2a₁b₁ Let A = ab₂ + a₂b₁ abz+azb a₁b₂+ a₂b₁ 2a₂b₂ azb₂ + a₂b3 a₁b3 + c3b₁ a2b3 + a3b₂. Expressing 2a3b3 A as the product of two determinants, show that A = 0. Hence, show that if ax² + 2hxy + by² + 2gx + 2fy + c = (x + my + n) a h b f (I'x + m'y + n), then h g g f = 0. C

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