3. Report the sample mean and standard deviationof the 52-week cost under each policy. Usingthe simulated results, is it possible to constructvalid 95% confidence intervals for the average52-week cost for each value of U? In any case,graph the average 52-week cost versus U. Whatis the best value of U for L 5 30
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3. Report the sample mean and standard deviation
of the 52-week cost under each policy. Using
the simulated results, is it possible to construct
valid 95% confidence intervals for the average
52-week cost for each value of U? In any case,
graph the average 52-week cost versus U. What
is the best value of U for L 5 30
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- For all parts of this question, assume that the log of GDP per capita is normally distributed with a mean of 8.7 and standard devistion of 1.5Step 1 of 4: If the log of the world distribution of income is normaly distributed with a mean of 8.7 and a standard deviation of 1.5, what income indollars) marks the 90th percentile? KeypadAnswer A 71.325B 1.29C 41,253D 10.63The data from 200 machined parts are summarizedas follows:y yesdepth of boreE, noabovebelowedge conditioncoarsetarget15target10moderatesmooth25205080(a) What is the probability that a part selected has a moderateedge condition and a below-target bore depth?(b) What is the probability that a part selected has a moderateedge condition or a below-target bore depth?(c) What is the probability that a part selected does not have amoderate edge condition or does not have a below-targetbore depth?(d) Construct a Venn diagram representation of the events inthis sample space.Can you explain what these two belows mean in regard of GMM and Maximum likelihood. What are we calculating and what is it used to Unconstrained optimizationConstrained optimizatio
- A quality inspector took five samples, each with four observations, for the length of timefor a chemical test to return a conclusive result. All values are in minutes. Use this informationto develop ONE control chart for the variable measure of time. Use formulas Unit 4 zoom filesto assist with your calculations. The process distribution standard deviation is known to be 0.02minute. Develop the chart with 3-sigma limits. i need the graph as well.A forecasting method has produced the following over the past five months Actual 140 Forecast 154 140 112 140 84 126 112 84 112 ?What is the mean absolute deviation 14-O 16.8 2.8- 116.2Give typing answer with explanation and conclusion Suppose that the government must undertake an irreversible policy decision regarding the extent of air pollution regulation. The government is making this decision in a situation of uncertainty, however. In particular, there is some probability p that the benefits will remain the same as they are this year for all future years, but there is some probability 1 - p that benefits will be less in all future years. If we take into consideration the multiperiod aspects, should we err on the side of overregulation or underregulation, compared to what we would do in a single-period choice?
- Please no written by hand solution Kate recently invested in real estate with the intention of selling the property one year from today. She has modeled the returns on that investment based on three economic scenarios. She believes that if the economy stays healthy, then her investment will generate a 30 percent return. However, if the economy softens, as predicted, the return will be 10 percent, while the return will be -25 percent if the economy slips into a recession. If the probabilities of the healthy, soft, and recessionary states are 0.6, 0.2, and 0.2, respectively, then what are the expected return and the standard deviation of the return on Kate❝s investment? Calculate the coefficient of variation for this investment. (Round expected return to 3 decimal places, e.g. 0.125 and round intermediate calculations and standard deviation to 5 decimal places, e.g. 0.07680.)Suppose X is a random variable with possible values -2,3 and 1 and with respective probabilities 0.22, 0.35, and 0.43 then the mean and standard deviation of X, respectively, are: of a. 1.04 and 1.838 O b. 1.04 and 1.876 O c. 0.667 and 1.876 d. 1.04 and 0.3733 O e. 0.667 and 0.3733probability and random variable Haider Ali AL-Saidi EXomfle CH-o): let X aned Y are C.g.Vs with joint →くれく4 →にすFiting a straight ine to a set of data yields the following predicion line. Complete (a) through (e) below a. Interpret the meaning of the Yintercept, Choose the correct anower below O A. The Yintercept, be =4, imples that the average value of Yis 4. OB. The Yintercept, b7, implies that when the value of Xs0, the mean value of Yis 7 OC. The Yantercept, by4, implies that tor each increase of 1 unt in X, the value ofYa expected to increase by 4 unts •D. The Yintercept, 4, implies that when the value of Xis 0, the mean value of Y is 4 b. Interpret the meaning of the slope, b Choose the comect answer below OA The slope, by4, implies that for each increase of 1 unit in X, the value of Yis expected to increase by 4 units OB. The slope, by =7, implies that the average value of Y is 7. O C. The slope, b,=7, imples that for each increase of 1 unit in X, the value of Y is expected to increase by 7 units %3D OD. The slope, b,7, implies that for each increase of 1 unit in X, the value of Yis…Economics MY NOTES ASK YOUR TEACHER DETAILS ASWESBE9 8.TB.1.021. 0/1 Submissions Used In order to estimate the average electric usage per manth, a sample of 121 houses was selected and the electric usage was determined. Assume a population standard deviation of 330 Vilnwatt-hours. Find the standard error of the mean. O30 O 121 O 30The 2018 statistics shows that the average life expectancy of females in Canada has risen to 83.9 years. Assuming the standard 1 deviation of their life expectancy was 7.4 yoars, determine the minimum percentage of females in Canada whose life expectancy was between 75.02 and 92.78 years. Type your numerical answer here. Numbers onlySEE MORE QUESTIONS