4. Consider the following piece of pseudocode: new DynamicArray d d[1] ← 1 for 2 ≤ i ≤ 4 do d[i] ix (i − 1) - end for x ←d[4]
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- Homework -4 1- Implement the following function by : Type 1 MUX ( D partitioned variable) Type 2 MUX (C,D) are partitioned variables • Type 3 MUX (B,C,D) are partitioned variables F(A,B,C,D)={m(4,5,6,7,10,14) 2- Implement the following function by: Type 1 MUX (D) partitioned variable • Type 1 MUX (C) partitioned variable (8X1) MUX's • (4X1) MUX's F(A,B,C,D)=_m(0,1,5,6,8,9,12,13)+d(3,11)MPI Programming: Write a MPI program in C/C++ to multiply two n-by-n matrices using p processors organized ina ring network with 1 ≤ p ≤ 12. Use the algorithm laid out here: P0 will generate and send ith row-band of Aand ith row-band of BT (the transpose of matrix B) to Pi, 1 ≤ i ≤ p − 1 (thus, space allocated should only be toaccommodate row-bands of A, BT and C). To compute their row-bands of product matrix C, the processors willuse p steps of computation (multiplying row-bands of A and BT producing a block of row-band of C) and (p-1)steps of communication (sending the row-band of BT to the right neighbor and receiving from the left neighbor).You must only use send/receive primitives. P0 finally receives the ith row-bands of product matrix C from Pi,1 ≤ i ≤ p − 1, and prints it out.31. Let f(x) = [x2/3]. Find f(S) if a) S = {-2, –1, 0, 1, 2, 3}.
- Write a program / Algorithm to find intersection of two sets in O(n).void setA_Intersection_setB (int setA[], int counterA, int setB[], int counterB) (Dont use pointers, C++)Write the implementations of functionscopy1 and copy2 for copying strings. copy1 uses array index notation. copy2 uses Pointers andPointer Arithmetic.#include <stdio.h>#define SIZE 10void copy1(char* s1, const char* s2); // prototypevoid copy2(char* s1, const char* s2); // prototypeint main(void){char string1[SIZE]; // create array string1char *string2 = "Hello"; // create a pointer to a stringcopy1(string1, string2);printf("string1 = %s\n", string1);char string3[SIZE]; // create array string3char string4[] = "Good Bye"; // create an array containing a stringcopy2(string3, string4);printf("string3 = %s\n", string3);}void copy1(char* s1, const char* s2){//Implement copying string using array index notation}void copy2(char* s1, const char* s2){//Implement copying string using Pointers and Pointer Arithmetic }Write in C Language Description A sparse matrix is a matrix in which most of the elements are zero. Representing a sparse matrix by a 2D array leads to wastage of lots of memory as zeroes in the matrix are of no use in most of the cases. So, we can compress the sparse matrix by only store non-zero elements. This means storing non-zero elements with triples- (Row, Column, value). 0 0 0 0 0 0 0 3 0 0 0 0 0 0 0 6 0 0 0 0 9 0 0 0 0 0 0 0 12 0 Here is a 5X6 matrix, there are 4 element non-zero, we using three number represent it 5 6 4 After the three number are (Row, Column, value): row col val 1 1 3 2 3 6 3 2 9 4 4 12 Write a program to read the compressed matrix and print out the original matrix. Input First line consists 3 integers. First and second integers shows the dimensions of original matrix. Third integer k shows number of non-zero elements. Followed k lines are content of the sparse matrix. Each line consists 3 integers, row number, column number, and data. Output Output…
- Write in C Language Description A sparse matrix is a matrix in which most of the elements are zero. Representing a sparse matrix by a 2D array leads to wastage of lots of memory as zeroes in the matrix are of no use in most of the cases. So, we can compress the sparse matrix by only store non-zero elements. This means storing non-zero elements with triples- (Row, Column, value). 0 0 0 0 0 0 0 3 0 0 0 0 0 0 0 6 0 0 0 0 9 0 0 0 0 0 0 0 12 0 Here is a 5X6 matrix, there are 4 element non-zero, we using three number represent it 5 6 4 After the three number are (Row, Column, value): row col val 1 1 3 2 3 6 3 2 9 4 4 12 Write a program to read the compressed matrix and print out the original matrix. Input First line consists 3 integers. First and second integers shows the dimensions of original matrix. Third integer k shows number of non-zero elements. Followed k lines are content of the sparse matrix. Each line consists 3 integers, row number, column number, and data. Output Output…For the following C++ code find and write the recurrence relation. You need to model the runtime of function "Func" in terms of n. (only the recurrence relation in terms of n, No output of the code or final runtime analysis is required) s= array L[] start index e= array L[] end index void Func(int L[], int s, int e) { if (s < e) { i=s-1; for (int j = s; j <= e - 1; j++) { if (A[j] <= x) { i++; swap (&L[i], &L[j]); } } swap (&L[i + 1], &L[e]); int k = i+1; Func(L, s, k - 1); Func(L, k + 1, e); } } Please explain how you get the relation Thank you!Introduction For this assignment, you are to write a program which implements a Sorted List data structure using a circular array-based implementation and a driver program that will test this implementation. The Sorted List ADT is a linear collection of data in which all elements are stored in sorted order. Your implementation has to store a single int value as each element of the list and support the following operations: 1. add(x) – adds the integer x to the list. The resulting list should remain sorted in increasing order. The time complexity of this operation should be 0(N), where N is the size of the list. 2. removefirst() - deletes the first integer from the list and returns its value. The remaining list should remain sorted. Time complexity of this operation should be 0(1). 3. removelast() – deletes the last integer from the list and returns its value. The remaining list should remain sorted. Time complexity of this operation should be 0(1). 4. exists(x) – returns true if the…
- Write below the kinked polygon function. def kink_polygon(poly): # YOUR CODE HERE [41] # You can use this space to debug your code. # YOUR CODE HERE Let us check that the solution works as intended. [42] poly1 = [(0, 0), (1, 2), (2, 0)] poly2 = kink polygon(poly1) draw_polygon(*poly2) IndexError Traceback (most recent call lasplease convert the code to C language // C++ program to find minimum deletion // to make all elements same#include <bits/stdc++.h>using namespace std; int minimum_no_of_deletion(vector<int> arr, int n){ //create a hash table where for each key //the hash function is h(x)=x //we will use stl map as hash table and //will keep frequencies stored //so say two keys are mapping to the same location, //then the location will have value 2 //instead of the keys itself map<int, int> hash; for (auto i : arr) { //for each number hash[i]++; } //now to make all elements same //we need to keep only the keys with //maximum frequency //we need to delete the other keys //so find the key with max frequency int maxfreq = 0; for (auto it = hash.begin(); it != hash.end(); it++) { if (it->second > maxfreq) { maxfreq = it->second; } } //so we need to dlete rest of //the elements…Please convert the code to C language // C++ program to find minimum deletion // to make all elements same#include <bits/stdc++.h>using namespace std; int minimum_no_of_deletion(vector<int> arr, int n){ //create a hash table where for each key //the hash function is h(x)=x //we will use stl map as hash table and //will keep frequencies stored //so say two keys are mapping to the same location, //then the location will have value 2 //instead of the keys itself map<int, int> hash; for (auto i : arr) { //for each number hash[i]++; } //now to make all elements same //we need to keep only the keys with //maximum frequency //we need to delete the other keys //so find the key with max frequency int maxfreq = 0; for (auto it = hash.begin(); it != hash.end(); it++) { if (it->second > maxfreq) { maxfreq = it->second; } } //so we need to dlete rest of //the elements…