5- A beam is reinforced with Ø16 mm bars and Ø10@200 mm stirrups. If the concrete cover is 40 mm, f, = 420 MPa and f' = 25MPA , then the development length of the 180° hooks of the reinforcing bars is ......mm. (a) 573 (b) 323 (c) 269 (d) 430 (e) None
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- A rectangular beam 250 mm wide, 500 mm deep is reinforced at the bottom with d-20-mm-dismeter bars and at the top with 2-16-mm bars. Concrete cover to bar centroid at the top is M0 mm and at the bottom is 70 mm. Use concrete strength r'e-21 MPa und steel yield strength fy 415 MPa for 20- mm bars and fy= 275 MPA for 16 mm bars Detenmine the design moment capacity n kN m of the beam in negative bending. A 40.06 O45.07 C. 42.70 D47.55The rectangular doubly reinforcement stress concrete block with the arrangement of reinforcement of 2N28 bars on top and 3N28 bars on bottom. The modulus of elasticity are Ec =23,500MPa and Es = 200,000MPa. Dead load is 18KN/m and live load is 12KN/m. f'c = 25MPa 800 730 N12 ligs (fx.t-500MPa) Ast = 3N28 350 Span = 10m Figure 3 Use the Transformed section approach considering the presence of steel. Calculate the concrete area and transformed steel area in both tension and compression shown in Figure 3. n=Es/Ec Ast=1232mm^2 Use n-1 for the transformed area to do the calculate. Unit: mm^2 with two decimalThe rectangular doubly reinforcement stress concrete block with the arrangement of reinforcement of 2N28 bars on top and 3N28 bars on bottom. The modulus of elasticity are Ec =23,500MPa and Es = 200,000MPa. Dead load is 18KN/m and live load is 12KN/m. f' = 25MPa 800 IDE 730 N12 ligs (fsv.f-500MPa) Ast = 3N28 350 Span = 10m Figure 3 Calculate the combination load for the reinforcement concrete beam shown in Figure 3. Unit: KN/m with two decimal. 1.2G+1.5Q=w
- 3. A reinforced rectangular concrete beam having a width of 300 mm, effective depth of500 mm, fc’ = 24 MPa, fy = 415 MPa, 4 - 28 mmɸ, d’ = 65 mm. Present the following (a) actual steel ratio (b) maximum steel ratio (c) a(d) c (e) check if steel yields (f) ?steel(g) type of failure (h) reduction factor (i) moment capacityQuestion 8 1 p The rectangular doubly reinforcement stress concrete block with the arrangement of reinforcement of 2N28 bars on top and 3N28 bars on bottom. The modulus of elasticity are Ec=23,500MPa and Es = 200,000MPa. Dead load is 18KN/m and live load is 12KN/m. f'c = 25MPa 800 TE 730 N12 ligs (fsv.t-500MPa) Ast = 3N28 350 Span = 10m Figure 3 Calculate the concrete stresses in tension and compression of the reinforcement concrete beam shown in Figure 3. Compression concrete stress Choose ] Tension Concrete stress Choose]a) For the rectangular section shown below the maximum allowable tensile stress in the concrete Fct = 3MPa. Assume an uncracked section and find the maximum moment the section can resist as well as the stress in the reinforcement for this moment Ec:= 30-GPa Es:= 200 GPa b:= 300 mm h := 520 mm d:= 460 mm 2 As 1470 mm := b As
- A beam cast monolithically has the following properties: bf=1200mm, t or hf = 110mm, bw=380mm and h=800mm. It is reinforced with 10D32mm grade 420MPa bars. Concrete strength is assumed to be 27.5MPa and the centroid of tension reinforcement is located 665mm from the outermost compression fiber. A. Determine maximum nominal moment to ensure tension controlled, kN-m. B. Calculate the balanced steel area, mm2. C. Calculate the balanced moment in kN-m.3 A concrete floor slab 100 mm thick is cast monolithic with concrete beams 2.0 m on centers. The beams have a span of 4.0 m, web width of 250 mm and overall depth of 500 mm. The tensile reinforcement consists of 6-∅20 mm bars in two rows with 25 mm vertical clear spacing. Use material strengths f’c = 21 MPa and fy = 415 MPa. Calculate the following considering a T-geometry: Effective flange width of an interior beam in mm = ? Depth of uniform stress block at ultimate stage in mm to the nearest whole number = ?? Tensile steel strain compatible with concrete strain of 0.003 in 3 decimal places = ?Assume Grade 50 steel and use f. = 5,000 psi for parts (a) thru (b). (a) u The beam below is subjected to a factored moment M₁ = 800 ft-k. Assuming that the reinforcement is to be placed in two layers as shown, design the reinforcement. (b) Calculate the moment strength oM₁ of your design in part (b) and compare that with the factored moment M₁ = 800 ft-k. Is your design adequate? Be sure to check the strain in the tension steel. A k 6" 4" 6" ....... 4" 12" 8" 4" 4"! 32"
- A W 305 x 87, 7.5m llong, is pinned at both ends and braced in the weak direction at the third points. Determine the available compressive strength. Properties: A = 10,965 mm² lx = 331.2x106 mm4 ly = 55.78x106 mm4 •• Please Show Solutions Steel Design: Civil Engineering Answersi Pn=Fer Ag= 274.61 (10965) 1000 Pn=3011.05 KNDetermine the maximu m allowable lo ad P that 1-90. can be safely supported by the frame if t= 30 m m an d 90 mm. The wood has a normal fa ilure stress of b = MPa, and a she ar failure stress o f Tfall Ofail 4 2 10.5 MP a. Use a factor of safety again st failure of 2. 75 mm 75 mm B 30O Find the ultimate moment of resistance for the rectangular section reinforced as shown below. material strengths: Concrete Reinforcement Width of section Reinforcement fcu:= 30-MPa fy:= 450-MPa b:= 280-mm d:= 510-mm A, 2410-mm d':= 50-mm A's:= 628-mm² b A', d'