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2t is a solution to y"- y' +y=e4, use the superposition principle to find solutions to the differential equations in parts (a) through (c) below. Given that y (t) = cos tis a solution to y'"- y'+y = sint and y2 (t) 3 (a) y'" - y' +y= 15 sin t A solution is y(t) -! (b) y"-y' +y=5 sint-6 e 2 A solution is y(t) = (c) y" - y' y-6 sint+ 21 e 21 A solution is y(1) =

2t is a solution to y"- y' +y=e4, use the superposition principle to find solutions to the differential equations in parts (a) through (c) below. Given that y (t) = cos tis a solution to y'"- y'+y = sint and y2 (t) 3 (a) y'" - y' +y= 15 sin t A solution is y(t) -! (b) y"-y' +y=5 sint-6 e 2 A solution is y(t) = (c) y" - y' y-6 sint+ 21 e 21 A solution is y(1) =

Calculus For The Life Sciences
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter11: Differential Equations
Section11.CR: Chapter 11 Review
Problem 15CR
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2t is a solution to y"- y' +y= e4, use the superposition principle to find solutions to the differential equations in parts (a) through (c) below. Given that y, (t) = costis a solution to y"-y'+y = sint and y2 (t) 3 (a) y'" - y' +y= 15 sin t A solution is y(t)-! (b) y"-y' +y=5 sint-6 e 2t A solution is y(t) = (c) y" -y' y-6 sin t+ 21 e 21 A solution is y(t)=
Transcribed Image Text:2t is a solution to y"- y' +y= e4, use the superposition principle to find solutions to the differential equations in parts (a) through (c) below. Given that y, (t) = costis a solution to y"-y'+y = sint and y2 (t) 3 (a) y'" - y' +y= 15 sin t A solution is y(t)-! (b) y"-y' +y=5 sint-6 e 2t A solution is y(t) = (c) y" -y' y-6 sin t+ 21 e 21 A solution is y(t)=
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