42 in64 [in]-50 inD59 inBی به سوالات فهد اما او شده وام بانک سامانه63 in-10 in21 inGiven: The plate( The shaded rectangular volume) has weighs 240 lbf.It is. suspended bycable CD, Which D is wall anchor.So, Find the magnitude of force in the cable CD such the system is in static equilibrium??.Show all works.

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Answered: 42 in X 64 [in]- 50 in D 59 in B 63 in…

Engineering

Mechanical Engineering

42 in X 64 [in]- 50 in D 59 in B 63 in -10 in 21 in y

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter1: Introduction To Statics

Section: Chapter Questions

Problem 1.31P: Resolve the 360-lb force into components along the cables AB and AC. Use =60 and =40.

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Resolve the 360-lb force into components along the cables AB and AC. Use =60 and =40.
42 in 64 [in]- 50 in D 59 in B این دو سال است اند اما او شده از این سامانه 63 in -10 in 21 in ( Given: The plate( The shaded rectangular volume) has weighs 240 lbf. It is. suspended bycable CD, Which D is wall anchor. So, Find the magnitude of force in the cable CD such the system is in static equilibrium??. Show all works.
The figure shows a mechanical model of the Russel fracture traction device and the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The total weight of the leg and the cast is W=200 N. The horizontal distance between points A and B where the cables are attached to the leg is L=100 cm and the vertical distance is d=10 cm . Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A ( 3L/4= 75 cm) . The angle that cable 2 makes with the horizontal is measured as β=40 ° . Accordingly, in order for the leg to remain in balance in the position shown; a) Find the tensile force T 1 in cable 1 . (Write your result in N ) b) Find the tensile force T 2 in cable 2 . (Write your result in N ) c) Find the angle α of cable 1 with the horizontal
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The figure shows the Russel fracture traction device and a mechanical model of the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The combined weight of the leg and cast is W=180 N. The horizontal distance between points A and B where the cables are attached to the leg is L=100 cm and the vertical distance is d=5 cm. Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A (3L/4= 75 cm). The angle that cable 2 makes with the horizontal is measured as β=30°. Accordingly, in order for the leg to remain in balance in the shown position; a) Find the tensile force T1 in cable 1. (Write your result in N) Answerb) Find the tensile force T2 in cable 2. (Write your result in N) Answerc) Find the angle α of cable 1 with the horizontal. Response
#1-A rod 15oom Cong Matates in a horizmtal plane about a vertical axis thru its center. At ench end f the rod is fastened a' cord o.800m long Each cord kupports a weight W. Find the Epeed f hotation 'n' to ircline each rpm cord at 32° th the verfical. #2 Given: W= 250 N Regis : aー 6-T L-0-800m C- time for | rev.
The figure shows the Russel fracture traction device and a mechanical model of the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The combined weight of the leg and the cast is W=210 N. The horizontal distance between points A and B where the cables are attached to the leg is L=100 cm and the vertical distance is d=6 cm. Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A (3L/4= 75 cm). The angle that cable 2 makes with the horizontal is measured as β=33°. Accordingly, in order for the leg to remain in balance in the shown position; a) Find the tensile force T1 in cable 1. (Write your result in N) b) Find the tensile force T2 in cable 2. (Write your result in N) c) Find the angle α of cable 1 with the horizontal.
The diameter of two pulleys are (0.3m)and (0.2m), center distance (1m).if we use open belt drive. Determine: 1- the length of V- belt (2ß = 60°). 2- the contact angle between belt and smaller pulley. 3- the horse power, if the smaller pulley turn with speed (400r.p.m) and the tension force in tight side (T1=90ON), coefficient of friction u=0.3 4- the speed of large pulley.
600 lb 2.5 ft 2.5 ft 2.5 t 2.5 ft E 1. The structure is: 2. The two-force member is: AB and CD v and its 3. Given that Fx +1000 Ib and Fy =+1000 Ib (Hint: take the moments at B), the magnitude of internal force FCD is: