= 12 X = 0.082 2(0.20)* I. 0.021 X = = 2(0.10)* m. 12.4 = 0.10 e.314(293) X = -4834 n. x= 4.62 e8.314(298) x= o. 4x = 1.1 x 10s x= 2.004 p. 3.746 + log '1.005 q. 4.876 + log (,mE) = 4.632 X = '2.005 4.
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