5.1.15 WP In the vortex tube shown in Fig. P5.1.15, air enters at 202 kPa absolute and 300 K. Hot air leaves at 150 kPa absolute and 350 K, whereas cold air leaves at 101 kPa absolute and 250 K. The hot air mass flowrate, mµ, equals the cold air mass flowrate, mc. Find the ratio of the hot air exit area to cold air exit area for equal exit velocities. TH = 350 K PH = 150 kPa Tc = 250 K Pc = 101 kPa T = 300 K p = 202 kPa FIGURE P5.1.15

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
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Q2:
5.1.15 WP In the vortex tube shown in Fig. P5.1.15, air enters at
202 kPa absolute and 300 K. Hot air leaves at 150 kPa absolute and
350 K, whereas cold air leaves at 101 kPa absolute and 250 K. The hot
air mass flowrate, mµ, equals the cold air mass flowrate, mc. Find the
ratio of the hot air exit area to cold air exit area for equal exit velocities.
Tc = 250 K
Pc = 101 kPa
%3D
Ти 3 350 K
PH = 150 kPa
T = 300 K
%3D
p = 202 kPa
FIGURE P5.1.15
Transcribed Image Text:Q2: 5.1.15 WP In the vortex tube shown in Fig. P5.1.15, air enters at 202 kPa absolute and 300 K. Hot air leaves at 150 kPa absolute and 350 K, whereas cold air leaves at 101 kPa absolute and 250 K. The hot air mass flowrate, mµ, equals the cold air mass flowrate, mc. Find the ratio of the hot air exit area to cold air exit area for equal exit velocities. Tc = 250 K Pc = 101 kPa %3D Ти 3 350 K PH = 150 kPa T = 300 K %3D p = 202 kPa FIGURE P5.1.15
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