5. Our sun orbits around the center of our galaxy (the Milky Way) once every 2.5 x 108 years. The radius of the sun's orbit about the center of the galaxy is approximately 3.15 x 102⁰ m. The sun has made only about 20 revolutions since the Earth was formed over 3 billion years ago! The centripetal force keeping our sun in orbit is supplied by the force of gravity. Calculate the mass of the galaxy. Show all work. You are here!

5. Our sun orbits around the center of our galaxy (the Milky Way) once every 2.5 x 108 years. The radius of the sun's orbit about the center of the galaxy is approximately 3.15 x 102⁰ m. The sun has made only about 20 revolutions since the Earth was formed over 3 billion years ago! The centripetal force keeping our sun in orbit is supplied by the force of gravity. Calculate the mass of the galaxy. Show all work. You are here!

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter7: Gravity

Section: Chapter Questions

Problem 15PQ: When Sedna was discovered in 2003, it was the most distant object known to orbit the Sun. Currently,...

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6. The sun is orbiting the center of the Milky Way galaxy in an approximately circular orbit with radius 26,000 light years in 230 million years. What is the linear speed of a person on the earth in miles per second because of this motion? 1 light year = 6,000,000,000 miles. 1 year = 365.25 days, 1 day =86,400 seconds.
1.If gravitational exist in all pairs in the universe, then let us compare for it's value between two rock founders of equal masses (72.0kg) that are 5.00m apart. 2. Masses of the earth and moon are 5.97x10^24 kg and 7.36x10^22 kg, respectively, while the average earth -moon distance is 3.84x10^8m. What gravitational force exists between the two?
1. Most galaxies, including our own Milky Way, have supermassive black holes at their centers. Recently, astronomers were able to track one star, named S2, as it orbited the black hole at the center of our galaxy. The star's actual orbit is elliptical, but we'll model it as a circular orbit. S2 has a period of 15 years and an orbit radius of 1000 au, where 1 au = 1 astronomical unit is the distance of the earth from the sun. a. What is the speed of S2? Give your answer as a fraction of c, where c is the speed of light, c=3.0×10^8m/s. b. What is the mass of the black hole? Give your answer as a multiple of Ms, where Ms is the solar mass, Ms=2.0×1030kg 2. A projectile is shot straight up from the earth's surface at a speed of 1.10×104 km/hr. How high does it go?
32. At a given point above the surface of the Earth, the gravitational acceleration is equal to 5.4 m/s². Take the Earth mass M = 5.97x1024 kg and radius R = 6378 km. The altitude of this point, above the surface of the Earth, in km, is closest to: 33. What does the scale read? (Hint: t = rxF) a. 6900 b. 2800 C. 4200 d. 5700 e. 2200 a. b. C. d. a. b. C. d. e. C. 34. A solid cylinder of 5 cm radius is positioned on a frictionless plane inclined at 30 degrees above horizontal. A force F is exerted by a string wrapped around the spool. When F has a certain critical value the center of mass of spool does not move. When this is the case, what is the angular acceleration of the spool? (Hint: t = la) 0001 1910 a. b. e. 500 N 1000 N 2000 N 4000 N 392 rad/s² 340 rad/s² 260 rad/s² 196 rad/s² 98 rad/s² Scale 30" Massless rod 1000 N 4.05 138 35. Two buckets spin around in a horizontal circle on frictionless bearings. Suddenly, it starts to rain. As result, The buckets speed up because the…
Direction: Complete the table below. Calculate the problem using the Laws of Planetary Motion based on the given basic planetary data below. F Earth Mars Saturn Uranus Neptune Jupiter 1. 3. Mean Distance(r) Period of 1.496 x 108 44.97x108 2.28 x 108 14.27x108 2. 4. Revolution (T) 365.2 days 1.88 yrs. 11.86 yrs. 84 yrs. Using the Earth as reference, determine the mean distance(r) or the Period of revolution (T) of each planet. Here is the formula in the Law of Period. (T₁)² (r₁)² (T₂)² (r₂)² = 1. Find the Mean distance of Jupiter. 2. Find the Period of Saturn 3. Find the mean distance of Uranus. 4. Find the Period of Neptune.
1)If the Moon were twice the distance from Earth than it currently is, the amount of time it would take to go around Earth would be roughly (the current orbital period of the Moon is four weeks) Group of answer choices A.eight weeks. B.11 weeks. C.six weeks. D.88 weeks. 2)A satellite is in orbit around a planet. The orbital radius is 46 km and the gravitational acceleration at that height is 7.09 ms-2 . What is the satellite's orbital speed in m/s? (with step)
2. The satellites in the global positioning system, or GPS, travel at 1.05 x 10 km/h. Find the orbital radius of these satellites. 3. Find the speed of a satellite that orbits the earth at an altitude equal to one earth radius. 4. How would your answer to (Question 3) change if the radius were larger? Explain your reasoning.
5. Find the acceleration of our galaxy, the Milky Way, due to the nearest comparably sized galaxy, the Andromeda galaxy (see figure below). The approximate mass of each galaxy is 800 billion solar masses (a solar mass is the mass of our Sun), and they are separated by 2.5 million light-years. (Note that the mass of Andromeda is not so well known but is believed to be slightly larger than our galaxy.) Each galaxy has a diameter of roughly 100,000 light-years (1 light-year = 9.5 × 1015 m) . *The mass of the Sun is 2.0 × 1030 kg and a light-year is the distance light travels in one year, 9.5 × 1015 m . Figure 135 Galaxies interact gravitationally over immense distances. The Andromeda galaxy is the nearest spiral galaxy to the Milky Way, and they will eventually collide. (credit Boris Seromar)
49. There are three celestial bodies discovered by astronomers beyond Planet N. The following are their findings: i. All three celestial bodies are spherical. ii. All celestial bodies are orbiting around the sun. iii.The first celestial body (Celestial body Q) is bigger than Mercury. iv. The second celestial body (Celestial body W) is the dominant body around its orbit. v.The third celestial body (Celestial body K) has very small mass. Which of these celestial bodies CANNOT be considered a planet? * A. Celestial body Q B. Celestial body W C. Celestial body K D. Celestial body K and W
Two planets orbit a star. You can ignore the gravitational interactions between the planets. Planet 1 has orbital radius r₁, and planet 2 has r₂ = 4r₁ Planet 1 orbits with period T₁ Planet 2 orbits with period A. T₂ = -1/T₁ B. T₂=2T₁ C. T₂ = 4T₁ D. T₂=8T₁
Neptune orbits the Sun with an orbital radius of 4.495 x 10^12 m. If the earth to sun distance 1A.U. = 1.5 x 10^11 m, a) Determine how many A.U.'s is Neptune's orbital radius (Round to the nearest tenth). b) Given the Sun's mass is 1.99 x10^30 kg, use Newton's modified version of Kepler's formula T^2 = (4pi^2/Gm(star)) x d^3 to find the period in seconds using scientific notation. (Round to the nearest thousandth). C) Convert the period in part b) to years (Round to the nearest tenth)
35. Ellipsoid Earth. to its rotation, producing an apparent "centrifugal force" pulling the equator outwards. You, at the north pole, and your friend, at latitude 0, decide to drill through the center of the Earth all the way to the other side. Ignoring the different layers of the Earth, and given that the Earth has a radius R along the poles, rotates along the equator at a speed v, has a constant density o everywhere, the difference between the time it takes to fall to the other side of the Earth through the poles and through latitude 0 is given by: The Earth is actually closer to being an ellipsoid than a sphere due -(e cos! 0 – 5) ) - egR' + v^(e cos/ 0 - f), cgR* At = VazG"o" egR® where a, b, c, d, e, f, a, B, y, e are dimensionless constants and G, g, # are their respective constants. Find Ja|ll + 2|3| +3/5|| + 4|e|". Hint: Don't let that complicated expression taunt you! What can you say about the units of the final expression?