4. Convert the following infix expression into postfix ones: i. (A + B) * (D / E) ii. (A+B^D)/(D-F) + G ii. A* (B+ D)/ E-F* (G + H/ K)
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- Solve the postfix expressions using appropriate data structures. 1. 456-*4/5 +1. Transform the postfix expression to infix form. Show ALL the steps. a) A B * C D E / - + b) A B - C + D E F - + * c) A B C D E - + / * E F * -PaoBLEM# 39 I Simplify the following expressions using Boolean algebra. Cite the laws and therorems used. • AB + A(CD + CD') • (BC' + A'D) (AB' + CD')
- 6. Find the errors from the following code. a. T=[a,b,c] printlh (T) b. for i in 1 to 100 : print (1) c. i=10 while [ib) print (a): else if (a6.Coding-----""Euler's totient function, also known as phi-function ϕ(n),counts the number of integers between 1 and n inclusive,which are coprime to n.(Two numbers are coprime if their greatest common divisor (GCD) equals 1)."""def euler_totient(n): """Euler's totient function or Phi function. Time Complexity: O(sqrt(n)).""" result = n for i in range(2, int(n ** 0.5) + 1): if n % i == 0: while n % i == 0: n //= i./* Find the sub of numbers crom N to */ /* Equivalent C code function would bet FINDSUB (int N) int ( int sub 15T while (N 1-0) sub Sub N-N- return Subs(b) Consider the following arithmetic expression in postfix notation: Postfix expression: a bc - + de f -g/h + * - i. Write the equivalent infix expression and prefix expression for the above expression. ii. Create an expression tree for the above expression.4. Using bitwise operators In C code Write a function int negate(int n) that can negate an integer without using the - operator.2. Write a recurrence relation describing the worst case running time of each of the following algorithms and determine the asymptotic complexity of the function defined by the recurrence relation. Justify your solution. You may not use the Master Theorem as justification of your answer. Simplify and express your answer as (nk) or (nk log₂ n) whenever possible. If the algorithm is exponential just give exponential lower bounds. a) function func(A,n) if n ≤ 5 then return A(1) else for i=1 to n for j = i to n-1 A(j) A(j) + A(i) + 3 /* endfor */ /* endfor */ wwwwwwwwww y ← func(A, n-6) return (y)SEE MORE QUESTIONS