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4. Formic acid, HFor, has a K, value equal to about 1.8 × 10¬4. A student is asked to prepare a buffer having a pH of 3.55 from a solution of formic acid and a solution of sodium formate having the same molarity. How many milliliters of the NaFor solution should she add to 20. mL of the HFor solution to make the buffer? (See discussion of buffers.) pHa pka +10g ( conjugate base) (aud) 3.55= 3.744 + log (0.02 -4 ka =18x10 pH= 355 Pkq= -log ka = -log ( 1.0 x104) 0.6397= = 3,744 V= 0.0312 L V= 31.2 mL 31.2 mL How many mL of 0.10 M NAOH should the student add to 20 mL 0.10 M HFO if she wished to prepare a buffer with a pH of 3.55, the same as in Problem 4?

4. Formic acid, HFor, has a K, value equal to about 1.8 × 10¬4. A student is asked to prepare a buffer having a pH of 3.55 from a solution of formic acid and a solution of sodium formate having the same molarity. How many milliliters of the NaFor solution should she add to 20. mL of the HFor solution to make the buffer? (See discussion of buffers.) pHa pka +10g ( conjugate base) (aud) 3.55= 3.744 + log (0.02 -4 ka =18x10 pH= 355 Pkq= -log ka = -log ( 1.0 x104) 0.6397= = 3,744 V= 0.0312 L V= 31.2 mL 31.2 mL How many mL of 0.10 M NAOH should the student add to 20 mL 0.10 M HFO if she wished to prepare a buffer with a pH of 3.55, the same as in Problem 4?

General Chemistry - Standalone book (MindTap Course List)
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter16: Acid-base Equilibria
Section: Chapter Questions
Problem 16.149QP: A solution of weak base is titrated to the equivalence point with a strong acid. Which one of the...
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4. Formic acid, HFor, has a K, value equal to about 1.8 × 10-4. A student is asked to prepare a buffer having a pH of 3.55 from a solution of formic acid and a solution of sodium formate having the same molarity. How many milliliters of the NaFor solution should she add to 20. mL of the HFO solution to make the buffer? (See discussion of buffers.) -4 ka =18x10 pH= 355 pHs pka +1og ( conjugate base) (aud) 3.55= 3.744 + log () Pka= -logka = -log ( 1.0x104) =D 3.744 0.6397=/0.02 V= 0.0312 L V: 31.2 mL 31.2 mL 5. How many mL of 0.10 M NAOH should the student add to 20 mL 0.10 M HFor if she wished to prepare a buffer with a pH of 3.55, the same as in Problem 4? Ka= mL
Transcribed Image Text:4. Formic acid, HFor, has a K, value equal to about 1.8 × 10-4. A student is asked to prepare a buffer having a pH of 3.55 from a solution of formic acid and a solution of sodium formate having the same molarity. How many milliliters of the NaFor solution should she add to 20. mL of the HFO solution to make the buffer? (See discussion of buffers.) -4 ka =18x10 pH= 355 pHs pka +1og ( conjugate base) (aud) 3.55= 3.744 + log () Pka= -logka = -log ( 1.0x104) =D 3.744 0.6397=/0.02 V= 0.0312 L V: 31.2 mL 31.2 mL 5. How many mL of 0.10 M NAOH should the student add to 20 mL 0.10 M HFor if she wished to prepare a buffer with a pH of 3.55, the same as in Problem 4? Ka= mL
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