3. Write the remove_evens() function that receives a list of integers as a parameter and returns a new list of integers containing only the odd numbers from the original list. Ex1) If n = [1, 2, 3, 4, 5, 6], remove_evens(n) returns [1, 3, 5]. Ex2) If n = [2, 4, 8], remove_evens(n) returns [].
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- Write a function called remove_odd that takes a list of numbers that have both even and odd numbers mixed.# Function should remove all the odd numbers and return a compact list which only contains the even numbers. Example1: Function Call:remove_odd ([21, 33, 44, 66, 11, 1, 88, 45, 10, 9])Output:[44, 66, 88, 10]5. The following function indexCounter aims to find and return all the indices of the element x in a list L. if x is not in the list L, return an empty list. However, the implementation has a flaw, so that many times it will return error message. Can you fix the flaw? def indexCounter(L, x): indexList [] startIndex = 0 while startIndex < len(L): indexList.append (L.index (x, startIndex)) startIndex = L.index (x, startIndex) + 1 return indexListImplement the following function def maxValue(alist: list)->int. alist contains integers only. This function finds and returns the largest numbr in the list. for example, alList-(1,5, 2), calling maxValue(alist) should return 5. Because 5 is the largest number in the list.
- Write a function called `filler(A, l)` that takes an integer `A`, and a list of integers `l` and if some of the numbers in `l` sum up to `A` then it returns a list of these numbers. Otherwise, it returns `None`. For example, filler(5, [1,6,3,4]) returns [1,4]. filler(5, [1,6,3,7]) returns None. filler(0, [-1,-1,2,-3]) returns [-1,-1,2]. filler(10, [2,3,2,3,1]) returns [2,3,2,3]. If there are multiple answers, then return any of them. You can use each number in the list once for each occurence. """ def filler(A, l): # remove the following line to solve this question returnRun the code below to call the function # In[ ]: otherList = [395,2,-4,20,47,200,-50,-12] #a list for testing print ('Before sorting:', otherList) bubbleSort (otherList) print ('After sorting:', otherList) a) What are the contents of otherList after a single iteration of the outer loop of 'bubbleSort? b) How many iterations of the outer loop happen when sorting `otherList? * Then run both blocks of code (the def block and the test block) again. * Examine the output to answer the question about iterations. Create a new list below with * elements known as "yourList" - a list where you can get 'bubbleSort` to stop early (do fewer iterations). How many times did the outer loop run for 'yourList? # In[ ]: yourList = [] #fill in this list with 8 elements separated by commas print ('Before sorting:', yourList) bubbleSort (yourList) print ('After sorting:', yourList)2. listAverage() returns the average number in a list. Which of these functions does this correctly? O A. function listAverage (1ist) ( var sum - for ( var 8 0: 0< list length sum- sum + 1ist A return sum / ist.length O B. tunction listAverage (list){ var sum for( var 8 0: Ise. 1ength sum sum + Ist O return sum / 1ist length . function listAverage (list) ( var sum= return sum / HElength) for ( var 0 0Define the function (siftNum lst). This function should resolve to all the numbers in the list, lst. For example: (siftNum '(a 8 2 1 m l 90 p 2)) resolves to '(8 2 1 1 90 2).Exercise G -- Implement a function halves that takes a list of integers and divides each element of the list by two (using the integer division operator //) NOTE use the map function combined with a lambda expression to do the division with a neat solution halves : List Int -> List Int halves xs = [ ] --remove this line and implement your halves function herePython question ocreate a function that takes a list of integers and an integer as 2arguments. The integer will represent an index point.o This function needs to add the sum of all the numbers in the listup until and including the given index point by making use ofrecursion and no loops.Examples of input and output:adding_up_to([1, 4, 5, 3, 12, 16], 4)=> 25=> adding the number all the way up to index 4 (1 + 4 + 5 + 3 + 12)adding_up_to([4, 3, 1, 5], 1)=> 7=> adding the number all the way up to index 1 (4 + 3) NB can you please add comments so I can follow alongdef remove_occurences[T](xs:List[T], elem: T, n:Int) : List[A] = {} Using the function above, can you show me how to make a polymorphic function in scala where the program removes elem , n number of times from the list. If n > elem then remove all elem from the list For example: remove_occurences(List(4,5,6,7,4),4,1) -> List(5,6,7,4)remove_occurences(List(4,5,6,7,4),4,2) -> List(5,6,7)remove_occurences(List(4,5,6,7,4),2,2) -> List(4,5,6,7,4)Write a function reverse_iter_for that takes a list and returns a new list that is the reverse of the original using a for loop. You should not need any indexing notation. def reverse_iter_for(lst): """Returns the reverse of the given list. >>> reverse_iter_for([1, 2, 3, 4]) [4, 3, 2, 1] TELEEL "*** YOUR CODE HERE ***" Complete the function reverse_iter_while that behaves identically to reverse_iter_for but is implemented as using a while loop. You may use indexing or slicing notation. Do not use 1st [::-1] ! def reverse_iter_while(lst): """Returns the reverse of the given list. >>> reverse_iter_while([1, 2, 3, 4]) [4, 3, 2, 1] rev_lst, i = [], 0 while i < len(lst): "*** YOUR CODE HERE ***"1) Write a function dropLowest() with one parameter n.2) n is a list that contains any 5 random integers in the range (1,100) inclusive.3) The function should return the updated list which drops the lowest number in n.4) Call the function, dropLowest() with the argument n, n = [10, 44, 8, 78, 60].5) Print the result of the function call. Example Output (n is the argument)[10, 44, 78, 60] PYTHON PROGRAMMINGSEE MORE QUESTIONS