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- Figure (a) shows the cross section of a column that uses a structural shape known as W867 (wide-flange beam, nominally 8 in. deep, weighing 67 lb/ft). The American Institute of Steel Construction Structural Steel Handbook lists the following cross-sectional properties: A=19.7in.2,Ix=272in.4, and Iy=88.6in.4. Determine the dimensions of the rectangle in Fig. (b) that has the same Ix and Iy as a W867 section.Given that P=120lb and Q=130lb, find the rectangular representation of P+Q.2-28 Find the resultant of the force system shown in Figure P2-28. 50 N 40 N 52 N 12 34 N
- S00 Ib In the fig. shown, compute the ff: (16-18) the resultant using cosine law (force polygon) 60 R = 35 (19-20) the angle of the R measured 500 lb cW from the x- axis.The following diagram corresponds to questions 1 to 3. A beam rests on two sharp edges as shown on the image. The beam has a length of 7,50 m and a mass of 4,25 kg. Object 1 has a mass of 1,50 kg; object 2 has a mass of 2,35 kg. Point P is 0,50 m form the center of the beam. CG 1. How much is the torque done by object 1 around point P? A. 55,2 N*m B. 7,36 N*m C. 62,5 N*m D. Object 1 doesn't exert a torque. 2. How much is the torque done by the force of gravity of the beam around point P? A. 20,8 N*m N-m ך177 .B C. 156 N*m D. 313 N*m 3. If you needed to cancel the nomal forces of the two objects, where you should place object 2? The axis of rotation is point P. A. 3,30 m from point B. 9,18 m from point P C. 5,69 m from point P D. 3,62 m from point PThe following diagram corresponds to questions 1 to 3. A beam rests on two sharp edges as shown on the image. The beam has a length of 7,50 m and a mass of 4,25 kg. Object 1 has a mass of 1,50 kg; object 2 has a mass of 2,35 kg. Point P is 0,50 m form the center of the beam. d 2 Pl CG 1. How much is the torque done by object 1 around point P? A. 55,2 N*m B. 7,36 N*m С. 62,5 N*m D. Object 1 doesn't exert a torque.
- a = 1.2 m b = 1,8 m c = 4 m Force AB = 500 Newtons FAB Find the y-component of Force AB in N. If the calculated answer is not whole number, express it in 4 significant figures. If the value is negative, include a negative sign. Find the z-component of Force AB in N. Find the Projected Force to direction AC in N. (Hint: Dot Product).Find box for the given Plane, where by =120m, d=25m, bz=25m, d2=100m, b3=80m & d3=25 m (Enter only the values in the boxes by referring the unit given in brackets. Also upload your hand written answers in the link provided) b2 dz di bị The value of X= (unit in m) The value of Y= (unit in m) The moment of inertia for sec 1 = lyyi = (unit in m) The moment of inertia for sec 2 = lyy2 = (unit in m4) The moment of inertia for sec 3 = lyya = (unit in m4) The moment of inertia of the given plate = lyy = (unit in m)Problems 5-117 through 5-122 Figures P5-117 through P5–122 show completed bending moment diagrams for beams. Develop the shearing force dia- gram and the loading diagram for each beam
- Using the Cartesian components (rectangular components), determine the resultant of the force vectors answering the magnitude in the space provided below and the direction in the procedure document. Only handwritten Draw to approximate scale the sum-of-forces polygon showing the original vectors and the resultant. In a separate document show the entire work. F = 252lbs, F₂ = 130lbs, a = 65° F3 = 55lbs, m = 6.2, and n = 8.6Question #3: In the figure below, a 100 N weight flower pot is suspended by three ropes. The tension in rope AB is three times the tension in ropes AC and AD. Find the dimension “d” on the figure which corresponds to the z-coordinate of point B. Also find the tensions in ropes AB, AC, and AD. Please do each step as I am trying to check my answers. I got to the point of setting the ijk components equal to zero. I'm stuck at multiplying the tension in vector AB times 3.In Figure, find the magnitude of Qopa if you know that the resultant of the three forces is a vertical force, and it is equal to 620N downward. A F=500N sol/ p=357.8N Q=240N To the left