2.58 Knowing that a 0.02-in. gap exists when the temperature is 75°F, determine (a) the temperature at which the normal stress in the aluminum bar will be equal to 11 ksi, (b) the corresponding exact length of the aluminum bar. 0.02 in. - 14 in. 18 in. Aluminum A = 2.8 in² Bronze A = 2.4 in² E = 15 × 106 psi α = 12 x 10-6/°F E = 10.6 × 106 psi α = 12.9 x 10-6/°F Fig. P2.58 and P2.59

2.58 Knowing that a 0.02-in. gap exists when the temperature is 75°F, determine (a) the temperature at which the normal stress in the aluminum bar will be equal to 11 ksi, (b) the corresponding exact length of the aluminum bar. 0.02 in. - 14 in. 18 in. Aluminum A = 2.8 in² Bronze A = 2.4 in² E = 15 × 106 psi α = 12 x 10-6/°F E = 10.6 × 106 psi α = 12.9 x 10-6/°F Fig. P2.58 and P2.59

Materials Science And Engineering Properties

1st Edition

ISBN:9781111988609

Author:Charles Gilmore

Publisher:Charles Gilmore

Chapter9: Time, Temperature, And Mechanical Properties

Section: Chapter Questions

Problem 9.3P

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2.58 Knowing that a 0.02-in. gap exists when the temperature is 75°F, determine (a) the temperature at which the normal stress in the alu- minum bar will be equal to -11 ksi, (b) the corresponding exact length of the aluminum bar. 0.02 in. - 14 in. - Bronze A = 2.4 in² E = 15 x 106 psi a = 12 x 10-6/°F Fig. P2.58 and P2.59 18 in.. Aluminum A = 2.8 in² E = 10.6 x 106 psi a = 12.9 x 10-6/°F 300 mm 0.5 mm 250
Question 2) Knowing that a 0.02-in. gap exists when the temperature is 75 °F, determine (a) the temperature at which the normal stress in the aluminum bar will be equal to -11 ksi, (b) the corresponding exact length of the aluminum bar. 0.02 in. -14 in. Bronze A = 2.4 in² E = 15 x 10 psi a = 12 x 10-6/°F -18 in.- Aluminum A = 2.8 in² E = 10.6 x 105 psi a = 12.9 x 10-6/°F
Knowing that a 0.03-in. gap exists when the temperature is 85 °F, determine the temperature at which the normal stress in the aluminum bar will be equal to-11 ksi. T= OF 0.03 in. 12 in. Bronze A = 2.2 in.² E = 15 × 106 psi a = 12 x 10-6°F 16 in.. Aluminum A = 2.8 in.² E = 10.6 × 106 psi a = 12.9 × 10 6 °F Ans = 250
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Knowing that a 0.02in gap exists when the temperature is 75°F, determine (a) the temperature at which the normal stress in the aluminum bar will be equal to -11ksi, (b) the corresponding exact length (2 decimal places in 10-3 inches) of the aluminum bar. 0.02 in. 14 in. 18 in. Bronze Aluminum A = 2.4 in? E = 15 × 10° psi a = 12 × 10-6/°F A = 2.8 in² E = 10.6 × 10° psi a = 12.9 × 10-6/ºF
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