5. Consider the following reaction at equilibríum. What effect will each of the following changes have on the amount of HCl present at equilibrium? (Increase, decrease, or remain the same) 2C12 (g) + 5 H;0(g) = 4HC1 (g) + 6 0, (g) Endothermic reaction a. Decrease the temperature b. Decrease the volume of the container c. Remove H2O (g) d. Add a Catalyst

Chemistry: An Atoms First Approach
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Chapter12: Chemical Equilibrium
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5. Consider the following reaction at equilibrium. What effect will each of the following changes
have on the amount of HCl present at equilibrium? (Increase, decrease, or remain the same)
2Cl; (g) + 5 H2O(g) = 4HCI (g) + 6 O, (g) Endothermic reaction
a. Decrease the temperature
b. Decrease the volume of the container
c. Remove H2O (g)
d. Add a Catalyst
Transcribed Image Text:5. Consider the following reaction at equilibrium. What effect will each of the following changes have on the amount of HCl present at equilibrium? (Increase, decrease, or remain the same) 2Cl; (g) + 5 H2O(g) = 4HCI (g) + 6 O, (g) Endothermic reaction a. Decrease the temperature b. Decrease the volume of the container c. Remove H2O (g) d. Add a Catalyst
Expert Solution
Step 1

The effect of given changes on the amount of HCl at equilibrium in the given reaction is to be determined.

Endothermic reaction proceeds with gain of heat energy.

Catalyst increase the rate of forward and reverse reaction equally.

According to Le Chatelier’s Principle,

  • Increasing the partial pressure or concentration of a reactant shifts the equilibrium to product side (i.e. forward reaction).
  • Increasing the partial pressure or concentration of product shifts the equilibrium to reactant side (i.e. reverse reaction).
  • Decreasing the partial pressure or concentration of a reactant shifts the equilibrium toward the reactant side (i.e. reverse reaction).
  • Decreasing the partial pressure or concentration of product shifts the equilibrium to product side (i.e. forward reaction.
  • Increasing the total pressure of reaction shifts the equilibrium toward the side of the reaction equation with fewer moles of gases.
  • Decreasing the total pressure of reaction shifts the equilibrium toward the side of the reaction equation with more moles of gases.
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