25. The switch is closed at t = 0 sec in the circuit shown below. Find i for t> 0 sec. The capacitor is initially uncharged. O100 V 40 kn V₁ 6 kn 60 ΚΩ 40 kn 50 μF 22 20 ΚΩ 20 mAO
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- You are an electrician working in an industrial plant. You discover that the problem with a certain machine is a defective capacitor. The capacitor is connected to a 240-volt AC circuit. The information on the capacitor reveals that it has a capacitance value of 10 mF and a voltage rating of 240 VAC. The only 10-mF AC capacitor in the storeroom is marked with a voltage rating of 350 WVDC. Can this capacitor be used to replace the defective capacitor? Explain your answer.In the figure ɛ = 10.0 V, R1 = 4.00 N, and R2 = 1.00 N. The inductor is ideal. If the switch is closed for a long time, what is the current through the inductor. Give your answer in A. Şekildeki devrede ɛ = 10.0 V, R1 = 4.00 N , ve R2 = 1.00 N olarak verilmişlerdir. Solenoidin iç direnci yoktur. Anahtar kapatıldıktan çok uzun süre sonra solenoidden geçen akım A cinsinden nedir. R1 R2 L E YanıtınızThe figure below shows a simple RC circuit with a 3.30-μF capacitor, a 4.40-M resistor, a 9.00-V emf, and a switch. What are the following exactly 9.00 s after the switch is closed? (a) the charge on the capacitor 13.7204 UC (b) the current in the resistor 0.0110522 x Your response is off by a multiple of ten. HA (c) the rate at which the capacitor is storing energy μW (d) the rate at which the battery is delivering energy μW
- In the circuit below, Find the voltage across the inductor at time t = 0.000909 s. The values are V1 = 146V, R = 4.4 ohms, L =0.02 henries1. A purely resistive circuit the current is leading by 90° with respect to voltage. 2. A purely inductive circuit the current is lag behind the voltage by 90°. 3. A purely capacitive circuit the current is lead by 90° with respect to the voltage. 4. A capacitor element stored magnetic energy. 5. An inductor element stored electrical energy. 6. Resistor elements consume power. 7. Angle between current and voltage is called power. 8. The power factor angle for a purely resistive is zero. 9. The power factor angle for a purely inductive load is -90°. 10. The power factor of a purely capacitive is leading.CONSIDER THE CIRCUT BELOW.SUPPOSE V1=10V AND V2=1V BEFORE THE SWITCH IS CLOSED,WHAT IS THE COOMN VOLTAGE ACROSS THE CAPACITOR AFTER THE SWITCH CLOSED.
- A series R–L–C circuit comprises a 5µF capacitor, a 4ohm resistor and a variable inductance L. The supply voltage is 10∠0◦ V at a frequency of 159.1 Hz. The inductance is adjusted until the p.d. across the 4 ohm resistanceis a maximum. Determine for this condition (a) the value of inductance, (b) the p.d. across each component and (c) the Q-factor of the circuit.Assume the passive sign convention. Consider the current waveform. -1 daptive SYNC i(1) (A) 2 10 -2- 1 2 3 - r(s) Determine the voltage across a 2.4 F capacitor. (You must provide an answer before moving on to the next part.) The voltage across the 2.4 F capacitor is -- V. Q Search **** 1/0 ceciet JAA 22-k resistor and a 0.02-F capacitor are connected in series to a 5-V source. How long will it take the capacitor to charge to 3.4 V Select one: a. 0.501 ms b. 0.66 ms c. 0.44 ms d. 0.70 ms
- For R1=9000, R2=2000, R3=6000, R4=5000, C1=0.006, C2=D0.002 & 11=0.007 A in the shown circuit, obtain the energy stored in each capacitor under dc conditions. C2 R4 ŽR3 ER2 ŽRI C1= Energy stored in C1= Energy stored in C2=152130 222 Ⓒ520° Fj² 7 Find voltage drop Mutual inductance Majt = + {1.2 V. on 12 resistance Nex (the same for allProblem 2: Determine the voltages across the wo capacitors and the currents through the two inductors under dc conditions. 55 32H C1 =2pF R1 w 1000 R2 www 500 C2 HI 1μF R3 www 300 Den L2 5H R4 900