4. ARM Data Addressing. Suppose r0-0x8000, and the memory layout is as follows Address Data 0x8000 0x1A 0x8001 0x2E 0x8002 0x2B 0x8003 OxOD 0x8004 0xFC 0x8005 0xA3 0x8006 0xCD 0x8007 0xE9 ii. ARM processors can be configured as big-endianness or little-endianness. What is the value of rl after running LDR r1, [ro]? (2) a. b. If little-endianness, r1 = If big-endianness, rl= Suppose the system is based on little-endianness. What are the values of r1 and r0 if these instructions are executed separately? (3) LDR r1,[r0,#4] r0= rl= LDR r1,[r0],#4 r0= rl= LDR r1,[r0,#4]! r0= rl =
4. ARM Data Addressing. Suppose r0-0x8000, and the memory layout is as follows Address Data 0x8000 0x1A 0x8001 0x2E 0x8002 0x2B 0x8003 OxOD 0x8004 0xFC 0x8005 0xA3 0x8006 0xCD 0x8007 0xE9 ii. ARM processors can be configured as big-endianness or little-endianness. What is the value of rl after running LDR r1, [ro]? (2) a. b. If little-endianness, r1 = If big-endianness, rl= Suppose the system is based on little-endianness. What are the values of r1 and r0 if these instructions are executed separately? (3) LDR r1,[r0,#4] r0= rl= LDR r1,[r0],#4 r0= rl= LDR r1,[r0,#4]! r0= rl =
Chapter22: Sequence Control
Section: Chapter Questions
Problem 6SQ: Draw a symbol for a solid-state logic element AND.
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