5.00 mL of 0.0200 M Fe(NO3)3 was mixed with 5.00 mL of 0.00200 M KSCN to form the FeSCN²+ complex. The equilibrium molar concentration of the FeSCN²+ complex was determined to be 1.00 X 104 M Moles of Fe³+, initial Moles of SCN, initial Moles of FeSCN²+ a) b) c)
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- A solution is prepared such that the initial concentration of A2+ is 1.50x103 M and the initial concentration of X is 4.60x10-3 M. A2+ and X are allowed to react as shown below to establish equilibrium with the complex AX2+. In a colorimetry experiment, the equilibrium concentration of the complex AX2+ is determined to be 8.9x10-4 M. A2* (aq) + X (aq) =Ax2+ (aq) %3D Complete the ICE table below by selecting the correct value or expression to place in the ICE table from the drop-down menu. A2+ (aq) X (ад) АХ2+ (aq) Initial concentration Change in concentration Equilibrium concentration expression Equilibrium concentration valueA solution is prepared such that the initial concentration of A2+ is 1.50×10-3 M and the initial concentration of X is 4.60×10-3 M. A2+ and X are allowed to react as shown below to establish equilibrium with the complex AX2+. In a colorimetry experiment, the equilibrium concentration of the complex AX2+ is determined to be 8.9×10-4 M. A2+ (aq) + X (aq) AX2+ (aq) Use your correct answers from #7 to answer this question. What is Kf, the formation constant, for this complex?A solution is prepared such that the initial concentration of A2+ is 1.50×10-3 M and the initial concentration of X is 4.60×10-3 M. A2+ and X are allowed to react as shown below to establish equilibrium with the complex AX2+. In a colorimetry experiment, the equilibrium concentration of the complex AX2+ is determined to be 8.9×10-4 M. A2+ (aq) + X (aq) AX2+ (aq) What is Kf, the formation constant, for this complex?
- If 4.00 g of CuSO4 are dissolved in 8.5 × 102 mL of 0.25 M NH3 solution, what are the concentrations of Cu2+, Cu(NH3)42+, and NH3 at equilibrium? The formation constant for Cu(NH3)42+ is 5.0 × 10^13. Cu2+=..............× 10............M (scientific notation. Cu(NH3)42+=......................M NH3=.........................MIn the determination of chloride by the Mob method, what will be the equiliblium concentration of silver ions in mgil, on the basis of the solubility product principle, when the chloride concentation has been reduced to 0.2 ma? (b) If the concentration of chromate indicator used is 5X M, how much excess silver ion in mgiL must be present before the formation of a red precipitate will begi(a) In the defermination of chloride by the Mohr method, what will be the equilibrium concentration of silver ions in meL., an the basis of the solubility. pcoduct principle, when the chloride concencration has beea reduced to 0.2m ? (b) If the concentration of chromate indicator ased is 5 × 10³ M, bow much excess silver ion in mel, must be present before the formatice of a red precipitate will begin?. 29) The following concentrations are found in mixtures of ions in equilibrium with slightly soluble solids. From the concentrations given, calculate Ksp for each of the slightly soluble solids indicated: (a) TlCl: [Tl+] = 1.21 ×× 10–2 M, [Cl–] = 1.2 ×× 10–2 M (b) Ce(IO3)4: [Ce4+] = 1.8 ×× 10–4 M, [IO3−][IO3−] = 2.6 ×× 10–13 M (c) Gd2(SO4)3: [Gd3+] = 0.132 M, [SO42−][SO42−] = 0.198 M (d) Ag2SO4: [Ag+] = 2.40 ×× 10–2 M, [SO42−][SO42−] = 2.05 ×× 10–2 M (e) BaSO4: [Ba2+] = 0.500 M, [SO42−][SO42−] = 4.6 ×× 10−8 M
- 21). The solubility product for silver phosphate is Ksp = 1.8 x 10–18. What is the molar solubility of Ag3PO4? (a) Show the reaction of dissociation of Ag3PO4. (b) Show the Ksp expression for Ag3PO4. (c) Calculate the molar solubility s for this compound.The value of Ksp for Cd(OH)2 is 2.5 x 10-14. (a) Whatis the molar solubility of Cd1OH22? (b) The solubilityof Cd(OH)2can be increased through formation of thecomplex ion CdBr42 - (Kf = 5 x 103). If solid Cd(OH)2 isadded to a NaBr solution, what is the initial concentrationof NaBr needed to increase the molar solubility of Cd(OH)2to 1.0 x 10-3 mol/L?Im trying to find the equilibrium concentration of Fe3+ or [Fe3+]eq in a solution of 9.00mL 0.0020M Fe(NO3)3 and 1.00 mL 0.0020M KSCN (both dissociate completely). The equation looks like this: Fe3+(aq)+SCN-(aq)<----> FeSCN2+(aq) The [FeSCN2+]eq is 3.5*10-5
- What is the molar solubility of nickel(II) sulfide in:a) Pure waterb) 1.79x10-3 M nickel(II) nitratec) 3M sodium sulfide, Na2Sd) 0.040 M KCN?For NiS, Ksp = 3.0 x 10–19; for Ni(CN)42–, Kf = 1.0 x 1031.The following concentrations are found in mixtures of ions in equilibrium with slightly soluble solids. From the concentrations given, calculate Ksp for each of the slightly soluble solids indicated:(a) TlCl: [Tl+] = 1.21 × 10–2 M, [Cl–] = 1.2 × 10–2 M(b) Ce(IO3)4: [Ce4+] = 1.8 × 10–4 M, [IO3−] = 2.6 × 10–13 M(c) Gd2(SO4)3: [Gd3+] = 0.132 M, [SO42−] = 0.198 M(d) Ag2SO4: [Ag+] = 2.40 × 10–2 M, [SO42−] = 2.05 × 10–2 M(e) BaSO4: [Ba2+] = 0.500 M, [SO42−] = 2.16 × 10–10 MWhat are the molar solubilities of Cu(OH)2 [Ksp = 2.2e-20] and Pb(OH)2 [Ksp = 1.2e-15]?