5 kN P 60 40 20 Al diniensions in mm Fat

Q: 400 lb 30° Hk = 0.5 2017 1250 Ib 20' В

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Q: 20kN 10 m 45 A B 10 m-

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Q: 7ft Corce докл 66° 5.30 look 50 g 80° G 36 30 Yo >15 4ft 3ff for all member f 66 2ft ? E

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Q: 10 kN 8 kN 15 kN m 2 m 3 m kN - m 80 60 40 20 3 4 -20 -40 -60 -80 %24 2.

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Q: For the stress state shown. Ox = 40 MPa MPa Oy = 80 MPa Txy %3D 65 Oy Txy Using Mohr's Circle, a)…

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Q: 60 Ib 90 lb 30 45 150 lb

A: GIVEN DATA- A 150lb BOX GIVEN ACTED BY TWO FORCES WE HAVE TO FIND ACCELERATION OF IT

Q: kj/kg, ochange in eafrey ky/My k solve coorte

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Q: =o7 Cm) findSmax. tor Figure 0,7 Cm) fin mox. tor tigure tigure. 225 mm J0omm

A: Given Data The force acting in the downward direction is: F=400 N The height of the weld is: h=0.7…

Q: 50 KN 100 KN/m 60 KN/m 40 KN/in 10 KN.m 2.0 m 6.0 m 2.0 m 4.0 m

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Q: Draw the shear and bending moment diagrams for the beams in Figure 3.13, indicating all critical…

A: “Since you have asked multiple question, we will solve the first question for you. If youwant any…

Q: 0(1) 18 N-m-s/rad 1 N-m-s/rad T() 02(1) 3 kg-m2 00 9 N-m/rad 3 N-m/rad

A: For shaft -1 the equation of motion is: 56 + 1(6, – 02) + 9(6 – 02) = 0 For shaft -2 the equation of…

Q: 60 135 60 60 30 F (4 m, 4 m, -2 m)

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Q: 30 kN | 50 kN D A BA 1m - 3 m - 2 m

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Q: 15 kN 25 kN 20 kN C В D 1 m 0.8 m 0.3 m 30 kN °0.4 m

A: Q7.35 Given: Load at A (P2)=15kNLoad at C (P1)=25kNLoad at D P3=30kNLoad at E (P4)=20kN

Q: 3 4 6. 760°C 758°C Block insulation 727°C |Outside air Hot gasep 68.42°C 26.5°C 68.5°C 6.35cm 12.7cm…

A: Let K =Thermal conductivity of fire brick =1.13W/mK h =Heat transfer coefficient for the outside…

Q: W= 75 Ib W= 150 lb W= 75 Ib R.

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Q: a piece of alloy has a mearsure mass of 90 g in air and 85 g in oil s.g of 0.88. find its volume and…

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Q: 7kN m 5 kN/m |C B D = 3m to D/2 D/2 12KN

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Q: constant R EC is fixed. The 11 cm frc

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Q: 5) An infismall element is plven oO a plane, where J2 - 0. a 120uPa 120MPQ 8əula Modulus of…

A: Stress is defined as the internal resisting force per unit area. Strain is defined as the change in…

Q: 12KN 4 kN /m 12m 24 KN 12m 36m 一- 10

A: Dear student, we are suppose to solve only one question. Please post other question as a separate…

Q: 4.) The pressure gage reading is 70 kPa. Find the weight (kN) of the piston. 1mø Piston 1 m Ol S…

A: The pressure exerted by the fluid at a point which is located at a depth of h from the surface is…

Q: 3000 lb 90 Ib /ft 9 ft 200 lb/ft

A: For solution refer below images.

Q: R 20° 30° 80 lb 100 lb

A: FREE BODY DIAGRAM:

Q: 20 kN 40 kN 10 kN/m 1 m 2 m 2 m 2 m 1 m w

A: Before going through the calculation for shear force and bending moment calculation first, calculate…

Q: 15 KN 10 KN 10 KN 20 KN E A 5.0m

A: To determine the support reaction at J.

Q: norma Bulk Modulus is defined as the ratio of nor stress to.

A: Given data : Direct stress=σVolumetric strain=∆VV

Q: 15ON 50N 100N /m EI 8 midspan F2 6 12 El 8 over hang =

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Q: 20 bar with te angles 30° anc

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Q: A1 of 50 cm2 , P1 = 100 kF %3D steadv, one-di

A: Given  at inlet A1= 50 cm2 T1= 300 K V1=100 m/sec P1= 100 kPa A2= 40 cm2

Q: 100 kN/m 150 KN E (m) 5 7 10

A: "Since you have posted a question with multiple sub-parts, we will solve the first three sub-parts…

Q: F = 120 lb | 30° 12 kN 1.25"- 30 4 m 1.5" 5 m 11"

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Q: 120 kN 7.5 kN/m 417.5 kNm 282.5 kNm A C +5m→5 m 10 m - RA = 115.5 kN Rg = 79.5 kN

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Q: 2) Şekildeki dirseğin A mesnedindeki tepki kuvvetinin şiddetini bulunuz. 120 mm 60 JB 50 N m

A: Let RHA and RVA are the horizontal and vertical reactions at hinged point A respectively. RVB is the…

Q: 120 kN 7.5 kN/m 417.5 kNm 282.5 kNm A D 5 m 5 m 10 m- RA = 115.5 kN Rg = 79.5 kN

A: Shear force diagram represents shear force at every section of the beam. Shear force at any…

Q: RB 50KN bm 100 KN 4m B 4m

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Q: 7 ft 80kN 60° 588 B looks 50 g 80° You 36 38 Cs 66 4f+ 3 ft P₁) Find force for all member? 200KN 2ft…

A: To find: The forces for all the member. FBD: The free body diagram shown below:

Q: 10 N-m SN 45°. 50° F1 150 mm 30 E

A: Given Data :- F=8N AB= 450mm BC=325 mm and rest of data is in diagram.

Q: metal rod 0.4 m long & 0.04 m in diamet end at 273 K. Calculate the total amount ven K= 385.J/ms°C)

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Q: 10 KN/m 1a KN (m Ra 1.5 m 4m 3 m 1.5m

A: For solution refer below images.

Q: Determine stress Force=50 kg Cross sectional area =4 cm2

A: Given data : Force (F)=50 kgCross sectional area (A)= 4 cm2

Q: y 5 m 5 m A 5 m В 20 kN

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Q: Question 12 What is the resulting modulus of In (2 +3 j)?

A: To find: The resulting modulus of ln2+3j. Given: The complex function is ln2+3j. Formula used: The…

Q: F126KN 180KN 26 -3m 1.5m 48 65° 145KN V165 KN

A: Drawing the system of force as shown below – Let us take point A as an origin of the coordinate…

Q: The state of stress at a point under plane stress condition is Ox = 100 MPa, Oy = 50 MPa, Txy = 20…

A: Vector is a physical quantity that has magnitude and direction both. Scalar is a physical quantity…

Q: Determine the reactions at the supports. E is constant.

A: Uniformly distributed load, P=3K/ftLength of the beam , L=10 ft

Q: G. 620mm 1.8m 1.2m

A: As per honor code and answering guidelines I can answer 1st 3 sub parts at a time.So i answered…

Q: In fig. shown. Pind the reaction force on paít(Bc) . OZ07 kpd L = 107 HRir %3D oiL D=75mm Y.d =0.88…

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Thermal Properties of Materials

In mechanical engineering, the thermal property is represented as the physical quantity that is relevant to the application of heat. The thermal properties are evaluated by variations in any specific material due to low heat or high heat. The quantities that influence the thermal property of the materials are mass, density, temperature, and many others.