4. Given that P = YWZ lb and Q = ZYX lb. Determine the resultant of the two forces. K 12 5 Q x
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Given that P = 980 lb and Q = 79 lb. Determine the resultant of the two forces.
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- Take P= 560 lb. (Figure 1) gure y E 4 ft X P 2 ft D B 2 ft 1 of 1 1 ft 3 ft Part A Determine the horizontal and vertical components of force that the pin at B exert on member ABD of the frame. Express your answer in pounds to three significant figures. Enter your answer separated by a comma. 197| ΑΣΦ 41 | vec B₂, By = Submit Part B Dz. Dy = Submit Request Answer Provide Feedback Determine the horizontal and vertical components of force that the pin at D exert on member ABD of the frame. Express your answer in pounds to three significant figures. Enter your answer separated by a comma. [V—| ΑΣΦ | ↓↑ vec www Request Answer ? lb ? lb13-1. The 6-lb particle is subjected to its weight and forces F₁ = {2i+ 6j 2tk} lb, F₂ = the action of {t²i – 4tj – 1k} lb,_and_F3 = {−2ti} lb, where is in seconds. Determine the distance the ball is from the origin 2 s after being released from rest. X F3 Z F₁ yTake P= 560 lb. (Figure 1) gure y E 4 ft X P 2 ft D B 2 ft 1 of 1 1 ft 3 ft Part A Determine the horizontal and vertical components of force that the pin at B exert on member ABD of the frame. Express your answer in pounds to three significant figures. Enter your answer separated by a comma. 197| ΑΣΦ 41 | vec Bz, By = Submit Part B Dz. Dy = Submit Request Answer Provide Feedback Determine the horizontal and vertical components of force that the pin at D exert on member ABD of the frame. Express your answer in pounds to three significant figures. Enter your answer separated by a comma. [V—| ΑΣΦ | ↓↑ vec www Request Answer ? lb ? lb
- The bar AB is attached to aluminum and steel rods, horizontal before the load P is applied. Find the displacement of aluminum rod caused by the force P = 55.25kN. ALUMINUM L=4.25m A = 556mm2 E = 70GPA STEEL L= 3.25m A = 354mm2 E= 200GPA 3.56m 2.64m5. A rigid bar AB, 9 m long is suspended by two vertical rods at its end A and B and hangs in a horizontal position by its own weight. The rod at A is brass, length 3m, cross-sectional area is 1000 mm? and E̟ =1×10°N/ mm? . The rod at B is steel, length 5 m , cross-sectional area is 445 mm?. At what distance 'd' from A may a vertical load P=300ON be applied if the bar is to remain horizontal even after the load is applied? ve stred Steel 5m Brass 3m P = 3000N B 9müz a aplanmadı ) üzerinden etlenmiş y ioruyu etle Н V The internal shear force V at a certain section of a beam is 60 kN.m. If the beam has a cross-section shown in the figure where h=243 mm, a=112 mm, b=182 mm, c=10,8 mm and t=14,7 mm, Determine the first moment of area (Q) for the point H (mm) where L=48,2 mm.
- A bar AE is in equilibrium under the action of the five forces shown. Determine P (kN). F1 = 82 kN F2 = 42 kN *type the numerical value in two (2) decimal places only without the unit 5m E F1 /sm Sm F2 5m A *type the numerical value in two (2) decimal places only without the unit (ADD " - " FOR DOWNWARD/LEFT DIRECTION. OTHERWISE, TYPE THE ANSWER AS IS.)Determine the force in each member of the loaded truss. The force is positive if in tension, negative if in compression. T 5m Answers: AB= Mi AC = BC = i -664 630. Mi 210. 15 m B 210 kg N Z Z Z N N2. Given the equations from Joint B Solve for the force in BD and BE. 600 lb 600 lb 600 lb 600 lb BD D 300 lb B. F 2 ft 4 in. 300 lb| 6 ft 1500 lb ВЕ E G H. 8 ft 8 ft→-8 ft→-8 ft 8. BD 8. ΣΕ-0= 1500| 8. BE 10 10 6. = 0 =1500 10 1, 600 – BD 8 6. + BE 10 3. Solve for x and y. 1200 lb 30°
- A. The resultant of the four belt tensions and couple C is force R acting through points O. 1. What is the value of R? 2. What is the value of C? 1000 N 30 mm 200 N 400 NProblem 01. (A-ODD) Given P1 = 40 Ibs and P2 = 100 lbs. (Use negative sign to indicate a direction of going down and going to the left.) 15 129 a. Determine the resultant of the two forces. b. Determine the components of the resultant along x axis. C. Determine the components of the resultant along y axis.A beam is subjected to a linearly distributed downward load and rests on two wide supports BC and DE, that exert uniformly distributed upward loads as shown. Determine the values of wec and WDE corresponding to equilibrium when WA = 750 N/m. 1200 N/m 20 C WBC ADA A 0.6 m- B' 0.8 m The value of WDE is The value of wBc is [ -3.1 ms -6 m- N/m. N/m. D (DE 1.0m E F