3- Suppose that DS = 100H, SS = 300H, BP = 200H, and SI = 0100H, BX= 1500H . Determine the memory Physical address accessed by each of the following instructions, assuming real mode operation: MOV DL, [BP+200] %3D
Q: Q4./DS 2000, SS 3000, BX-012A, BP-021B, DI 0010 SI 0020. 1. Compute the offset of each of the…
A: We solve the question in figure: Figure 1:
Q: Example1: Describe the contents of the address, data and control bus lines when the instruction? MOV…
A: Solution:- Assembly code is as follows; CS = FEDBH ; ZETA = 1234H ; MOV BX, ZETA ; 0AH
Q: 2- Draw memory and microprocessor contents before and after execution the following instruction: MOV…
A: Given: We are given a microprocessor instruction below: Goal: We have to find the contents of…
Q: e system shown below, answer following questions CLK 3.3GHZ DATA BUS (16 bits) CPU ADDRESS BUS (23…
A: 1). 2address bus width Equals total addressable memory * The size of the data bus. For example, a…
Q: Q1) If BX=1000, DS=0200, SS=0100, CS=0300 and AL=EDH, for the following instruction: MOV [BX] +…
A: Given Values are:- BX= 1000, DS= 0200, SS=0100, CS=0300, AL=EDH The instruction is MOV [BX]+1234H,…
Q: Design a machine with a byte addressable main memory of 2 bytes and and block size of 8 bytes.…
A: answer is below:-
Q: Assume the miss rate of an instruction cache is 2% and the miss rate of the data cache is 4%. If a…
A: GIVEN: Instruction miss rate= 2% Data miss rate= 4% CPI without memory stalls =2 Miss penalty= 100…
Q: Assume that the registers have the following values (all in hex) and that CS=1000, DS=2000, SS=3000,…
A: Physical address: Actually, a physical address is also called as real address, or binary address. It…
Q: DATA ADDRESSING MODE Suppose that ES=7D68, DS=C5DC, SS=8FE7, AX=0BC5, DI=05E9, BP=0ACE, SI=05FD,…
A:
Q: Assume that two numbers: dividend and divisor are saved in memory address M1 and M2 respectively.…
A: Given that Assume that two numbers: dividend and divisor are saved in memory address M1 and M2…
Q: Assume SS=5000H, DS=6000H, ES=7000H, CS=9000H, BX=1000H, DI=2000H, BP=3000H, IP=4000H, SI=2000H, the…
A: Given: We are given various registers with values stored in them. Register such as SS, DS, ES, CS,…
Q: Assume SS=5000H, DS=6000H, ES=7000H, CS=9000H, BX=1000H, DI=2000H, BP=3000H, IP=4000H, SI=2000H, the…
A: MOV 20.[DI], AL Here we are given that DS = 6000H Shifting left 20 times we will get 6000…
Q: 2- Show how each of the following MIPS instructions is converted into machine code. Assume the…
A: Answer:- Solution: Conversion of machine code to MISP can done by following below steps…
Q: Question 2: Given the ending address and memory location address, determine the segment register…
A: Below I have solved the question on time .
Q: Consider the following instruction, discussed in Example 8.6: MAC *AR2+, *AR3+, A Suppose the…
A: Solution:-- 1)The given question has required for the solution which is related with the…
Q: Let us consider a memory that includes two instructions. First instruction is located at memory…
A: The solution for the above given question is given below:
Q: 1. The hypothetical machine of Figure 3.4 also has two I/O instructions: In these cases, the 12-bit…
A:
Q: 4. Assume that the state of the 8088´s registers and memory is as follows: Memory [DS:100H] = 0FH…
A: So after executing the each instructions the results prodeuced in the destination operand are given…
Q: Q2: Suppose that DS-0201h, BX= 300h, and DI- 400h determine the memory address accessed by each of…
A: First, convert all the Hexadecimal numbers into decimal numbers. DS, BX, DI, AL, AX, BI are like…
Q: 2- Show how each of the following MIPS instructions is converted into machine code. Assume the…
A: Answer:- Solution: Conversion of machine code to MISP can done by following below steps…
Q: Assume SS=5000H, DS=6000H, ES=7000H, CS=9000H, BX=1000H, DI=2000H, BP=3000H, IP=4000H, SI=2000H, the…
A: Given Instruction: MOV [DI + 3000H], AL. -> Here MOV means Move instruction. The content of…
Q: Address Word Ox00000015 ? Ox00000014 ? Ox00000013 ? Ox00000012 ? Ox00000011 )x00000010
A: Here is the solution to the above problem: -
Q: Q2/ Assuming that the registers have the following values (all in hex) and that CS-1000, DS-2000,…
A:
Q: b) The average memory access time for a microprocessor with 1 level of cache L1 is 2.6 clock cycles.…
A: Explanation: Consider the expressiono for miss rate of L1 cache. Given that: Hit time = 1…
Q: Consider 1GHZ clock frequency processor, uses different operand access modes shown below: Operand…
A: Introduction Given, Clock frequency as 1 Ghz For , memory access 8 cycle Arithmetic computation 4…
Q: (b) Suppose that the following instructions are found at the given location in memory. Illustrate…
A: Below I have Provided handwritten solution to the given question:
Q: 2- Find the physical destination address of last instruction below MOV BX,0AAH MOV AX,1BBH MOV DS,AX…
A: Please give positive ratings for my efforts. Thanks. ANSWER BX = 0AA H AX = 1BB H DS = AX = 1BB…
Q: QI) I BX=1000, DS-0200, SS=0100, CS-0300 and AL=EDH, for the following instruction: MOV [BX] +…
A: Here is Solution for Above Problem :: Q1). Given Data : BX = 1000 DS = 0200 SS = 0100 CS = 0300 AL…
Q: Solve the following problem using Write-Invalidate and Write-Through algorithm? Given three…
A: Write Invalidate the immediate sending of the updated cache block to the other cache is not done.…
Q: Assume that the Intel 8086 registers AL, BL, CL, and DL have the following values Gn Hexadecimal)…
A: Question 1) XCHG BL, DL will exchange the values of BL with DL , thus BL= AB DL = CD. Question 2)…
Q: Q2/ Assuming that the registers have the following values (all in hex) and that CS=1000, DS=2000,…
A: 1.Instruction Address: In the execution of a sequence of instructions in a computer program, a…
Q: Consider an instruction ADD AC, A, B which adds the contents of location A and the contents of…
A: Step1: The address of the current instruction has to be stored in Memory Address Register (MAR).…
Q: Suppose we have the instruction Load 0000. Given memory and register R1 contain the values below: R1…
A: Answer: We need to write the how to load into accumulator using the following addressing mode. So we…
Q: (B)- Choose the correct answer for the following questions (Choose FIVE Only) 1. Assume AL register…
A: Q.1 = C Q.2= B Q.3= C
Q: Find the physical destination address of last instruction below. MOV BX,0AAH MOV AX,1BBH MOV…
A: Given: MOV BX,0AAH MOV AX,1BBH MOV DS,AX MOV [BX],AX Our Task:Find the physical destination address…
Q: 3. Suppose M8=x and M9=y. After each instruction has been executed, what is the content of the…
A: Suppose M8-X And M9=Y. After Each Instruction Has Been Executed:
Q: Assuming a 500 KHz 6800 microprocessor, the total time (in microseconds) required to execute the…
A: Direct and Extended Addressing Modes In the Direct and Extended modes of addressing, the quantity…
Q: Let (BX)=100H, DI=200H, DS=1200H, SI= FO02H, AX= 0105H, and the following memory content. what is…
A: Solution:
Q: 2- Show how each of the following MIPS instructions is converted into machine code. Assume the…
A: Introduction: MIPS Instruction: If an instruction description begins with an o, then the…
Q: 2. Consider the initial value of register Stia Ox12345678 and the content of memory location…
A: Consider the initial value of register $t1 is 0x12345678 and the content of memory location…
Q: (B)- Choose the correct answer for the following questions (Choose FIVE Only) 1. Assume AL register…
A: 1) Ans:- Option c Assume AL register 7FH, it would become 81H after executed NEG AL instruction. 2)…
Q: Assume SS=5000H, DS=6000H, ES=7000H, CS=9000H, BX=1000H, DI=2000H, BP=3000H, IP=4000H, SI=2000H, the…
A: Given: We are given various registers with values stored in them. Register such as SS, DS, ES, CS,…
Q: Memory locations 00390H through 00393H contain, respectively, 9A, 76, 65, and 1F. What does AX…
A: Memory location 00393H contain ,respectively,9A ,76,65 and 1F.what does Ax contain after each…
Q: Assume miss rate of an instruction cache is 2% and miss rätê ôf data cac IS 4%, If a processor have…
A: Introduction:
Q: Question 2: Given the ending address and memory location address, determine the segment register…
A:
Q: Draw the memory map and show the values of the affected registers and memory locations. assuming AC…
A: The Answer is in Below Steps
Q: 2- Draw memory and microprocessor contents before and after execution the following instruction: MOV…
A: Given: We are given a microprocessor instruction that is executing. Goal: We have to find out…
Q: CPU Main Memory Instructions Space MAR ALU MBR AC BUS PC Control Data Space Cache Suppose we have…
A: To do the logical operation between 10 and 5, these two numbers have to be given to ALU as input.…
Q: 3) Assume SS=5000H, DS=6000H, ES=7000H, CS=9000H, BX=1000H, DI=2000H, BP=3000H, IP=4000H, SI=2000H,…
A: Concept Given: We are given various registers with values stored in them. Register such as SS, DS,…
Q: If BX=1000, DS=0200, SS=0100, CS=0300 and AL=EDH, for the following instruction: MOV [BX] + 1234H,…
A: Answer: It is a base addressing mode. Effective address of the operand obtained by adding direct or…
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- Q1- Write a program in assembly language for the 8085 microprocessor to receive 10 bytes of data via the SID and store it at the memory address (3000H to 3009H) using a baud rate of 1200. Information: The 8085 processor operates at a frequency of 3.072 MHz. When you receive each byte of the required bytes, you must adhere to the following: The bits of two high bits will be received at the beginning of the reception (start bits), after that the data bits will be received, after that the low bit of the stop bit will be received (stop bit). The following flowchart will help you, but you should notice that this flowchart deals with one byte, and you are required to deal with 10 bytes The solution must be integrated and include the calculation of the baudrate delay time Of+CD!HID+[00 Yes SIDATA Read SID Start Bit? Wait for Half-Bit Time Set up Bit Counter Wait Bit Time Read SID Save Bit Decrement Bit Counter All Bits Received? Add Bit to Previous Bits Go Back to Get Next Bit Return IMUNIa. Find the address accessed by each of the following instructions. If DS = 0100H, BX= 0120H, DATA = 0140H, and SI = 0050H and real mode operation:1. MOV DATA[SI], ECX2. MOV BL, [ BX+SI]b. Descriptor contains a base address of 00260000H, a limit of 00110H, and G = 1,determine starting and ending locations are addressed by the descriptor for aCore2.By assuming that X = 3, and 33 is a two digit number, consider memory storage of a 64-bit word stored at memory word 33 in a byte-addressable memory (a) What is the byte address of memory word 33? (b) What are the byte addresses that memory word 33 spans? (c) Draw the number 0xF1234567890ABCDE stored at word 33 in both big endian and little-endian machines. Clearly label the byte address corresponding to each data byte value.
- Suppose a specific MCU has the following size of memories: 2 M byte of flash, starting from 0x0800_0000, 256 k byte of SRAM starting from 0x2000_0000, and 8 k byte registers for GPIOs, start at 0x4001_0000. (Note that 0x is the prefix for hexadecimal numbers.) Draw the memory map based on your calculations for the addresses.The following tables contains memory dump and contents of few registers, as follows: add cont reg cont OXAO Ox72 eax 0x9C Ох9C Оx23 есх Ох11D Ох9Е Ох11 edx 0x40 OXA2 Ox41 After executing the following assembly line lea edx, [eax] The destination is ---- and its contents is Select one: а. еax, Ox 9C b. edx, Ox 23 C. edx, 0x 9C d. eax, Ox 23Ql'assuming the DS=1983 and SI-2284, BX-1325, BP-3425 and SS-1839, show the contents of memory locations after the execution? MOV CH,[BP]+23 MOV AX,[BX]+12
- 3. The contents of memory location B0007H are FFH and those at BO00AH are O0H. What is the data word stored starting at address B0008H? Is the word aligned or misaligned? And how many cycles are used to transfer this word if (a) BS16' is negated (b) BS16' is asserted?[b] Consider the following portion of memory with a starting address of 80000H (referenced by Val1). Show how the following declarations will get stored in the memory Vall DD 12345678H Varl DB 10, 3 DUP(0), 20 80000 80001 80002 80003 80004 80005 80006 80007 80008 80009 8000AConsider memory storage of a 32-bit word stored at memory word 34 in a byte addressable memory. (a) What is the byte address of memory word 34? (b) What are the byte addresses that memory word 34 spans? (c) Draw the number 0x3F526372 stored at word 342 in both big-endian and little-endian machines. Clearly label the byte address corresponding to each data byte value.
- Q1- Write a program in assembly language for the 8085 microprocessor to send 10 bytes of data located at the memory address (3000H to 3009H) using SOD at a baud rate of 1200. Information: The 8085 processor operates at a frequency of 3.072 MHz. When sending each of the required bytes, you must adhere to the following: The two high bits of the start bits must be sent, after that the data bits are sent, after that the low bit of the stop bit is sent. The following flowchart will help you, but you should notice that this flowchart deals with one byte, and you are required to deal with 10 bytes. The solution must be integrated and include the calculation of the baudrate delay time Transmit No Set up Character Bit Counter Send Start Bit Wait Bit Time Get Character in Accumulator Output Bit Using Do Wait Bit Time Rotate Next Bit in Do Decrement Bit Counter Is It Last Bit? Yes Add Parity if Necessary • Send Two Stop Bits Return (a)6- In 8086Mp bus cycles, the signal (ALE) becomes '1' during clock cycle. 7- The type of the buffer used for buffering data lines is while the type of the buffer used for buffering address lines is 8- During transferring a data of 8-bits from 8086Mp to memory address (1F871H), give the logic value of the following signals: M/IO= RD= = WR= BHE= 9- The benefit of multiplexing operation is 1. CC2. A memory location has a logical address where the segment address is the first four digits is your roll number and the offset address is the last four digits of your roll number. Find the physical address of the memory location. [example: if your roll number is 1234200516789, then the segment address is 1234h and the offset address is 6789h]