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- A l.00ml aliquot of flsh ol was andyud for N using the Kieldahl methad : Afler chqastim, the dishlled ammania collected in l0omlof 0:0503M HCl. The excess HCl required 28.3 ml of o.124M NgoH for titatiun.Cale, the amound ot Nin the somple of fish oil as mglml4.5 gm of oxalic auid/ foOH ) COUH presentin soomlor foletion. Therm Normalilay is ( Hint: COOH → C0 A) 0.1 B) 0-L C) 0.3 D) O. gPlease help me solve this experience İSÜ ÜNİVERSİTESİ EITANEUL Ausaclore for 20mh. problen then myghi be in the elam. IASide + How wsh ld you fiepue 40ml of a tš mo M, Nacl Bolution. from a 5.0M Chack -su.02-'the AOw. maoy grans of Nicl is veguicad to prepet 250ml of 3 molac How Borik Acid- Tris Big buffer ponader. sy we pat S4.028 Nacl Sulutiun ? after this 3 mokr esoml, Nacl solution Was * How may ml of 8 moker Nach Sulupion Should de taken if it is describe dilute this solution to a fotal Volume of 2 molar 400m18 glepened Sooml of dishilled bater,
- Write the expression for the K of H2PO;. HPO OH %3D [H2PO;] [HPO H,0*] %3D [H2 PO,] [H3 PO3[H3O*] [H2PO;] K= [H3 PO3][OH] OK= %3D [H, POA l.00ml alıquot of fish od was andyud for N using the kieldahl methad: After chqashim, the dishilled ammania colleeted in 10onlof 0:0503 M Hl. The excess Hl requied 28.3 ml of o.124M NgoH for titratin. amount Cale the ofN in the sconle of fish oil as mglm KJE LDAHL METHOD)E 50 um? of 6-2 moldni3 Solution Na, (o3 was dileted usith distilled weeter to obtain f 250 cm3 Sorlution, what world be the Con ien trei blum f Sbuution? the resulbing of
- gascous ammonia, NH3lA) at reacts 3)/A 3.83L Volume of SIP is bubbled through lo8.0mb Water and Completley to form. R. aummonium hydroxide, NH40H (ag) a) what is the mdar concentration ot the resulding NHOH(aa) solkubion. 16) Whal mass of NH4 OH is present in the loo: Ome Solution. How moles of NHq OH would be sprasera present many în 482 mL ofa solution of he the Same IConcentration.K/s 9:06 hw.pdf > Hw () Determine the melarity of e-ch of the folloning 2.25 kg of Cusoy in 1.45 Lof solusion O,006 mol. of Br, in lo mL of soleie O. s 0075 gm of C HHs Noz i n 1.osmL of solution Hint. The atomic numbers used in the above Problem ave O = 16 Cu: 29 Br: 35 K = 19 CI - 7 S: 16 Al: 13 N = 7How many grams of Anilin GHS NH2 Should be Solved in water to Prefare I liter containg oH iong Know that Kb CAnilWhe)=4*/0 a Solution of with -6 2* 10 -10
- 2 N, Og g) - 2. The istandaed gibbs yece enetgy chenge KT/mot Change $2 thins čcaction is -29.0 what is the value ef gibis eee ehetg 350 K when %3D 0-602. M, [No, ] %3D O. 021Expeniment and name Chemical formula Cobalt (11) nitzate Co(NOs)2 Buldatance Aane and dhemical farmula mm, q/mo! 182.95g lmol Fruihal volume , L Iniial concentrahion measure d, mal/L Number of mole's and massof mass Of solute 500ML 0.876 mollL 0 -438 mol Colw0z to Concentration after eventahom affer evapo 1.461 mal L Can you please explatn to calculate how the 180.19) cduo wsas arrived at ? Thanks asswhat is the molaity of a 0.350 L solution mole by albing a4.9 a Nagoa to suffecint wote? b.) 0.350M W SLIC (0 w cC'I (*p