5. A cutting is to be formed on a section of a proposed road. Calculate the volume of cut required toform the cutting between chainages 1000m and 1090m by using :a. End areas methodb. Prismoidal formula1010172.5CH1000102010601030177.5104010501070185.510801090A(m) 175.6175.5178.5176.5190.5188.5191.5

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Answered: 5. A cutting is to be formed on a…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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QUESTION 11 A cutting is to be formed on a section of a proposed road. Calculate the volume of cut required to form the cutting between chainages 1750m and 1850m by using : a. End areas method b. Prismoidal formula CH Area (m²) 1750 1760 1770 176.3 172.3 175.5 2 1 2 1780 1790 177.9 178.6 6 1 1800 1810 1820 1830 1840 1850 176.1 177.1 176.2 173.1 179.8 182.2 9 1 5 7 6 5
QUESTION 10 A cutting is to be formed on a straight section of a proposed road. The values of eight consecutive cross sectional areas taken at a constant horizontal distance interval of 20m are 325m², 398m², 456m², 580m², 634m², 546m², 447m² and 362m² respectively. Calculate the volume contained between the first and last cross section using : a. End areas method b. Prismoidal formula
1. Complete the differential level notes shown below and perform the customary arithmetic check Level Notes from BM1 to BM4: Station BS HI FS ELEVATION BM1 1.256 127.133 m ТР1 1.116 1.886 ТР2 1.228 1.527 BM2 1.189 2.246 BM3 1.070 2.017 ТРЗ 1.831 2.656 BM4 2.765
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2 A 4 2 56 58 55 58 59 59 60 61 10 60 62 63 64 S 63 64 65 66 M 65 S 5 * S B. Shown to the left is a trapezoidal area which will be excavated and used as borrow pit. It has been laid out by lines at right angles to each other at given distances. The elevation of each grade intersection is as indicated in meters. It is desired to excavate the same to elevation 51 m. Determine the volume of excavation in cubic meters by using: 1) unit volume method 2) parallel section method
14. Shown in the accompanying Figure C are the measured offsets from a traverse line AB to an irregular boundary and the spacing between the offsets. Determine the area bounded by the traverse line, the irregular boundary and the end offsets using a.) Trapezoidal rule b.) Simpson's One-third rule and c.) Compute the difference between Trapezoidal Rule and Simpson's One-Third Rule 5.60 h₁ 6.40 h₂ 7.90 h₂ 6.20 2₂ 7.50 9.50 12.30 hs no h₂ ・6m 6m 6m- Figure C 10.80 ng 2.70
Answer the do (0.0026 L'= L te=) 30 + (-0.0026) s)? (L+= 29.9974 and Explain types of errors in me nents, 1 (L'/L)ME TL = ( 29.9974/30) *500 H TL = 499.9566657 382) Arizontal distance of (500 m) must be lay out with a steel tape, length of the steel tape der standard conditions is (30 m). Field conditions indicate that standard conditions apply except the measured temperature is 50 °C and applied tension 120'N, Determine the correct T= (T-Ts) Lx T= (50-2032) A =T= 0.0lounder P= (P-P₂)L AE P-(120-50)3 The standard temperature 20 °C. 0.02*21*Coefficient of thermal expansion of steel tape = 11.6x10-6 °C 70.005) Standard tension = 50N ∙W C-W² Mass of the tape = 0.05 kg/m 2p² -(0.05 jan Total = 0. olo44 +0.005-0. Total (€) = mans. له میشه راه horizontal distance to be laid out, if Modulus of elasticity (E) = 210*106 N/m2 24 (120) Cross-sectional area of the tape = 0.02 cm² 0.022 022 1.05 +X5 +1·15=3₁3 X5=3-3-22 X5=11 1.1-2.4 -1.3 567 5-1.3= 55.4 fall 1₁4.5-2.28 = -0183
1. Calculate the linear error of closure. 2. Calculate the relative precision.
3. Complete the differential level notes shown below and perform the customary arithmetic check. Station Backsight Stadia Foresight Stadia Elevation BM1 140.00 1.152 1.117 0.935 | 0.718 0.899 0.662 TP1 2.784 1.904 2.420 1.537 2.057 1.172 TP2 1.713 1.450 1.440 1.177 1.166 0.904 TP3 2.591 2.210 2.094 1.714 1.599 1.218 BM2 a. Find the difference in elevation of TP3 and BM1. b. Find the elevation of BM2
1. Complete the differential level notes shown below, perform the customary arithmetic check, provide a detailed sketch on every instrument set-up, and a detailed solution. BACKSIGHT FORESIGHT STA HI ELEV HAIR RDGS MEAN RDG HAIR RDGS MEAN RDG 3.258 BM20 3.015 532.1234 2.833 1.289 3.584 TP: 1.114 3.319 1.002 3.189 5.964 6.647 TP, 5.714 6.556 5.568 6.412 4.845 3.478 TP3 4.602 3.268 4.469 3.001 0.846 2.298 TP. 0.739 2.048 0.698 1.885 2.222 BM21 2.111 2.000
1. Complete the differential level notes shown below, perform the customary arithmetic check, provide a detailed sketch on every instrument set-up, and a detailed solution. BACKSIGHT FORESIGHT STA HI ELEV HAIR RDGS MEAN RDG S HAIR RDGS MEAN RDG S 3.258 BM20 3.015 532.1234 2.833 1.289 3.584 TP, 1.114 3.319 1.002 3.189 5.964 6.647 TP2 5.714 6.556 5.568 6.412 4.845 3.478 TP3 4.602 3.268 4.469 01 0.846 2.298 TP4 0.739 2.048 0.698 1.885 2.222 BM21 2.111 2.000

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5. A cutting is to be formed on a section of a proposed road. Calculate the volume of cut required to form the cutting between chainages 1000m and 1090m by using : € ct1 a. End areas method b. Prismoidal formula