22) The given equ" of the circle (x+12) ² + (y + 5) ² = 169 Here centre of the circle ins (-12,-5) and radius is 13 unit. Now (x(+12) ² + (y + 5) = 169 9 Differentiate wir-t a we 2 ( x +¹²) + 2 (y + 5) dy = 0 वर → dy= y+5 • Em (60) = -¹² dy 12 S The equn of the (2-0) = - 1²/31 (^~0) x+12 =-122 sy 2x+ 5yco (Ang) 127- Pr (-17-5) tangent get at (0,0) 12n+8y=

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.2: Graphs Of Equations
Problem 66E
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2) The
(x+12)² + (7+5) ² = 169
Here centre of the circle in (-12,-5)
and radius is 13 unit.
given
iven equ" of the circle is
Now, (x+12) ² + (y + 5) * = 169
→
Differentiate wir.t a we get
2(x + 2) + 2 (y + 5) dr = 0
क्य
dy =.
ㅋ
ㅋ 127
En
The equn of the
(2-0) = - 1²/31 (x-0)
2+12
=
=-122
y + 5
12
S
tangent at (0,0) =
sy:
127+ 5y =o (Ang)
(-12-5)
124+3y=0
Transcribed Image Text:2) The (x+12)² + (7+5) ² = 169 Here centre of the circle in (-12,-5) and radius is 13 unit. given iven equ" of the circle is Now, (x+12) ² + (y + 5) * = 169 → Differentiate wir.t a we get 2(x + 2) + 2 (y + 5) dr = 0 क्य dy =. ㅋ ㅋ 127 En The equn of the (2-0) = - 1²/31 (x-0) 2+12 = =-122 y + 5 12 S tangent at (0,0) = sy: 127+ 5y =o (Ang) (-12-5) 124+3y=0
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